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blabla
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Abcd
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Đỗ Thanh Hải
5 tháng 9 2021 lúc 8:45

39 be on time for your interview

40 tall is she

41 What is she like?

42 have you been in this city?

43 is the price of those books

44 How did she greet friends?

45 What did she walk to the station for

Ngọc Ngân
Abcd
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Đỗ Thanh Hải
17 tháng 9 2021 lúc 20:57

2 is going to b

3 am writing

4 has also typed

5 has been planting

6 has written

7 have just heard

8 does the play start

9 have worked

10 have practise

11 go

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Đỗ Thanh Hải
19 tháng 9 2021 lúc 14:09

1 Mary thanked me for looking after her children when she was away

2 The mother warned her son not to play near the dog

3 Tim insisted on taking Laura to the airport

4 Miss Hoa thanked me for inviting her to the dinner

5 He suggested going to the movies

6 The boy denied cheating in the exam

7 chưa có từ gọi ý

Vie-Vie
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Đỗ Thanh Hải
19 tháng 9 2021 lúc 14:27

7 Tracy thanked Mr Smith for helping her

8 Susan refused to come to Jack's birthday party the next Saturday evening

9 She accused Tom of telling a lie

10 She suggested taking part in voluntary club

11 Tom advised Ba to study hard for the coming exam

12 Paul reminded me to buy some bread

13 She asked me why I had turned off the television

14 Peter asked Linda if she had invited those girls to her party the day before

15 Long asked Van if he watched television every evening

16 Kerry told Cheryl she had something to tell him

17 Peter suggested that I ask the teacher for help

18 Ivan promised to play back the money to Gloria

19 Frederic invited Sarah to come to his birthday party

20 He offered me some more beer

21 He suggested going to the cinema that night

22 Jasmine advised me to rest for a few days

Quỳnhh Hương
Nguyễn Lê Phước Thịnh
2 tháng 9 2021 lúc 13:04

a: Ta có: \(P=\left(\dfrac{\sqrt{x}}{\sqrt{x}-2}-\dfrac{x-\sqrt{x}-1}{x-2\sqrt{x}}\right):\left(\dfrac{\sqrt{x}+2}{\sqrt{x}+1}-\dfrac{x-5}{x-\sqrt{x}-2}\right)\)

\(=\dfrac{x-x+\sqrt{x}+1}{\sqrt{x}\left(\sqrt{x}-2\right)}:\dfrac{x-4-x+5}{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{\sqrt{x}+1}{\sqrt{x}\left(\sqrt{x}-2\right)}\cdot\dfrac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)}{1}\)

\(=\dfrac{x+2\sqrt{x}+1}{\sqrt{x}}\)

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Thu Hồng
21 tháng 9 2021 lúc 1:38

undefined

Kentros Itz
Lê Phan Bảo Khanh
22 tháng 12 2021 lúc 15:44

\(=\dfrac{3^5.\left(2^2\right)^3}{2^5.\left(3^2\right)^3}=\dfrac{3^5.2^6}{2^5.3^6}=\dfrac{2}{3}\)

Lê Phan Bảo Khanh
22 tháng 12 2021 lúc 16:01

\(=\dfrac{3}{2}\)