12/1.2.22/2.3.32/3.4.......9992999.1000
Bài 1
A=1.2+2.3+3.4+....+151.152
B=1.3+3.5+5.7+...+2023.2025
C=2.4+4.6+...+2024.2026
D=1.2+3.4+...+200.202
M=12+22+...+20242
N=13+23+...+1003
Q=13+23+...+20243
R=12+22+...+2003
\(A=1\cdot2+2\cdot3+...+151\cdot152\)
\(=1\left(1+1\right)+2\left(1+2\right)+...+151\left(1+151\right)\)
\(=\left(1+2+3+...+151\right)+\left(1^2+2^2+...+151^2\right)\)
\(=\dfrac{151\left(151+1\right)}{2}+\dfrac{151\left(151+1\right)\left(2\cdot151+1\right)}{6}\)
\(=151\cdot76+\dfrac{151\cdot152\cdot303}{6}\)
\(=151\cdot76+151\cdot7676=1170552\)
\(C=2\cdot4+4\cdot6+...+2024\cdot2026\)
\(=2\cdot2\left(1\cdot2+2\cdot3+...+1012\cdot1013\right)\)
\(=4\left[1\left(1+1\right)+2\left(1+2\right)+...+1012\left(1+1012\right)\right]\)
\(=4\left[\left(1+2+...+1012\right)+\left(1^2+2^2+...+1012^2\right)\right]\)
\(=4\left[1012\cdot\dfrac{1013}{2}+\dfrac{1012\left(1012+1\right)\left(2\cdot1012+1\right)}{6}\right]\)
\(=4\left[506\cdot1013+345990150\right]\)
\(=1386010912\)
\(M=1^2+2^2+...+2024^2\)
\(=\dfrac{2024\left(2024+1\right)\cdot\left(2\cdot2024+1\right)}{6}\)
\(=2024\cdot2025\cdot\dfrac{4049}{6}\)
=2765871900
\(N=1^3+2^3+...+100^3\)
\(=\left(1+2+3+...+100\right)^2\)
\(=\left[\dfrac{100\left(100+1\right)}{2}\right]^2\)
\(=\left[50\cdot101\right]^2=5050^2\)
\(Q=1^3+2^3+...+2024^3\)
\(=\left(1+2+3+...+2024\right)^2\)
\(=\left[\dfrac{2024\left(2024+1\right)}{2}\right]^2\)
\(=\left[1012\left(2024+1\right)\right]^2\)
\(=2049300^2\)
12:3.4+3.23=?
RÚT GỌN : A =\(\frac{4.8^4.6^7-9^3.4^{16}}{12^3.4^4+18^3.32^3}\)
Mấy bn help mk vs nha !!!!!!!!!!!!!!!1
Bằng -16322,21709
00000000000
2.x-[3.4+4.5+5.6+....+79.80]=12
5x+3x=3^6:3^3.4+12
Cho A=1/3.4/6.7/9.10/12...2008/2010
Chứng minh A<125
( 1.2 + 2.3 + 3.4 + ...... + 98.99 ) x / 26950 = 12/6/7 : 3/2
Khó quá mk chịu thôi bạn giải giùm mk nha
k mình đi
kb luôn nhé
cmr A =1/3.4/6.7/9.10/12.....208/210 < 1/25
1/2 . (2/1 . 2. .3+2/2 .3.4+2/3.4.5+... 2/18 . 19 . 12)
\(=\dfrac{1}{2}\cdot2\cdot\left(\dfrac{1}{1\cdot2\cdot3}+\dfrac{1}{2\cdot3\cdot4}+...+\dfrac{1}{18\cdot19\cdot20}\right)\)
\(=\dfrac{1}{1\cdot2}-\dfrac{1}{2\cdot3}+\dfrac{1}{2\cdot3}-\dfrac{1}{2\cdot4}+...+\dfrac{1}{18\cdot19}-\dfrac{1}{19\cdot20}\)
=1/2-1/380
=179/380
Thày mềnh cho đề: Tìm x,y biết 4x=3y và xy=12
Và thầy làm như sau: 4x=3y=>x/3=y/4 => x^2/9=y^2/16=x.y/3.4=12/12=1
Minh ko hiểu chỗ này cho lắm: x^2/9=Y^2/16=x.y/3.4
MONG mÂYs bạn giải thich giup minh voi
THANKs!