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bài 2
a)\(\left(x-\frac{5}{8}\right).\frac{5}{18}=\frac{-15}{36}\)
b)\(\frac{x+2}{5}=\frac{-15}{2}\)
c)\(x\)là ước của 4
Tìm x, biết:
a. \(\frac{-2}{5}+\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}\)
b.\(\frac{-2}{5}+\frac{2}{3}x+\frac{1}{6}x=\frac{-4}{15}\)
c. \(\frac{3}{2}x+\frac{-2}{5}-\frac{2}{3}x=\frac{-4}{15}\)
giúp dùm mình nhanh với nhé thnks các bạn nhiều
\(\frac{-2}{5}+\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}\) (a)
\(\frac{-2}{5}+\frac{2}{3}x+\frac{1}{6}x=\frac{-4}{15}\) (b)
\(\frac{3}{2}x+\frac{-2}{5}-\frac{2}{3}x=\frac{-4}{15}\)(c)
Mọi ng` giải giúp mình nhé! thanks các bạn nhiều.
a)Ta có: \(\frac{-2}{5}+\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}\)
\(\Rightarrow\frac{6}{5}.\left(y-\frac{2}{3}\right)=\frac{-4}{15}-\frac{-2}{15}\)
\(\Rightarrow\frac{6}{5}.\left(y-\frac{2}{3}=\right)\frac{-2}{5}\)
\(\Rightarrow y-\frac{2}{3}=\frac{-2}{5}:\frac{6}{5}=\frac{-1}{3}\)
\(\Rightarrow y=\frac{-1}{3}+\frac{2}{3}=\frac{1}{3}\)
Vậy x = \(\frac{1}{3}\)
b) Ta có: \(\frac{-2}{5}+\frac{2}{3}x+\frac{1}{6}x=\frac{-4}{15}\)
\(\Rightarrow\frac{-2}{5}+x.\left(\frac{2}{3}+\frac{1}{6}\right)=\frac{-4}{15}\)
\(\Rightarrow x.\frac{5}{6}=\frac{-4}{15}-\frac{-2}{15}\)
\(x.\frac{5}{6}=\frac{-2}{15}\)
\(\Rightarrow x=\frac{-2}{15}:\frac{5}{6}=\frac{-4}{25}\)
Vậy x = \(\frac{-4}{25}\)
c) Ta có: \(\frac{3}{2}x+\frac{-2}{5}-\frac{2}{3}.x=\frac{-4}{15}\)
\(\Rightarrow\frac{3}{2}x-\frac{2}{3}x+\frac{-2}{5}=\frac{-4}{15}\)
\(\Rightarrow x.\left(\frac{3}{2}-\frac{2}{4}\right)=\frac{-4}{15}-\frac{-2}{15}\)
\(\Rightarrow x.\frac{5}{6}=\frac{-2}{15}\)
\(\Rightarrow x=\frac{-2}{15}:\frac{5}{6}=\frac{-4}{25}\)
Vậy x = \(\frac{-4}{25}\)
Ủng hộ tớ nha m.n
Tìm x, biết:
a) ( x - 15 ) : 5 + 22 = 24
b) | x + 7 | = 15 - ( -4 )
c) \(\left(x-\frac{1}{2}\right)\div\frac{1}{3}+\frac{5}{7}=9\frac{5}{7}\)
giúp mình với m.n, mình cần gấp
a, (x-15):5+22=24
( x - 15 ) : 5 = 2
x-15 = 10
x = 25
\(\left(X-\frac{5}{8}\right)\cdot\frac{5}{18}=\frac{_{-15}}{36}\)
\(\left(x-\frac{5}{8}\right).\frac{5}{18}=-\frac{15}{36}\)
\(\left(x-\frac{5}{8}\right)=-\frac{15}{36}:\frac{5}{8}\)
\(\left(x-\frac{5}{8}\right)=-\frac{3}{2}\)
\(x=-\frac{3}{2}+\frac{5}{8}\)
\(x=-\frac{7}{8}\)
^...^ ^_^ hihihi
\(\left(x-\frac{5}{8}\right)\times\frac{5}{18}=\frac{-15}{36}\)
x-5/8= -15/36 : 5/18
x-5/8 = -3/2
x = -3/2 + 5/8
x= -7/8
\(\left(x-\frac{5}{8}\right).\frac{5}{8}=-\frac{15}{36}\)
\(\left(x-\frac{5}{8}\right)=-\frac{15}{36}:\frac{5}{8}\)
\(-\frac{3}{2}\)
x=\(-\frac{3}{2}+\frac{5}{8}=-\frac{7}{8}\)
tìm x,biết:
a)\(\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+8\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right)\left(x+14\right)}\)
b)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
c)\(\left(x+2\right)^2=\frac{38}{25}+\frac{9}{10}-\frac{11}{15}+\frac{13}{21}-\frac{15}{28}+\frac{17}{36}-...+\frac{197}{4851}-\frac{199}{4950}\)
giúp tớ với,huhu
Tìm X:
a)\(\frac{3}{4}+\frac{1}{4}:x=\frac{2}{5}\)
b)\(\left(-\frac{2^2}{3}\right).x=\left(-\frac{2}{3}\right)^5\)
c)\(\frac{15}{8}-\frac{1}{8}:\left(\frac{x}{4}-0,5\right)=\frac{5}{4}\)
Mk cần gấp, các bn giải cụ thể giúp mk nhé ^^
a) 3/4+ 1/4:x = 2/5
1/4:x = 3/4-2/5
1/4:x= 7/20
x= 7/20:1/4
x= 7/5
b) chưa học
c) 15/8-1/8: (x/4 - 0,5) = 5/4
1/8: (x/4 -1/2)= 15/8-5/4
1/8:( x/4 -1/2) = 5/8
x/4 - 1/2 = 1/8:5/8
x/4 -1/2= 1/5
x/4= 1/5+1/2
x/4 = 7/7
x/4= 7/7× 4/4
x/4= 28/28
4/4=28/28
phần c ko chắc chắn
đúng k nhé
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
Bài 1:tính giá trị biểu thức sau:
\(B=\left(1-\frac{1}{21}\right).\left(1-\frac{1}{28}\right).\left(1-\frac{1}{36}\right)...\left(1-\frac{1}{1326}\right)\)
Bài 2 tìm x biết
\(a,1\frac{1}{30}:\left(24\frac{1}{6}-24\frac{1}{5}\right)-\frac{1\frac{1}{2}-\frac{3}{4}}{4x-\frac{1}{2}}=\left(-1\frac{1}{15}\right):\left(8\frac{1}{5}-8\frac{1}{3}\right)\)
\(b,\left|3x-\frac{2}{5}\right|=\frac{1}{35}+\left|\frac{-3}{7}\right|\)
\(c,-3\frac{1}{2}-\left(2x+\frac{1}{2}\right):\left(-\frac{3}{7}\right)=0\)
\(d,\left(x-4\right).\left(x+2\right)\le0\)với x thuộc z
giúp mk với