can(15-x) +can(3-x)=6
can(15-x) +can(3-x)=6
\(\sqrt{15-x}+\sqrt{3-x}=6\left(ĐK:x\le3\right)\)
\(\Leftrightarrow\left(\sqrt{15-x}\right)^2=\left(6-\sqrt{3-x}\right)^2\)
\(\Leftrightarrow15-x=36+3-x-12\sqrt{3-x}\)
\(\Leftrightarrow\sqrt{3-x}=2\Leftrightarrow x=-1\)(TM)
Vậy nghiệm của phương trình là : x = -1
cả 3 can 15 x 3 = 45(l)
can thứ 3 45-(12+6) = 17 (l)
đáp án là 17 (l)
giải phương trình
(căn( x+5)-can (x+3))(1-can(x2+8x+15))=2
10*can(8+x^3)=3(x^2-x+6)
10\(\sqrt{8+x^3}=3\left(x^2-x+6\right)\) dk tu xd
\(10\sqrt{\left(x+2\right)\left(x^2-2x+4\right)}=3\left(x+2\right)\left(x+3\right)\)
\(\Leftrightarrow\sqrt{x+2}\left(10\sqrt{x^2-2x+4}-3\left(x+3\right)\sqrt{x+2}\right)=0\)
đến đây tự giải quyết nhé
Tim tat ca cac so thuc bac x thoa man
a)(2x-1)^2+(x-1)^3=3x+6
b) x+1= can bac x+3 ( ko viet dc can bac hi hi)
c)2x^2+1=5 . can bac x^2+1-4
Tim tat ca cac so thuc bac x thoa man
a)(2x-1)^2+(x-1)^3=3x+6
b) x+1= can bac x+3 ( ko viet dc can bac hi hi)
c)2x^2+1=5 . can bac x^2+1-4
Tim tat ca cac so thuc bac x thoa man
a)(2x-1)^2+(x-1)^3=3x+6
b) x+1= can bac x+3 ( ko viet dc can bac hi hi)
c)2x^2+1=5 . can bac x^2+1-4
giai pt:
1)can(2(x+1)(x+3))+can((x+1)(x-1))=2(x+1)
2)can(x)-can(x+1)-can(x+4)+can(x+9)=0
Tim so nguyen x, biet :
a) (1/2 - 1/3) . 6x + 6x + 2 = 615 + 618.
b) (1/2 - 1/6) . 3x + 4 - 4 . 3x = 316 - 4 . 313.
Minh dang can gap. Ai biet thi chi giup minh voi nhe! Cam on moi nguoi .