Tìm x
71+65.4 = x+140/x+260
71+65.4=[x+140]:x+260
\(331=\left(x+140\right).\frac{1}{x}+260\)
\(\left(x+140\right).\frac{1}{x}+260-331=0\)
\(\left(x+140\right).\frac{1}{x}-71=0\)
\(\frac{1}{x}.x+\frac{1}{x}.140-71=0\)
\(1+\frac{1}{x}.140=0\)
\(\frac{1}{x}.140=0-1=-1\)
\(\frac{1}{x}=-\frac{1}{140}\Rightarrow x=1:-\frac{1}{140}=-140\)
\(71+260=\frac{x+140+260x}{x
}\)
\(331=\frac{261x+140}{x}\)
\(331x=261x+140\)
\(70x=140\)
\(x=2\)
Nhớ thêm dấu khi và chỉ khi <=> trước mỗi phép kia nhé, mình lười quá không ghi
331= [x+140]:x+260 hay [x+140]:x+260=331
x/x + 140/x + 260 = 331
1 + 140/x + 260 = 331
1 + 140/x = 331 - 260
1 + 140/x = 71
140/x = 71 - 1
140/x = 70
=> x = 140 : 70 = 2
71+65.4=[x+140]:x+260
tim x
a, ( x 0,25+1999).2000=(53+1999).2000
b, 71+65.4=x+140/x+260
a, ( x . 0,25+1999).2000=(53+1999).2000
=> 500x + 1999 . 2000 = 53 . 2000 + 1999 . 2000
=> 500x = 53 . 2000 + 1999 . 2000 - 1999 .2000
=> 500x = 53 . 2000
=> x = 53 . 2000 : 500
=> x = 53 . 4
=> x = 212
Bài 6: Tìm X
a) \(\frac{3}{x-7}=\frac{27}{135}\)
b) \(71+65.4=\frac{x+140}{x}+260\)
c) \(1,2.\left(\frac{24.x-0,23}{x}-0,05\right)=1,44\)
Giúp mik 3 câu trên vs ạ. Mik cảm ơn!
a) 3/x-7 = 27/135
3/x-7 = 3/15
x - 7 = 15
x = 15 + 7
x = 22
a) \(\frac{3}{x-7}=\frac{27}{135}\)
\(\Rightarrow\)\(\left(x-7\right).27=3.135\)
\(\Rightarrow\)\(\left(x-7\right).27=405\)
\(\Rightarrow\)\(x-7=15\)
\(\Rightarrow\)\(x=22\)
Vậy \(x=22\)
b ) \(71+65.4=\frac{x+140}{x}+260\)
\(71+260=\frac{x+140}{x}+260\)
\(331=\frac{x+140}{x}+260\)
\(331-260=\frac{x+140}{x}\)
\(71=\frac{x+140}{x}\)
\(71=\frac{x}{x}+\frac{140}{x}\)
\(71=1+\frac{140}{x}\)
\(70=\frac{140}{x}\)
\(x=140\div70\)
\(x=20\)
Vậy \(x=20\)
#TQY
331= [x+140]:x+260 hay [x+140]:x+260=331
x/x + 140/x + 260 = 331
1 + 140/x + 260 = 331
1 + 140/x = 331 - 260
1 + 140/x = 71
140/x = 71 - 1
140/x = 70
=> x = 140 : 70 = 2
tìm x :71+65x4=x+140/x+260
Trả lời:
71+65.4=x+140/x+260
x+140/x+260=71+65.4
x+140/x+260=71+260
x+140/x=71
x/x+140/x=71
1+140/x=71
140/x=71-1
140/x=70
x=140/70
x=2
vậy x=2
cậu ơi cái chỗ 71+65x4 là nhân 4 hay là 65 nhân x nhân 4 ạ
là 65 nhân 4 nghe
71 + 65 x 4 = X + 140 / X + 260. tìm X
tìm X
71+65x4=X+140/X+260
tìm X
71 + 65 x 4 = X + 140 / X +260
hình như bn viết ngược
bài giải
x + 140/x + 260=331
x nhân 2 + 140 =331-260=71
x nhân 2 =71 : 140 =0,50
x= 0,50 : 2
x=0,25
hok tốt
\(71+65\) x 4 = \(\frac{x+140}{x+260}\)
=> 71 + 260 = \(\frac{x+140}{x+260}\)
=> \(331=\frac{x+140}{x+260}\)
=> \(331.\left(x+260\right)=x+140\)
=> \(331x+86060=x+140\)
=> \(331x-x=-86060+140\)
=>330x =- 85920
=> x = -2864/11
=> \(330x=-85920\)
tìm x biết
71 + 65x4=(x + 140):x +260
71+ 65x4 = (x+140) :x + 260
71 + 260 = x:x + 140:x + 260
71 + 260 - 1- 260 = 140x
70 = 140x
x= 70 : 140
x= 1/2