a = 2011.2013

a = 2011.(2012+1)

a = 2011.2012 + 2011

b = 2012.2012

b = (2011+1).2012

b = 2011.2012 + 2012

Vì 2011 < 2012

=> 2011.2012 + 2011 < 2011.2012 + 2012

=> a < b

a lớn hơn b nhé ae

a lớn hơn b

\(10A=\dfrac{10^{2021}+10}{10^{2021}+1}=\dfrac{\left(10^{2021}+1\right)+9}{10^{2021}+1}=\dfrac{10^{2021}+1}{10^{2021}+1}+\dfrac{9}{10^{2021}+1}=1+\dfrac{9}{10^{2021}+1}\)

\(10B=\dfrac{10^{2022}+10}{10^{2022}+1}=\dfrac{\left(10^{2022}+1\right)+9}{10^{2022}+1}=\dfrac{10^{2022}+1}{10^{2022}+1}+\dfrac{9}{10^{2022}+1}=1+\dfrac{9}{10^{2022}+1}\)

Vì \(10^{2022}>10^{2021}=>10^{2021}+1< 10^{2022}+1\)

\(=>\dfrac{9}{10^{2021}+1}>\dfrac{9}{10^{2022}+1}\)

\(=>10A>10B\)

\(=>A>B\)

A > B nhé

Bạn trình bày bài giải cho mình nhé

Ta có:

\(A=1999\times1999=1999\times\left(1997+2\right)=1999\times1997+1999\times2\)

\(B=1997\times2001=1997\times\left(1999+2\right)=1999\times1997+1997\times2\)

Vì \(1999\times1997+1999\times2>1999\times1997+1997\times2\)Nên \(A>B\)

A= 10 x 28,96 x 2,869

B = 28,96 x 2,896 x 10

=> A = B

A=8,6x8,9=8,6x(8,8+0,1)=8,6x8,8+8,7

B=8,7x8,8=(8,6+0,1)x8,8=8,6x8,8+8,9

Vì 8,7<8,9

=>A<B

Ta có: A = 32 x 53 - 31 = 31 x 53 + 53 - 31 = 31 x 53 + 22

Do 22 < 32 => 31 x 53 + 22 < 53 x 31 + 32

                 => 52 x 53 - 31 < 53 x 31 + 32         

                  => A < B

\(A=32\times53-31\)

\(\Leftrightarrow A=\left(31+1\right)\times53-31\)

\(\Leftrightarrow A=31\times53+53-31\)

\(\Leftrightarrow A=31\times53+22\)

Vì 22 < 32 nên 31 x 53 + 22 < 53 x 31 + 32 hay A < B

~ Hok tốt ~