a) (2x-1)³ = 27
(2x-1)³ = 9³
2x-1 = 9
2x = 9+1
2x = 10
x = 10:5
x = 2
Vậy x = 2

b) (2x-1)⁴ = 81
(2x-1)⁴ = (\(\pm\)3⁴)
2x-1 = \(\pm\)3
Trường hợp 1:
2x-1 = 3
2x = 3+1
2x = 4
x = 4:2
x = 2
Trường hợp 2:
2x-1 = -3
2x = -3+1
2x = -2
x = -2:2
x = -1
Vậy x \(\in[_{ }2;-1]\)
Vì không tìm thấy ngoặc nhọn nên mình dùng tạm ngoặc vuông nhé

À phần b) bạn sửa dòng (2x-1)⁴ = (\(\pm\)3⁴) thành (2x-1)⁴ = (\(\pm\)3)⁴ nhé
Mình vừa viết nhầm

1/ ( x-3) ²=16

\(\Rightarrow\left[{}\begin{matrix}x-3=4\\x-3=-4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=7\\x=-1\end{matrix}\right.\)

2/ (3x-1)³=8

\(\Rightarrow3x-1=2\\ \Rightarrow3x=3\\ \Rightarrow x=1\)

3/ (x-11)³=-27

\(\Rightarrow x-11=-3\\ \Rightarrow x=8\)

phần 4 mình ko rõ đề

4) \(x^3-3x^2+3x-1=-64\)

\(\Rightarrow x^3-3x^2+3x+63=0\\ \Rightarrow\left(x^3+3x^2\right)-\left(6x^2+18x\right)+\left(21x+63\right)=0\\ \Rightarrow x^2\left(x+3\right)+6x\left(x+3\right)+21\left(x+3\right)=0\\ \Rightarrow\left(x+3\right)\left(x^2+6x+21\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+3=0\\x^2+6x+21=0\end{matrix}\right.\)

\(x+3=0\\ \Rightarrow x=-3\)

\(x^2+6x+21=0\\ \Rightarrow\left(x^2+6x+9\right)+12=0\\ \Rightarrow\left(x+3\right)^2+12=0\)

Vì \(\left(x+3\right)^2\ge0;12>0\Rightarrow\left(x+3\right)^2+12>0\Rightarrow x^2+6x+21vônghiệm\)

Vậy \(x=-3\)

a, (2x-1)³=8

2x-1=2

2x=2+1

2x=3

x=1,5

a, \(\left(2x-1\right)^3=8\)

\(\Leftrightarrow\left(2x-1\right)^3=2^3\)

\(\Leftrightarrow2x-1=2\Leftrightarrow2x=3\Leftrightarrow x=\frac{3}{2}\)

b, \(\left(x-1\right)^x+2=\left(x-1\right)^x+4\)

\(\Leftrightarrow\left(x-1\right)^x+2-\left(x-1\right)^x-4=0\)

\(\Leftrightarrow-2\ne0\)=> vô nghiệm 

c, \(3^x-1+5.3^{3x}-1=162\)

Đề sai.

th1: \(\left(\frac{y}{3}-5\right)^{2008}-\left(\frac{y}{3}-5\right)^{2000}=0\)

\(\left(\frac{y}{3}-5\right)^{2000}.\left[\left(\frac{y}{3}-5\right)^8-1\right]=0\)

\(=>\orbr{\begin{cases}\left(\frac{y}{3}-5\right)^{2000}=0\\\left(\frac{y}{3}-5\right)^{2008}-1=0\end{cases}}\)

\(=>\orbr{\begin{cases}\frac{y}{3}=5=>y=15\\\frac{y}{3}=6=>y=18,\frac{y}{3}=4=>y=12\end{cases}}\)

Vậy ...

P/S: cái đoạn\(\left(\frac{y}{3}-5\right)^{2008}-1=0\)vì số mũ chẵn nên y=18 hay bằng 12 nha!

1) 5^x+5^x+2=650

   5^x.1+5^x.5²=650

   5^x(1+5²)=650

   5^x(1+25)=650

   5^x.26=650

   5^x=650:26=25=5²

=> x=2

2) 3^x-1+5.3^x-1=162

    3^x-1.1+5.3^x-1=162

    3^x-1(1+5)=162

    3^x-1.6=162

    3^x-1=162:6=27=3³

=> x-1=3

     x=3+1=4

3) 2^3x+2=4^x+5

    2^3x.2²=4^x.4⁵

    2^3x+2=(2.2)^x.(2.2)⁵=2^x.2^x.2⁵.2⁵=2^2x.2⁵⁺⁵=2^2x.2¹⁰=2^2x+10

=> 3x+2=2x+10

     3x+2-2x=10

     3x-2x=10-2=8

     x=8

Tick nha

CHTT nha bạn !