Tìm x, biết:
a) ( \(\frac{11}{1.2}\)+ \(\frac{11}{12.13}\)+\(\frac{11}{23.24}\)+....+ \(\frac{11}{89.100}\)) + x = \(\frac{5}{3}\)
Các bn giúp mik với nếu đề sai thì sửa giùm mik nhé
tìm x, biết
a, \(\left(\frac{11}{12}+\frac{11}{12.23}+\frac{11}{23.24}+...+\frac{11}{89.100}\right)+x=\frac{5}{3}\)
b, \(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right)-x+4+\frac{221}{231}=\frac{7}{3}\)
(\(\frac{11}{12}+\frac{11}{12.23}+\frac{11}{23.24}+...+\frac{11}{89.100}\))+x = \(\frac{2}{3}\)
tìm x, biết
a ) \(( 11/ 12 + 11/ 12.13 + 11/ 23.24 +...+11/ 89.100 ) + x= 5/2\)
b) \(1/ 3+ 1/ 6 + 1/ 10 +...+ 2/ x(x+1) = 199/ 2001\)
giúp mik với mik cần gấp lắm
=`123456789009895436891619370390615895`96312836092419643527671493963894583594783285675 NHA BẠN!?~~~~~~
\(\frac{11}{12}+\frac{11}{12.23}+\frac{11}{23.24}+...+\frac{11}{89.100}\)=?
Tìm x biết:
\(\left(\frac{11}{12}+\frac{11}{12.23}+...+\frac{11}{89.100}\right)+x=\frac{2}{3}\)
Hình như câu này sai đề
Bài này dài dòng lắm sai thì không sai bây giờ tớ cho kết quả
= 11-11/100 = 1089/100+x =2/3
Suy ra x= 2/3 -1089/100=-3067/300(âm ba trăm sáu mươi bảy phần ba trăm)
Nếu đúng thì k ủng hộ mik nha bye chúc bạn chăm học
1.tính (nhanh nếu có thể)
a) \(\frac{3}{11}x\frac{13}{5}-\frac{3}{5}x\frac{8}{11}\)
b)\(\left(\frac{2}{5}+\frac{1}{4}\right)x\left(\frac{2}{11}-\frac{7}{11}\right)\)
c)\(\frac{2}{7}+\frac{5}{7}-\frac{14}{15}\)
các bạn nhanh giúp mik nhé,mik gấp lắm rồi
Bài 1:Tìm các số nguyên x để:
a. 18/17+ 5/17< x/17<6/17+9/17
b.1/3+3/35< x/210< 4/7+ 3/5+ 1/3
Bài 2: Tìm x biết ( 11/12+ 11/12.23+11/23.24+...+11/89.100)+ x=5/3
Bài 3: Tìm số nguyên n để biểu thức sau có giá trị là số nguyên: 4/n-1+ 6/n-1-3/n-1
Bài 4:Tính tổng:
a. 1/1.2+ 1/2.3+ 1/3.4+...+1/98.99+ 1/99.100 ; b. 3/2.5+ 3/5.8+ ...+ 3/17.20
Bài 5: Tìm số nguyên x biết
a. x: 3\(\frac{1}{15}\)= 1\(\frac{1}{2}\); b.x. 15/28= 3/20; 5\(\frac{4}{7}\): x =13
\(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}\)
Giúp mik với !! mik ko hiểu bài này !! giúp mik nhé
\(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}.\)
\(\frac{x+1}{2009}+1+\frac{x+2}{2008}+1+\frac{x+3}{2007}+1=\frac{x+10}{2000}+1+\frac{x+11}{1999}+1+\frac{x+12}{1998}+1.\)(cộng 2 vế cho 3)
\(\frac{x+1}{2009}+\frac{2009}{2009}+\frac{x+2}{2008}+\frac{2008}{2008}+\frac{x+3}{2007}+\frac{2007}{2007}=\frac{x+10}{2000}+\frac{2000}{2000}+\frac{x+11}{1999}+\frac{1999}{1999}+\frac{x+12}{1998}+\frac{1998}{1998}.\)
\(\frac{x+2010}{2009}+\frac{x+2010}{2008}+\frac{x+2010}{2007}=\frac{x+2010}{2000}+\frac{x+2010}{1999}+\frac{x+2010}{1998}.\)
\(\frac{x+2010}{2009}+\frac{x+2010}{2008}+\frac{x+2010}{2007}-\frac{x+2010}{2000}-\frac{x+2010}{1999}-\frac{x+2010}{1998}=0\)
x+2010=0
x=-2010
\(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}\)
\(\Leftrightarrow\left(1+\frac{x+1}{2009}\right)+\left(1+\frac{x+2}{2008}\right)+\left(1+\frac{x+3}{2007}\right)\)
\(=\left(1+\frac{x+10}{2000}\right)+\left(1+\frac{x+11}{1999}\right)+\left(1+\frac{x+12}{1998}\right)\)
\(\Leftrightarrow\frac{x+2010}{2009}+\frac{x+2010}{2008}+\frac{x+2010}{2007}=\frac{x+2010}{2000}+\frac{x+2010}{1999}+\frac{x=2010}{1998}\)
\(\Leftrightarrow\frac{x+2010}{2009}+\frac{x+2010}{2008}+\frac{x+2010}{2007}-\frac{x+2010}{2000}-\frac{x+2010}{1999}-\frac{x+2010}{1998}\)
\(=0\)
\(\Leftrightarrow\left(x+2010\right)\left(\frac{1}{2009}+\frac{1}{2008}+\frac{1}{2007}-\frac{1}{2000}-\frac{1}{1999}-\frac{1}{1998}\right)=0\)
\(\Leftrightarrow x+2010=0\)
\(\Leftrightarrow x=-2010\)
\(\frac{x+1}{2009}+\frac{x+2}{2008}+\frac{x+3}{2007}=\frac{x+10}{2000}+\frac{x+11}{1999}+\frac{x+12}{1998}\)
\(\Leftrightarrow\frac{x+1}{2009}+1+\frac{x+2}{2008}+1+\frac{x+3}{2007}+1=\frac{x+10}{2000}+1+\frac{x+11}{1999}+1+\frac{x+12}{1998}+1\)
\(\Leftrightarrow\frac{x+2010}{2009}+\frac{x+2010}{2008}+\frac{x+2010}{2007}=\frac{x+2010}{2000}+\frac{x+2010}{1999}+\frac{x+2010}{1998}\)
\(\Leftrightarrow\left(x+2010\right)\left(\frac{1}{2009}+\frac{1}{2008}+\frac{1}{2007}-\frac{1}{2000}-\frac{1}{1999}-\frac{1}{1998}\ne0\right)=0\Leftrightarrow x=-2010\)
a)\(11\frac{1}{4}-\left(2\frac{5}{7}+5\frac{1}{4}\right)\)
b)\(\left(8\frac{5}{11}+3\frac{5}{8}\right)-3\frac{5}{11}\)
Các bạn giúp mik nhé mik sẽ tick và kêt bạn . Cảm ơn nhiều!
a, 11 1/4-(2 5/7+5 1/4)
= 45/4-(19/7+21/4)
= 45/4-223/28
=23/7
b, (8 5/11+3 5/8)-3 5/11
=(93/11+29/8)-38/11
=1063/88-38/11
=69/8
a, =\(11\frac{1}{4}-2\frac{5}{7}-5\frac{1}{4}\)
\(=\left(11\frac{1}{4}-5\frac{1}{4}\right)-2\frac{5}{7}\)
\(=6-2\frac{5}{7}\)
\(=\frac{23}{7}\)
b, \(=8\frac{5}{11}+3\frac{5}{8}-3\frac{5}{11}\)
\(=\left(8\frac{5}{11}-3\frac{5}{11}\right)+3\frac{5}{8}\)
\(=5+3\frac{5}{8}\)
\(=\frac{69}{8}\)
Bạn Pham Ngoc Anh ơi ! Sorry bạn nhé ! mik chỉ có thể k 1 lần thay vì không k được mik sẽ kết bạn nhé !