tim x biet
a ) 9<3 mũ x < 81
b ) 25 <5 mũ x , 81
mong cac ban ban nho dang yeu giup do .
Bai 1: Tim ab ; biet ab = b x 9
Bai 2 : Tim ab, biet :
a) ab x 5 = 2ab b) ab = 4ab / 9.
Bai 3 : Tim ab, biet : a 2 = b x 5
Bai 4 : Tim cac so ab biet :
a) a x3 = bx9 b) a x4 = b x6.
Bai 5 :
a) Tim abc, biet a , b , c khac nhau va : a x bc = 91.
b) Tim a , b , c khac nhau biet aa x bc = 1001
a, Cho F(x) = a x+b . Tim a,b biet f(0) = 3 va F(2) =-1
b, Cho F(x) =a x+ b. Tim a,b biet F(1) = -1 va F(-2) = 8
c, Cho F(x) =a x +b .tim a,b biet F(0) = 1 va F(-2) = -9
a, Tim so tu nhien x, y biet rang 4<9/x<12/y<18
b, Tim so nguyen x, y biet rang x/2 - 2/y = 1/2
Lam cach nao de ra duoc ket qua nhu vay ha ban?
a) tim X biet
X+7/X = 9 ( voi X > 0 )
b) tim 3 gia tri cua X biet
12,3 < X < 12,4
bai 1)tim x biet
a )24-(36+5)=x
b)14-21=(13-x)-(15+8)
bai 2) tim x biet
a)17-x=-25+(-16+9)
b)3x-21=-19-(-2x)
Bài 1: Tìm x, biết
a )24-(36+5)=x b)14-21=(13-x)-(15+8)
24-41=x (13-x)-23=-7
x=-17 13-x=(-7)+23
Vậy x=-17 13-x=16
x=13-16
x=-3 Vậy x=-3
Bài 2:Tìm x, biết
a)17-x=-25+(-16+9) b)3x-21=-19-(-2x)
17-x=-25+(-7) 3x-21=-19+2x
17-x=-32 3x-2x=-19+21
x=17-(-32) x=4
x=49 Vậy x=4
Vậy x=49
Bài 1:
a. 24 - (36+5) = x
=> 24 - 41 = x
=> -17 = x
=> x = -17
b. 14 - 21 = (13 - x) - (15 + 8)
=> -7 = 13 - x - 23
=> -7 - 13 + 23 = -x
=> 3 = -x
=> x = -3
Bài 2:
a. 17 - x = -25 + (-16 + 9)
=> 17 - x = -25 + (-7)
=> 17 - x = -32
=> 17 + 32 = x
=> x = 49
b. 3x - 21 = -19 - (-2x)
=> 3x - 21 = -19 + 2x
=> 3x - 2x = -19 + 21
=> x = 2
Bài1
a)24-(36+5)=x\(\Rightarrow\)x=24-41=-17
b)14-21=(13-x)-(15+8)\(\Rightarrow\)(13-x)-(15+8)=-7\(\Rightarrow\)13-x=-7+23=16\(\Rightarrow\)x=13-16=-3
Bài2
a)17-x=-25+(-16+9)\(\Rightarrow\)17-x=-25+-7\(\Rightarrow\)17-x=-32\(\Rightarrow\)x=17-(-32)=17+32=49
b)3x-21=-19-(-2x)\(\Rightarrow\)3x-(-2x)=-19-21\(\Rightarrow\)3x+2x=-40\(\Rightarrow\)5x=-40\(\Rightarrow\)x=-8
a,Tim x biet:1+5+9+13+17+...+x=507528
tim x biet: |x-9|+x-9=0
| x - 9 | + x - 9 = 0
=> | x - 9 | = x + 9
Điều kiện :
x + 9 \(\ge\)0
Khi đó : | x - 9 | = x + 9
=> x - 9 = x + 9
=> 0x = 9 - 9
=> 0x = 0
=> x \(\in\)Z
Vậy x \(\in\)Z
Chúc em học giỏi!
| x - 9 | + x - 9 = 0
=> | x - 9 | = 9 + x
Với điều kiện : x + 9 > hoặc = 0
Ta có :| x - 9 | = x + 9
=> x - 9 = x + 9
=> 0x = 9 - 9
=> 0x = 0
=> x thuộc Z
tim x y z biet
a) x.(y-2).(x^2-9)=0
bai 1 tim x biet
a) x+a =12
b)a-x=-8
c25-x=a
d)a-x-a=7
bai 2 tim x biet
a) -18-x=30
b)-25+x=-2 +9
c) -45-(x-1)=56
2)
a)-18-x=30\(\Rightarrow\)x=-18-30=-48
b)-25+x=-2+9\(\Rightarrow\)-25+x=7\(\Rightarrow\)x=7-(-25)=7+25=32
c)-45-(x-1)=56\(\Rightarrow\)x-1=-45-56=-101\(\Rightarrow\)x=-101+1=-100
tim x,biet
a,-x.[ x+3 ]=0
b, [ x-2 ]. [ 3x-9 ]=0