H = (9/30303/80808+7/303030/484848)+4,03

   = ( \(\frac{75}{8}+\frac{61}{8}\)) + \(\frac{403}{100}\)

   = \(\frac{136}{8}\)+ \(\frac{403}{100}\)

   =  17 + \(\frac{403}{100}\)

   =  \(\frac{2103}{100}\)

Vậy : H = \(\frac{2103}{100}\)

#Chúc bạn học tốt !

\(F=\left(9,75.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}.21\frac{3}{7}+\frac{39}{4}.18\frac{4}{7}\right).\frac{15}{78}=\left(\frac{39}{4}\left(21\frac{3}{7}+18\frac{4}{7}\right)\right).\frac{15}{78}=\left(\frac{39}{4}.40\right).\frac{15}{78}=390.\frac{15}{78}=75\)\(H=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03=\left(9\frac{3}{8}+7\frac{30}{48}\right)+4,03=17+4,03=21,03\)

\(A=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4,03\)

\(A=\left(9,375+7,625\right)+4,03\)

\(A=17+4,03\)

\(A=21,03\)

\(H=\left(9\frac{30303}{80808}+7\frac{303030}{484848}\right)+4.03\)

\(H=\left(\frac{75}{8}+\frac{61}{8}\right)+\frac{403}{100}\)

\(H=17+\frac{403}{100}\)

\(H=\frac{2103}{100}\)

\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)

\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)

\(I=10101.\left(\frac{5}{111111}-\frac{4}{111111}+\frac{5}{222222}\right)\)

\(I=10101.\left(\frac{1}{111111}+\frac{5}{222222}\right)\)

\(I=10101.\frac{7}{222222}\)

\(I=\frac{7}{22}\)

I=10101(5/111111+5/222222+4/3.7.11.13.37)

I=10101(5/111111+5/222222+4/111111)

I=10101(10/222222+5/222222+8/222222)

I=10101.23/222222

I=232323/222222

\(I=\frac{7}{22}\)

\(H=\frac{2103}{100}=21,03\)

Nguyễn Triệu Yến Nhi chép sai đề rồi!!!

\(C=9\frac{30303}{80808}+4,03+7\frac{303030}{484848}\)

     \(=9\frac{3}{8}+4\frac{3}{100}+7\frac{5}{8}\)

      \(=\left(9+7\right)+\left(\frac{3}{8}+\frac{5}{8}\right)+4\frac{3}{100}\)

      \(=16+1+4\frac{3}{100}\)

       \(=21\frac{3}{100}\)