\(a,2^{x+2}-2^x=96\)

\(=>2^x.2^2-2^x=96\)

\(=>2^x.\left(4-1\right)=96\)

\(=>2^x.3=96\)

\(=>2^x=96:3=32\)

\(=>2^x=2^5\)

\(=>x=5\)

\(b,720:\left[41.\left(2x-5\right)\right]=2^3.125:5^2\)

\(=>720:\left[41.\left(2x-5\right)\right]=8.125:25\)

\(=>720:\left[41.\left(2x-5\right)\right]=8.5=40\)

\(=>41.\left(2x-5\right)=720:40=18\)

\(=>2x-5=18:41=\frac{18}{41}\)

\(=>2x=\frac{18}{41}+5=\frac{223}{41}\)

\(=>x=\frac{223}{41}:2=\frac{223}{62}\)

\(c,\left(-2x+7\right)^{19}=\left(-2x+7\right)^{19}.\left(x+1\frac{1}{4}\right)^2\)

\(=>\left(-2x+7\right)^{19}:\left(-2x+7\right)^{19}=\left(x+\frac{5}{4}\right)^2\)

\(=>1=\left(x+\frac{5}{4}\right)^2\)

\(=>1^2=\left(x+\frac{5}{4}\right)^2\)

\(=>1=x+\frac{5}{4}\)

\(=>x=1-\frac{5}{4}=-\frac{1}{4}\)

Chúc bạn Hk tốt!!!!

Và giữ đúng lời hứa trên@@!!!!!

Ta có:4/x=x/4

Hay x²/4x=16/4x

Hay x²=16

Hay x²=4²

Hay x=4

Suy ra x=4

Vậy x=4

\(\frac{4}{x}=\frac{x}{4}\)

\(\Rightarrow x=1\)

\(\frac{4}{x}=\frac{x}{4}\Rightarrow4\cdot4=x\cdot x\Rightarrow x^2=16\Rightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)

\(5\left(x+3\right)-2x\left(x+3\right)=0\)

<=> \(\left(5-2x\right)\left(x+3\right)=0\)

<=> \(\hept{\begin{cases}5-2x=0\\x+3=0\end{cases}}\)

<=> \(\hept{\begin{cases}x=\frac{5}{2}\\x=-3\end{cases}}\)

\(4x\left(x-2018\right)-x+2018=0\)

<=> \(4x\left(x-2018\right)-\left(x-2018\right)=0\)

<=> \(\left(4x-1\right)\left(x-2018\right)=0\)

<=> \(\hept{\begin{cases}4x-1=0\\x-2018=0\end{cases}}\)

<=> \(\hept{\begin{cases}x=\frac{1}{4}\\x=2018\end{cases}}\)

\(\left(x+1\right)^2-\left(x+1\right)=0\)

<=> \(\left(x+1\right)\left(x+1-1\right)=0\)

<=> \(\left(x+1\right).x=0\)

<=> \(\hept{\begin{cases}x=0\\x+1=0\end{cases}}\)

<=> \(\hept{\begin{cases}x=0\\x=-1\end{cases}}\)

học tốt

a) \(5\left(x+3\right)-2x\left(3+x\right)=0\)

\(5\left(x+3\right)+2x\left(x+3\right)=0\)

\(\left(x+3\right)\left(5+2x\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+3=0\\5+2x=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-3\\x=\frac{-5}{2}\end{cases}}\)

b) \(4x\left(x-2018\right)-x+2018=0\)

\(4x\left(x-2018\right)-\left(x-2018\right)=0\)

\(\left(x-2018\right)\left(4x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-2018=0\\4x-1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=2018\\x=\frac{1}{4}\end{cases}}\)

c) \(\left(x+1\right)^2-\left(x+1\right)=0\)

\(\left(x+1\right)\left(x+1-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x+1=0\\x+1-1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=-1\\x=0\end{cases}}\)

Cảm ơn 2 bn đã giúp mk nha!!!

3/4+1/4:x=-3

1/4:x=(-3)-3/4

1/4:x=-15/4

x=-15/4.1/4

x=-15/16

đúng nha bn

3/4+3/4 : x= -3 

4/4 :x =-3

1:x =-3

x= -1/3

\(\frac{3}{4}+\frac{1}{4}:x=-3\)

=> \(\frac{1}{4}:x=-3-\frac{3}{4}=\frac{-15}{4}\)

=> \(x=\frac{1}{4}:\left(\frac{-15}{4}\right)=\frac{1}{4}.\left(\frac{-4}{15}\right)=\frac{-1}{15}\)

Vậy \(x=\frac{-1}{15}\)

Ta có: A=2^0+2^1+2^2+2^3+...+2^2010
         =>2A=2+2^2+2^3+2^4+...+2^2011
    =>2A-A=(2+2^2+2^3+...+2^2011)-( 1+2+2^2+2^3+...+2^2010)
    =>A= 2^2011-1

Từ đó ta suy ra A=B (=2^2011-1)
 k nha!

2A=2¹+2²+...+2²⁰¹¹

Suy ra: A=2A-A = (2¹+2²+...+2²⁰¹¹) - (2⁰+2¹+...+2²⁰¹⁰)=2²⁰¹¹-1=B

Vậy: A=B.

hihi mk cảm ơn mk sẽ lấy nick phụ k cho các bạn nhé !

bài 1 mình tính ra là 855

bài 2 thì mình ko bít thông nha bạn?

bài 2 thì ko làm được thông cảm cho mình nha ?

1 k là mình vui rồi hihi

Bài 1 :

563 + {54 + [ 37 . ( -2 )² ] }

= 563 + [54 + ( 37 . 4 ) ]

= 563 + ( 54 + 148 )

= 563 + 202

= 765

Bài 2 :

a) x/4 = y/3 = 12/z = 12/2 = 6

=> x = 6 x 4 = 24

=>     y = 6 x 3 = 18

=>     z = 12 : 6 = 2

b) Mk ko bt làm :))

c) Mk cx ko bt nốt =.=

Hok tốt !!! 

ai tk mk nhiều nhất và nhanh nhất mk sẽ tk cho 

48

6

7 tk nha

2 x 2 x 3 x 4 = 48

1 x 2 x 3 = 6

1 + 6 = 7

\(\Leftrightarrow\sqrt{\left(\sqrt{x}+1\right)^2}=2\Leftrightarrow\sqrt{x}+1=2\Leftrightarrow\sqrt{x}=1\Leftrightarrow x=1\)

\(\Leftrightarrow\sqrt{\left(\sqrt{x}-2\right)^2}=3\Leftrightarrow\sqrt{x}-2=3\Leftrightarrow\sqrt{x}=5\Leftrightarrow x=25\) 

\(\sqrt{x-2\sqrt{x-1}}=\sqrt{x-1-2\sqrt{x-1}+1}=\sqrt{\left(\sqrt{x-1}-1\right)^2}=\sqrt{x-1}-1=2\) 

\(\Leftrightarrow x=10\)

 ĐKXĐ tự tìm\(b,\sqrt{x-4\sqrt{x}+4}=3\)

\(\Leftrightarrow\sqrt{\left(\sqrt{x}-2\right)^2}=3\)

\(\Leftrightarrow\sqrt{x}-2=3\)

\(\Leftrightarrow\sqrt{x}=5\)

\(\Rightarrow x=5^2=25\)