b)|x-2|=3

=>x-2=3

x=3+2

x=5

hoặc x-2=-3

x=-3+2

x=-1

|x - 5| = |-7|

=> |x - 5| = 7

=> \(\orbr{\begin{cases}x-5=7\\x-5=-7\end{cases}}\)

=> \(\orbr{\begin{cases}x=12\\x=-2\end{cases}}\)

c ) | x - 5 | = | -7 |

cs 2 trường hợp

TH1 x-5=7

x=5+7

x=12

TH2 x-5=-7

x=-7+5

x=-2

# chi kute@#

| x -5 | = | -7 |

=> | x-5 | = \(\pm\)7

=>\(\orbr{\begin{cases}\left|x-5\right|=-7\\\left|x-5\right|=7\end{cases}}\)

=> \(\orbr{\begin{cases}\left|x\right|=-7+5\\\left|x\right|=7+5\end{cases}}\)

=> \(\orbr{\begin{cases}x=-2\\x=12\end{cases}}\)

a.\(7:\left|x-3\right|=4\)

\(\Leftrightarrow\left|x-3\right|=\frac{7}{4}\Leftrightarrow\orbr{\begin{cases}x-3=\frac{7}{4}\\x-3=\frac{-7}{4}\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{7}{4}+3\\x=\frac{-7}{4}+3\end{cases}}}\Leftrightarrow\orbr{\begin{cases}x=\frac{19}{4}\\x=\frac{5}{4}\end{cases}}\)

Vậy x = 19/4 hoặc x = 5/4

b. \(12:\left(x-8\right)=114\)

                 \(x-8=\frac{12}{114}=\frac{2}{19}\)

                 \(x=\frac{2}{19}+8\)

                 \(x=\frac{154}{19}\)

c. \(47+\left|x-7\right|=123\)

\(\Leftrightarrow\left|x-7\right|=123-47\Leftrightarrow\left|x-7\right|=76\)

\(\Leftrightarrow\orbr{\begin{cases}x-7=76\\x-7=-76\end{cases}\Leftrightarrow\orbr{\begin{cases}x=83\\x=-69\end{cases}}}\)

Vậy x = 83 hoặc x = -69

d.\(188+\left|3x-1\right|=1198\)

\(\Leftrightarrow\left|3x-1\right|=1198-188\Leftrightarrow\left|3x-1\right|=1010\)

\(\Leftrightarrow\orbr{\begin{cases}3x-1=1010\\3x-1=-1010\end{cases}\Leftrightarrow\orbr{\begin{cases}3x=1010+1\\3x=-1010+1\end{cases}\Leftrightarrow}\orbr{\begin{cases}3x=1011\\3x=-1009\end{cases}}}\Leftrightarrow\orbr{\begin{cases}x=337\\x=\frac{-1009}{3}\end{cases}}\)

Vậy x = 337 hoặc x= -1009/3

e. \(\left|4-x\right|+3=12\)

\(\Leftrightarrow\left|4-x\right|=12-3\Leftrightarrow\left|4-x\right|=9\)

\(\Leftrightarrow\orbr{\begin{cases}4-x=9\\4-x=-9\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=4-9\\x=-4-9\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-5\\x=-13\end{cases}}}\)

Vậy x = -5 hoặc x = -13

g. \(\left|12x\right|-9=-41\)

\(\Leftrightarrow\left|12x\right|=-41+9\Leftrightarrow\left|12x\right|=-32\)\(\text{(Vô Lí)}\)

Vậy không tồn tại x  

\(-12(x-5)+7(3-x)=5\)

\(\Rightarrow-12x-60+21-7x=5\)

\(\Rightarrow-12x-7x-60+21=5\)

\(\Rightarrow-12x-7x-81=5\)

\(\Rightarrow-19x-81=5\)

\(\Rightarrow81-19x=5\)

\(\Rightarrow-19x=-76\)

\(\Rightarrow x=4\)

-12(x-5)+7(3-x)=5

-12x-(-12.5)+7.3-7x=5

-12x-(-60)+21-7x=5

-12x-(-60)+21=5+7x

-12x-(-60)=5+7x-21

-12x=5+7x-21+(-60)

-12x-7x=5-21+(-60)

-19x=-76

  x=-76:(-19)

  x=4

          vậy x=4

-12 ( x - 5 ) + 7 ( 3 - x ) = 5

-12x + 12 . 5 + 7 . 3 - 7x = 5

-12x + 60 + 21 - 7x = 5

-12x - 7x = 5 - 60 - 21

-19x = -76

x = -76 : (-19)

x = 4

các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha

a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)

              -\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)

              -6 < \(x\) < -4

             vì \(x\) \(\in\) Z nên \(x\) = -5

- \(\dfrac{19}{6}+\dfrac{-15}{2}+\dfrac{11}{3}\) < \(x\) < - \(\dfrac{5}{4}\) + \(\dfrac{19}{12}\) - \(\dfrac{10}{3}\)

- \(\dfrac{32}{3}+\dfrac{11}{3}< x< \) \(\dfrac{1}{3}\) - \(\dfrac{10}{3}\)

-7 < \(x\) < - 3

Vì \(x\in\) Z nên \(x\in\) {-6;-5;-4}

a)2.25 hoac 9/4

b)0.8 hoac 4/5

c)-0.15 hoab -3/20

t cho minh nha