\(ĐKXĐ:\hept{\begin{cases}x\ne0\\x\ne30\\x\ne24\end{cases}}\)

Ta có \(\frac{60}{\frac{120}{x}-4}+\frac{60}{\frac{120}{x}-5}=x\)

\(\Leftrightarrow\frac{60}{\frac{120-4x}{x}}+\frac{60}{\frac{120-5x}{x}}=x\)

\(\Leftrightarrow\frac{60x}{120-4x}+\frac{60x}{120-5x}=x\)

\(\Leftrightarrow\frac{60}{120-4x}+\frac{60}{120-5x}=1\left(Do\text{ }x\ne0\right)\)    

\(\Leftrightarrow\frac{15}{30-x}=1-\frac{12}{24-x}\)

\(\Leftrightarrow\frac{15}{30-x}=\frac{24-x-12}{24-x}\)

\(\Leftrightarrow\frac{15}{30-x}=\frac{12-x}{24-x}\)

\(\Leftrightarrow360-15x=\left(12-x\right)\left(30-x\right)\)

\(\Leftrightarrow360-15x=360-42x+x^2\)

\(\Leftrightarrow x^2-27x=0\)

\(\Leftrightarrow x\left(x-27\right)=0\)

\(\Leftrightarrow x=27\left(Tm\text{ }ĐKXĐ\right)\)

\(\Leftrightarrow\hept{\begin{cases}x-y=20\\\frac{y-x}{xy}=\frac{1}{120}\end{cases}\Leftrightarrow}\hept{\begin{cases}x-y=20\\xy=-2400\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}y=x-20\\x\left(x-20\right)+2400=0\end{cases}}\)

Đến đây dễ rồi nhé

30 theo tui nghĩ là đúng

=>\(\frac{30x\left(x-6\right)}{x\left(x+10\right)\left(x-6\right)}+\frac{30x\left(x+10\right)}{x\left(x+10\right)\left(x-6\right)}=\frac{60\left(x+10\right)\left(x-6\right)}{x\left(x-6\left(x+10\right)\right)}\)

=>30x²-180x+30x²+300x=60x²-360x+600x-3600

=>60x²+120x=60x²+240x-3600

=>-120x=-3600

=>x=30

nhớ k mk........Đúng 100%

pt đã cho có dạng \(\frac{1}{\left(x+1\right)\left(x+4\right)}+\frac{1}{\left(x+4\right)\left(x+7\right)}+\frac{1}{\left(x+7\right)\left(x+10\right)}=\frac{4}{13}\)
\(\Leftrightarrow\frac{1}{x+1}-\frac{1}{x+4}+\frac{1}{x+4}-\frac{1}{x+7}+\frac{1}{x+7}-\frac{1}{x+10}=\frac{4}{13}\)
\(\Leftrightarrow\frac{1}{x+1}-\frac{1}{x+10}=\frac{4}{13}\Leftrightarrow....\)

bạn tuấn mình thấy vậy nè

Gỉa sử cho x=1 ta thấy \(\frac{1}{1\times4}\ne\frac{1}{1}-\frac{1}{4}\)

Bạn bấm máy tính thử xem dấu bằng chỉ áp dụng với 2 số tự nhiên liên tiếp thôi còn cái này cách 3 lận

giải thích giúp mình với

à 

ý là nhân hai về pt cho 3 đúg kk 

mình hiểu rồi nha

cảm ơn nha

\(\Leftrightarrow\sqrt{x^2-\frac{1}{4}+\sqrt{\left(x+\frac{1}{2}\right)^2}}=\frac{1}{2}\left(2x^3+x^2+2x+1\right)\)\(\Leftrightarrow\sqrt{x^2+x+\frac{1}{4}}=\frac{1}{2}\left(2x^3+x^2+2x+1\right)\)\(\Leftrightarrow x+\frac{1}{2}=\frac{1}{2}\left(2x^3+x^2+2x+1\right)\Leftrightarrow2x+1=2x^3+x^2+2x+1\)\(\Leftrightarrow2x^3+x^2=0\Leftrightarrow\orbr{\begin{cases}x=0\\x=-\frac{1}{2}\end{cases}}\)

\(\sqrt{x^2-\frac{1}{4}+\sqrt{x^2+x+\frac{1}{4}}}=\frac{1}{2}\left(2x^3+x^2+2x+1\right)\left(1\right)\)

\(\left(1\right)\Leftrightarrow\sqrt{x^2-\frac{1}{4}+\sqrt{\left(x+\frac{1}{2}\right)^2}}=\frac{1}{2}\left(2x+1\right)\left(x^2+1\right)\)

\(x^2+1\ge1\forall x\Rightarrow2x+1\ge0!2x+1!=2x+1\)

\(\left(1\right)\Leftrightarrow\sqrt{x^2+x+\frac{1}{4}}=\frac{1}{2}\left(2x+1\right)\left(x^2+1\right)\)

\(\left(1\right)\Leftrightarrow x+\frac{1}{2}=\frac{1}{2}\left(2x+1\right)\left(x^2+1\right)\)

\(\left(1\right)\Leftrightarrow2x+1=\left(2x+1\right)\left(x^2+1\right)\Leftrightarrow\left(2x+1\right).\left(1-\left(x^2+1\right)\right)=0\)

\(\hept{\begin{cases}2x+1=0\\-x^2=0\end{cases}\Rightarrow\hept{\begin{cases}x=-\frac{1}{2}\\x=0\end{cases}}}\)

Chúc bạn học tốt !!!

Ta có: \(\frac{x+4}{5}-x+4=\frac{x}{3}-\frac{x-2}{2}\)

<=> \(\frac{6\left(x+4\right)-30x+120}{30}=\frac{10x-15x+30}{30}\)

<=> 6x + 24 - 30x + 120 = -5x + 30

<=> -24x + 5x = 30 - 144

<=> -19x = -114

<=> x = 6

Vậy S = {6}

\(\frac{x+2}{98}+\frac{x+4}{96}=\frac{x+6}{94}+\frac{x+8}{92}\)

\(\Leftrightarrow\left(\frac{x+2}{98}+1\right)+\left(\frac{x+4}{96}+1\right)-2=\left(\frac{x+6}{94}+1\right)+\left(\frac{x+8}{92}+1\right)-2\)

\(\Leftrightarrow\frac{x+100}{98}+\frac{x+100}{96}-\frac{x+100}{94}-\frac{x+100}{92}=0\)

\(\Leftrightarrow\left(x+100\right)\times\left(\frac{1}{98}+\frac{1}{96}-\frac{1}{94}-\frac{1}{92}\right)=0\)

\(\Leftrightarrow x+100=0\left(\frac{1}{98}+\frac{1}{96}-\frac{1}{94}-\frac{1}{92}\ne0\right)\)

\(\Leftrightarrow x=-100\)

Vậy......

Đặt: \(\hept{\begin{cases}\frac{1}{x}=a\\\frac{1}{y}=b\end{cases}}\)thì hệ thành

\(\hept{\begin{cases}a=\frac{3b}{2}\\a+b=\frac{1}{24}\end{cases}}\)

Rồi giải tiếp đi b

cảm ơn bạn

nhung mk vẫn chưa hiểu lắm bạn giải tiếp cho mk dc ko