Chứng minh rằng:
a)A=1/11+1/12+1/13+...+1/20>1/2 b)B=1/41+1/42+1/43+...+1/80>7/20
Những câu hỏi liên quan
chứng minh rằng
B=1/41+1/42+1/43+...+1/80>7/20
Chứng minh rằng
a) 1/2 + 1/3 + 1/4 +...+1/63 > 2
b) 1/41 + 1/42 + 1/43 +...+1/79 + 1/80 > 7/12
Chứng minh:7/12< 1/41+1/42+1/43+...+1/79+1/80<1
A<10(1/40+1/50+1/70+1/60)=319/420<1
A>10(1/50+1/60+1/70+1/80)>7/12
=>7/12<A<1
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Hãy chứng tỏ rằng:
a) 1/41+1/42+1/43+...+1/79+1/80>7/12
b)11/15<1/21+1/22+1/23+...+1/59+1/60<3/2
a) cho A =999993^1999 - 555557^4997. Chứng minh rằng A chia hết cho 5
b) Chứng tỏrằng : 1/41+1/42+1/43+...+1/79+1/80>7/12
Chứng minh : 7/12<1/41+1/42+1/43+........+1/80<1
Chứng minh 1/41 + 1/42 + 1/43 + ... + 1/79 + 1/80 > 7/12
Ta có:
7/12 = 4/12 + 3/12 = 1/3 + 1/4 = 20/60 + 20/80
1/41 + 1/42 + 1/43 +...+ 1/79 + 1/80 = (1/41 + 1/42 + 1/43 + ...+ 1/60) + (1/61 + 1/62 +...+ 1/79 + 1/80)
Do 1/41> 1/42 > 1/43 > ...>1/59 > 1/60
=> (1/41 + 1/42 + 1/43 + ...+ 1/60) > 1/60 + ...+ 1/60 = 20/60
và 1/61> 1/62> ... >1/79> 1/80
=> (1/61 + 1/62 +...+ 1/79 + 1/80) > 1/80 + ...+ 1/80 = 20/80
Vậy: 1/41 + 1/42 + 1/43 +...+ 1/79 + 1/80 > 20/60 + 20/80 = 7/12
=> 1/41 + 1/42 + 1/43 +...+ 1/79 + 1/80 > 7/12
=> ĐPCM
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Chứng minh rằng :1/41+1/42+1/43+...+1/80 > 7/12
Ta có:
7/12 = 4/12 + 3/12 = 1/3 + 1/4 = 20/60 + 20/80
1/41 + 1/42 + 1/43 +...+ 1/79 + 1/80 = (1/41 + 1/42 + 1/43 + ...+ 1/60) + (1/61 + 1/62 +...+ 1/79 + 1/80)
Do 1/41> 1/42 > 1/43 > ...>1/59 > 1/60
=> (1/41 + 1/42 + 1/43 + ...+ 1/60) > 1/60 + ...+ 1/60 = 20/60
và 1/61> 1/62> ... >1/79> 1/80
=> (1/61 + 1/62 +...+ 1/79 + 1/80) > 1/80 + ...+ 1/80 = 20/80
Vậy: 1/41 + 1/42 + 1/43 +...+ 1/79 + 1/80 > 20/60 + 20/80 = 7/12
=> 1/41 + 1/42 + 1/43 +...+ 1/79 + 1/80 > 7/12 ( ĐPCM )
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Chứng minh rằng: 1/41+1/42+1/43+..........+1/79+1/80>7/12
Chứng minh : 7/12<1/41+1/42+1/43+...+1/80 <1
