4058210

k nhé

2014.2015 - 1/2014.2015=4058210

Ta có : \(A\text{=}\dfrac{2013.2014-1}{2013.2014}\text{=}\dfrac{2013.2014}{2013.2014}-\dfrac{1}{2013.2014}\text{=}1-\dfrac{1}{2013.2014}\)

\(B\text{=}\dfrac{2014.2015-1}{2014.2015}\text{=}\dfrac{2014.2015}{2014.2015}-\dfrac{1}{2014.2015}\text{=}1-\dfrac{1}{2014.2015}\)

\(Ta\) có : \(\dfrac{1}{2013.2014}>\dfrac{1}{2014.2015}\)

\(\Rightarrow A< B\)

\(A=1-\dfrac{1}{2013.2014}\)

\(B=1-\dfrac{1}{2014.2015}\)

Ta có: \(2014.2015>2013.2014\)

\(\Rightarrow A>B\)

Vì \(2014.2015=2014.2015\)nên \(2014.2015-1< 2014.2015\)1 đơn vi

Vì \(2015.2016=2015.2016\)nên \(2015.2016-1< 2015.2016\)1 đơn vị

Ta có :

\(1-M=1-\frac{2014.2015-1}{2014.2015}=\frac{1}{2014.2015}\)

\(1-N=1-\frac{2015.2016-1}{2015.2016}=\frac{1}{2015.2016}\)

Vì \(2015=2015\)nên \(2014.2015< 2015.2016\)

Vì \(\frac{1}{2014.2015}>\frac{1}{2015.2016}\)( do \(2014.2015< 2015.2016\))

Nên \(N>M\)

Vậy \(N>M\)

Câu hỏi của Nguyễn Tuấn Minh - Toán lớp 6 - Học toán với OnlineMath

Đặt S = 1.2 + 2.3 + 3.4 + ... + 2013.2014 
3S = 1.2.3 + 2.3.3 + 3.4.3 + ... + 2013.2014.3 
Mà : 
1.2.3 = 1.2.3 
2.3.3 = 2.3.4 - 2.3.1 
3.4.3 = 3.4.5 - 3.4.2 
................................... 
................................... 
2012.2013.3 = 2012.2013.2014 - 2012.2013.2011 
2013.2014.3 = 2013.2014.2015 - 2013.2014.2012 
Cộng tất cả, vế theo vế ---> 3S = 2013.2014.2015 
---> S = 2013.2014.2015 / 3 = 2723058910

\(A=1-\frac{1}{2013.2014}\) ; \(B=1-\frac{1}{2014.2015}\)

Vì \(\frac{1}{2013.2014}>\frac{1}{2014.2015}\) nên A < B

\(\frac{2013\cdot2014-1}{2013\cdot2014}=\frac{2013\cdot2013}{2013\cdot2014}=\frac{2013}{2014}\)

\(\frac{2014\cdot2015-1}{2014\cdot2015}=\frac{2014\cdot2014}{2014\cdot2015}=\frac{2014}{2015}\)

Vậy \(\frac{2014}{2015}>\frac{2013}{2014}\)

cam on bn nha,mk cx dg can gap

thanks bn nf>>>

2014.2015-1007.30=2014.2015-2014.15=2014.(2015-15)=2014.2000=4028000

A=1.2+2.3+....+2014.2015

=>3A=1.2.3+2.3.3+3.4.3+...+2015.2014.3

=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+2014.2015.(2016-2013)

=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+.....+2014.2015.2016-2013.2014.2015

=(1.2.3-1.2.3)+(2.3.4-2.3.4)+(3.4.5-3.4.5)+....+(2013.2014.2015-2013.2014.2015)+0.1.2+2013.2014.2015

=0+2013.2014.2015

=>A=\(\frac{2013.2014.2015}{3}\)

A=1.2+2.3+3.4+4.5+...+2014.2015

=>3A=1.2.3+2.3.3+3.4.3+4.5.3+...+2014.2015.3

=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+4.5.(6-3)+...+2014.2015.(2016-2013)

=1.2.3-0.1.2+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+2014.2015.2016-2013.2014.2015

=(1.2.3-1.2.3)+(2.3.4-2.3.4)+(3.4.5-3.4.5)+(4.5.6-4.5.6)+...+(2013.2014.2015-2013.2014.2015)+0.1.2+2014.2015.2016

=0+2014.2015.2016

=>A=\(\frac{2014.2015.2016}{3}\)