=7/2.(2/1.3+2/3.5+....+2/13.15)

=7/2.(1/1-1/3+1/3-1/5+....+1/13-1/15)

=7/2.(1-1/15)

=7/2.14/15=7.14/2.25

=7.7/1/15=49/15

Ai làm nhanh mk cho nah

\(\frac{7}{1\cdot3}+\frac{7}{3\cdot5}+\frac{7}{5\cdot7}+\frac{7}{7\cdot9}+\frac{7}{9\cdot11}+\frac{7}{11\cdot13}+\frac{7}{13\cdot15}\)

\(=\frac{7}{2}\left(\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+..........+\frac{2}{13\cdot15}\right)\)

\(=\frac{7}{2}\left(\frac{2}{1}-\frac{2}{3}+\frac{2}{3}-\frac{2}{5}+.........+\frac{2}{13}-\frac{2}{15}\right)\)

\(=\frac{7}{2}\left(2-\frac{2}{15}\right)=\frac{98}{15}\)

A = 35/39 

35/39 thid phải

A=7(1/3.5+1/5.7+1/7.9+1/9.11+1/11.13)

A=7(1/3-1/5+1/5-1/7+1/7-1/9+1/9-1/11+1/11-1/13)

A=7(1/3-1/13)

A=7.10/39

A=70/39

Vậy A=70/39

\(D=\dfrac{7}{15}+\dfrac{7}{35}+\dfrac{7}{63}+\dfrac{7}{99}+\dfrac{7}{143}\)

\(=7.\left(\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}+\dfrac{1}{143}\right)\)

\(=7.\left(\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.11}+\dfrac{1}{11.13}\right)\)

\(=7.\dfrac{1}{2}.\left(\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}\right)\)

\(=\dfrac{7}{2}.\left(\dfrac{1}{5}-\dfrac{1}{13}\right)\)

\(=\dfrac{7}{2}.\dfrac{8}{65}=\dfrac{28}{65}\)

D = 7\(\left(\dfrac{1}{15}+\dfrac{1}{35}+\dfrac{1}{63}+\dfrac{1}{99}+\dfrac{1}{143}\right)\)

= 7\(\left(\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.11}+\dfrac{1}{11.13}\right)\)

= 7\(\left[\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{11.13}\right):2\right]\)

= 7\(\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}\right)\): 2

= 7\(\left(\dfrac{1}{3}-\dfrac{1}{13}\right)\) : 2

= 7 . \(\dfrac{10}{39}\) : 2 = \(\dfrac{70}{78}\) = \(\dfrac{35}{39}\)

D=\(\dfrac{7}{3.5}+\dfrac{7}{5.7}+\dfrac{7}{7.9}+\dfrac{7}{9.11}+\dfrac{7}{11.13}\) =

\(7.\left(\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.11}+\dfrac{1}{11.13}\right)\)

=\(\dfrac{7}{2}.\left(\dfrac{2}{3.5}+\dfrac{2}{5.7}+\dfrac{2}{7.9}+\dfrac{2}{9.11}+\dfrac{2}{13}\right)\)\(\dfrac{7}{2}.\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{13}\right)\)=\(\dfrac{7}{2}.\left(\dfrac{1}{3}-\dfrac{1}{13}\right)\)

=\(\dfrac{35}{39}\)

11/15 nha

BẰNG 11/15 NHA BẠN

N=7/2(2/1.3+....+2/13.15)

N=7/2.(1/1-1/3+.....+1/13-1/15)

N=7/2.(1-1/15)

N=7/2.(14/15)

N=7.14/2.15

Bạn giải M luôn dc ko?

Dễ lắm bạn.Suy nghĩ 1 tí là ra

\(7.\left[\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right):2\right]\)

\(7.\left[\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right):2\right]\)

\(7.\left(\frac{1}{3}-\frac{1}{13}\right):2\)

\(7.\frac{10}{39}:2=\frac{35}{39}\)

\(\frac{7}{15}+\frac{7}{35}+\frac{7}{63}+\frac{7}{99}+\frac{7}{143}\)

\(=\frac{7}{2}\cdot\left(\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+\frac{2}{99}+\frac{2}{143}\right)\)

\(=\frac{7}{2}\cdot\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+\frac{2}{11.13}\right)\)

\(=\frac{7}{2}\cdot\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}\right)\)

\(=\frac{7}{2}\cdot\left(\frac{1}{3}-\frac{1}{13}\right)\)

\(=\frac{7}{2}\cdot\frac{10}{39}\)

\(=\frac{35}{39}\)

=7(1/3+1/15+1/35+...+1/9999)

=7(1/1.3+1/3.5+1/5.7+...+1/99.101)

=7(1-1/3+1/5-1/7+1/7-...+1/99-1/101)

=7(1-1/101)

=7.100/101=700/101

kết quả mk trà lời đó sai òi chia 2 nửa bạn ạ =305/101

Đặt \(A=1\frac{7}{15}-\frac{1}{3}-\frac{1}{15}-\frac{1}{35}-\frac{1}{63}-\frac{1}{99}-\frac{1}{143}-\frac{1}{195}\)

\(\Rightarrow A=\frac{22}{15}-\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\right)\)

Đặt \(B=\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}+\frac{1}{195}\)

\(\Rightarrow B=\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}+\frac{1}{11\cdot13}+\frac{1}{13\cdot15}\)

\(\Rightarrow2B=2\left(\frac{1}{1\cdot3}+\frac{1}{3\cdot5}+\frac{1}{5\cdot7}+\frac{1}{7\cdot9}+\frac{1}{9\cdot11}+\frac{1}{11\cdot13}+\frac{1}{13\cdot15}\right)\)

\(\Rightarrow2B=\frac{2}{1\cdot3}+\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+\frac{2}{9\cdot11}+\frac{2}{11\cdot13}+\frac{2}{13\cdot15}\)

\(\Rightarrow2B=1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}\)

\(\Rightarrow2B=1-\frac{1}{15}\)

\(\Rightarrow2B=\frac{14}{15}\)

\(\Rightarrow B=\frac{14}{15}:2\Rightarrow B=\frac{7}{15}\)

\(\Rightarrow A=\frac{22}{15}-\frac{7}{15}\Rightarrow A=\frac{15}{15}=1\)

đáp án là 59​/15

   mình chắc chắn

=22/15- 1/1.3 - 1/3.5 - 1/5.7 -.........- 1/11.13 - 1/13.15

=22/15 - (1/1.3+1/3.5+....+1/13.17)

=22/15 - 1/2(2/1.3+2/3.5.........+2/13.17)

=22/15 - 1/2(1-1/3+1/3-1/4+.............+1/13-1/17)

=22/15 - 1/2(1-1/17)

=22/15-8/17

=254/255