d,\(=\frac{1}{3^2}\cdot\frac{1}{3}\cdot\left(3^2\right)^2=\frac{3^4}{3^3}=3\)

b,\(=2^2\cdot2^5:\left(2^3\cdot\frac{1}{2^4}\right)=2^7:\frac{1}{2}=2^7\cdot2=2^8\)

ủa , còn câu trả lời của e ạ !!! chắc oline math duyệt !!! 

a) \(9\cdot3^3\cdot\frac{1}{81}\cdot3^2\)

\(=\frac{3^2\cdot3^3\cdot3^2}{3^4}\)

\(=3^3=27\)

b) \(4\cdot2^5:\left(2^3\cdot\frac{1}{16}\right)\)

\(=\frac{2^2\cdot2^2\cdot2^4}{2^3}\)

\(=2^5=32\)

c) \(3^2\cdot2^5\cdot\left(\frac{2}{3}\right)^2\)

\(=\frac{3^2\cdot2^5\cdot2^4}{3^2}\)

\(=2^9=512\)

d) \(\left(\frac{1}{3}\right)^2\cdot\frac{1}{3}\cdot9^2\)

\(=\frac{1^2\cdot1\cdot3^4}{3^2}\)

\(=3^2=9\)

a/

\(9.3^2.\frac{1}{81}.27=\frac{9.3^2.27}{81}=\frac{3^2.3^2.3^3}{3^4}=\frac{3^7}{3^4}=3^3\)

b/

\(4.32:\left(2^3.\frac{1}{16}\right)=4.32:\left(\frac{2^3}{16}\right)=4.32:\left(\frac{2^3}{2^4}\right)=4.32:\frac{1}{2}=4.32.2=4.64=4.4^3=4^4\)

c/

\(3^4.3^5:\frac{1}{27}=3^4.3^5.27=3^4.3^5.3^3=3^{12}\)

d/(ý bạn là (-2)^2 hay -2^2 , mình làm theo cách (-2)^2 nhé!)

\(2^2.4.\frac{32}{\left(-2\right)^2}.2^5=2^2.2^2.\frac{2^5}{2^2}.2^5=2^2.2^2.2^3.2^5=2^{12}\)

giúp minh vớ các bạn

thanks bạn thao minh donna

1, \(\frac{1}{2}-\left(6\frac{5}{9}+x-\frac{117}{8}\right):\left(12\frac{1}{9}\right)=0\)

   \(\left(\frac{6.9+5}{9}+x-\frac{117}{8}\right):\frac{12.9+1}{9}=\frac{1}{2}\)

 ( . là nhân nha) 

    \(\left(\frac{59}{9}-\frac{117}{8}+x\right):\frac{109}{9}=\frac{1}{2}\)

    \(\frac{59}{9}-\frac{117}{8}+x=\frac{1}{2}\cdot\frac{109}{9}\)

    \(\frac{59}{9}-\frac{117}{8}+x=\frac{109}{18}\)

   \(x=\frac{109}{18}-\frac{59}{9}+\frac{117}{8}\)

\(x=\frac{113}{8}\)

( \(\left(y+\frac{1}{3}\right)+\left(y+\frac{2}{9}\right)+\left(y+\frac{1}{27}\right)+\left(y+\frac{1}{81}\right)=\frac{56}{81}\)

   \(y+\frac{1}{3}+y+\frac{2}{9}+y+\frac{1}{27}+y+\frac{1}{81}=\frac{56}{81}\)

\(4y+\frac{1}{3}+\frac{2}{9}+\frac{1}{27}+\frac{1}{81}=\frac{56}{81}\)

\(4y+\frac{49}{81}=\frac{56}{81}\)

\(4y=\frac{7}{81}\)

y      =  7/81:4

y       = 7/324

a: \(=3^2\cdot3^5:3^4=3^{2+5-4}=3^3\)

b: \(=2^3\cdot2^4:\left(\dfrac{8}{16}\right)=\dfrac{2^7}{2}=2^6\)

c: \(=3^7\cdot3^3=3^{10}\)

d: \(=5^3\cdot5^2\cdot\dfrac{1}{5^4}=5^1\)