1/4;3/5;5/8;1;13/8;?
Ai giải bài này hộ em với
Rút gon phân thức:
A=(1^4+1/4).(3^4+1/4).(5^4+1/4)....(11^4+1/4) / (2^4+1/4).(4^4+1/4).(6^4+1/4)....(12^4+1/4)
Tính giá trị của biểu thức
A= (1+1/4)(3^4 +1/4)(5^4 +1/4)...(29^4+1/4)/2^4+1/4)(4^4+1/4)(6^4+1/4)...(30^4+1/4)
1+1+1+1+1+1+1+1+1+1+1+11+11+1+1+1+1+1+1+1+11+0+0+0+0+0+4+4+4+4+4+4+4+4+4+4+4+4+4++4+4+44+0+0+0+++0+0++0+0++0+0+0++0
kết quả bằng bao nhiêu?
chào kim ngưu kết quả bằng 122
tích cho anh nha
đúng ghi Đ sai ghi S
a)1-3/4+1/4=1-3+1/4 b)1-3/4+1/4=4/4-3/4+1/4
=1-1=0[ ] 1/4+1/4=1/2[ ]
1 - \(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) = \(\dfrac{4}{4}\) - \(\dfrac{3}{4}\) + \(\dfrac{1}{4}\) = \(\dfrac{2}{4}\) = \(\dfrac{1}{2}\)
Vậy a, S còn b, Đ
tính A = (1^4 + 1/4 ).(3^4 +1/4)......(2019^4 + 1/4) / (2^4 + 1/4 ).(4^4 +1/4).......(2018^4 + 1/4)
Tính S= (2^4 + 1/4) (4^4 + 1/4).... (100^4+1/4) / (1^4+1/4) (3^4 +1/4) .... (99^4+1/4)
Tính giá trị biểu thức: A= (1+1/4)(3^4 +1/4)(5^4 + 1/4).....(29^4 +1/4) / (2^4 +1/4)(4^4 +1/4).......(30^4 +1/4)
Tính : \(\frac{\left(1^4+\frac{1}{4}\right)\left(3^4+\frac{1}{4}\right)\left(5^4+\frac{1}{4}\right)\left(7^4+\frac{1}{4}\right)\left(9^4+\frac{1}{4}\right)\left(11^4+\frac{1}{4}\right)}{\left(2^4+\frac{1}{4}\right)\left(4^4+\frac{1}{4}\right)\left(6^4+\frac{1}{4}\right)\left(8^4+\frac{1}{4}\right)\left(10^4+\frac{1}{4}\right)\left(12^4+\frac{1}{4}\right)}\)
Tính A/B
A=(14+1/4)(34+1/4)(54+1/4)...........(194+1/4)
B=(24+1/4)(44+1/4)(64+1/4)...........(204+1/4)
Tính A/B
A=(14+1/4)(34+1/4)(54+1/4)...........(194+1/4)
B=(24+1/4)(44+1/4)(64+1/4)...........(204+1/4)