Rut gon bieu thuc sau: 472*524/216= ?
Những câu hỏi liên quan
rut gon bieu thuc sau : 4^2.25^2+32.125/2^3.5^2
- rut gon bieu thuc sau :123 .(125.127 -125.87) +87.125.123 -123.125.126
123. (125.127- 125 .87) +87.125.123 -123 .125.126
=123. [125.(127-87)] +87.125.123 -123 .125.126
=123. (125.40) +87.125.123 -123 .125.126
=123.5000 +10875.123 -123 .15750
=123.(5000+10875-15750)
=123.125
=15375
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Cho bieu thuc:
P=\(\frac{1}{\sqrt{x}+2}-\frac{5}{x-\sqrt{x}-6}-\frac{\sqrt{x}-2}{3-\sqrt{x}}\)
a. Rut gon bieu thuc P
b.Tim GTLN cua P sau khi rut gon
đk: x>=0; x khác 3
a) \(P=\frac{\sqrt{x}-3}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}-\frac{5}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}+\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+2\right)}{\sqrt{x}-3}=\frac{\sqrt{x}-3-5+x-4}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}=\frac{x+\sqrt{x}-12}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}\)
\(P=\frac{\left(\sqrt{x}+4\right)\left(\sqrt{x}-3\right)}{\left(\sqrt{x}+2\right)\left(\sqrt{x}-3\right)}=\frac{\sqrt{x}+4}{\sqrt{x}+2}\)
b) \(P=\frac{\sqrt{x}+2+2}{\sqrt{x}+2}=1+\frac{2}{\sqrt{x}+2}\)
ta có: \(x\ge0\Rightarrow\sqrt{x}\ge0\Leftrightarrow\sqrt{x}+2\ge2\Leftrightarrow\frac{2}{\sqrt{x}+2}\le1\Leftrightarrow1+\frac{2}{\sqrt{x}+2}\le2\Rightarrow MaxP=2\Rightarrow x=0\)
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rut gon bieu thuc sau:
(x+5)^3-15x(x+10)
rut gon bieu thuc sau -4+{x-15}+3
-4+(x-15)+3
=-4+x-15+3
=x-19+3
=x-16
nhớ k mk nha
rut gon bieu thuc sau
A=5x-2-/2x+1/
Rut gon cacc bieu thuc sau : ( 4x - 3 ).( x - 5 ) - 2x ( 2x- 11)
\(\left(4x-3\right).\left(x-5\right)-2x\left(2x-11\right)\)
=\(4x^2-20x-3x+15-\left(4x^2-22x\right)\)
\(=4x^2-20x-3x+15-4x^2+22x\)
\(=-x+15\)
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rut gon bieu thuc sau : (-12).(-2)-[|-3|^2-(-2)^3.3]/(-3)^3
rut gon bieu thuc
(2x-1).(x-2)
