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Nguyễn Duy Minh
22 tháng 11 2015 lúc 16:19

gợi ý bài 1 : a.b = BCNN(a,b) . UCLN(a,b) và mở SBT ra

Nguyễn Thị Thanh Bình
13 tháng 12 2021 lúc 21:01

không biết

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Nguyễn Thành Đạt
31 tháng 1 2022 lúc 10:50

UKM

^6^7g^7*(KHV C GTGFCCGttedx

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Nhok Cuồng Tùng
8 tháng 12 2015 lúc 20:30

a) goi hai so la a ; b va a >b

vi UCLN(a,b)=18=>a=18k            ;       b=18q       (trong do UCLN (k,q)=1 va k>q)

=>a+b=162

18k+18q =162

18(k+q)=162

k+q=9

ta co bang sau   

 

k1234
q8765
a18365472
b14412610890

vay ...........

   
    
    

 

Nguyễn Nhật Quang
29 tháng 10 2016 lúc 13:10

21453 

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542454550212.100000000000000000000000000000000000000000000000000000000000000000000000000000
  
  
viet
12 tháng 11 2017 lúc 19:54

ngyen vu thien nhan coi sach

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Hồ Trần Minh Anh
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Nguyễn Xuân Thành
4 tháng 9 2023 lúc 17:34

Vì \(BCNN\left(a,b\right)=300\) và \(ƯCLN\left(a,b\right)=15\)

\(\Leftrightarrow a.b=300.15=4500\)

Vì \(ƯCLN\left(a,b\right)=15\) nên \(a=15m\) và \(b=15n\) với \(ƯCLN=\left(m,n\right)=1\)

Vì \(a+15=b\Rightarrow15m+15=15n\Rightarrow15\left(m+1\right)=15n\)

\(\Leftrightarrow m+1=n\)

Mà \(a.b=4500\Rightarrow15m.15n=4500\Rightarrow15.15.m.n=4500\)

\(\Leftrightarrow m.n=20\)

\(\Leftrightarrow m=1\) và \(n=20\) hoặc \(m=4\) và \(n=5\)

Phan Mạnh Quân
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