- Mình có thể giúp bài 1 :)

 5^x +  5^ ( x + 2 ) = 650

5^x +  5^x . 5² = 650

 5^x .( 1 + 25 ) = 650

 5^x . 26 = 650 

5^x = 650 : 26

 5^x = 25

 5^x = 5² 

=> x = 2 

Vậy x = 2 

The Reflection Of Light~ Ủa đề  là 5^x-5^x+2= 650 sao ông lại đổi thành 5^x-5^(x+2) zậy

a)5^x+5^x+2=650

2*5^x+2=650

2(5^x+1)=650

5^x+1=650/2

5^x+1=325

5^x=325-1

5^x=324

=>x \(\in\phi\)

b)3^x-1+5*3^x-1=162

3^x-1(1+5)=162

3^x-1=162/6

3^x-1=27=3³

=>x-1=3

x=3+1

x=4

c)(2x-1)⁶=(1-2x)⁸

(2x-1)⁶=(-2x-1)⁸=(2x-1)⁸=(2x-1)⁶*(2x-1)²

=>(2x-1)²=1

2x-1=1

2x=1+1

2x=2

x=2/2

x=1

*)2x-1=0

2x=0+1

2x=1

x=1/2

102,5m2

a. 3.(5+2+3)=30

b. 9.(2+5+3)=90

c. 8.(5-2+6)=72

d. (1000-298).(140:14-10)=702.0=0

a.30

b.90

c.72

d.0

a. 3x5 + 2x3 +3x3 

  = 3x(5+2+3)

  =3x10=30

b.2x9 + 5x9 +27

= 2x9 +5x9 +3x9

=9x(2+5+3)

=9x10=90

c.5x8 -16 + 8x6

=5x8 -2x8 + 8x6

=8x(5-2+6)=8x10=80

d.(650-298+350)x(70:14x2 - 10)

=(650-296=350)x(5x2 - 10)

=0

\(\frac{1}{3}.x+650\%x-x=-6\)

\(x.\left(\frac{1}{3}+650\%-1\right)=-6\)

\(\frac{35}{6}.x=-6\)

\(x=-6:\frac{35}{6}\)

\(x=-\frac{36}{35}\)

~ Thiên Mã ~

\(\frac{1}{3}x+650\%x-x=-6\)
\(\frac{1}{3}x+\frac{13}{2}x-x=-6\)
\(x\left(\frac{1}{3}+\frac{13}{2}-1\right)=-6\)
\(x\left(\frac{2}{6}+\frac{39}{6}-\frac{6}{6}\right)=-6\)
\(x\frac{35}{6}=-6\)
\(x=-6.\frac{35}{6}\)
\(x=-35\)
\(\Rightarrow x=-35\)

\(\frac{1}{3}x+650\%\cdot x-x=\left(-6\right)\)

\(\Rightarrow\frac{1}{3}x+6,5\cdot x-x=\left(-6\right)\)

\(\Rightarrow x\left(\frac{1}{3}+6,5-1\right)=\left(-6\right)\)

\(\Rightarrow x\left(\frac{1}{3}+\frac{13}{2}-1\right)=\left(-6\right)\)

\(\Rightarrow x\left(\frac{2}{6}+\frac{39}{6}-\frac{6}{6}\right)=\left(-6\right)\)

\(\Rightarrow x\left(\frac{2+39-6}{6}\right)=\left(-6\right)\)

\(\Rightarrow x\cdot\frac{35}{6}=\left(-6\right)\)

\(\Rightarrow x=\left(-6\right):\frac{35}{6}\)

\(\Rightarrow x=-\frac{36}{35}\)

a,   (2x-1)^6= (2x-1)^8

=>2x-1=1 hoặc 2x-1=0

2x=2 hoặc 2x=1

x=1 hoặc x=1/2

b,   5^x + 5^x+2= 650

5^x+5^x.5²=650

5^x(1+5²)=650

5^x.26=650

5^x=650:26

5^x=25

5^x=5²

=>x=2

b, 5^x + 5^x+2 = 650

  5^x ( 1 + 5^2) = 650

  5^x . 26         = 650

  5^x                =650:26

  5^x                 = 25

 5^x                   = 5^2

  x                     = 2

2x-1=-1

2x=-1+1

x=0

c) 5^x+5^x+2=650

=> 5^x+5^x5² = 650

=> 5^x ( 1+ 25 ) = 650 

=> 5^x          = 650 / 26

=> 5^x = 25 = 5²

=> x = 2

câu 1,2,4 nguyenthithuhang làm rồi mình chỉ chữa lại câu 3 thôi nha

Ta có :(2x-1)⁶ = (2x-1)⁸

             => 2x-1=1

                2x=2

                   x=1

       Vậy x=1