tim x,y biet
x.y=15
tim x,y biet 15^x+8=y^2
tim x va y biet
x/15=y/21va2x-y=34
ta có x/15=y/21
áp dụng tính chất của dãy tỉ số bằng nhau ta có
2x/30=y/21=2x-y/30-21=34/9
-> 2x=34/9.30
y=21.34/9
-> 2x=340/3
y=238/3
->x=170/3
y=238/3
vậy...
tim y,x
y(x+3)-5x-15=2
tim x;y de -xx(2-y)=10 (1-x)x(1+y)=-15
tim x va y biet : xy – 2x + y = 15
xy-2x+y=15
<=.xy-2x+y-2=13
<=>x(y-2)+(y-2)=13
<=>(x+1)(y-2)-13=0
<=>(x+1)(y-2)-13=-13.1=13.(-1)
x+1 -13 1 13 -1
y-2 1 -13 -1 13
x -14 0 12 -2
y 3 -11 1 15
vậy pt có 4 nghiệm:
(1)x=-14 ; y=3
(2)x=0 ; y=-11
(3)x=12 ; y=1
(4)x=-2 ; y=15
Tim cac so x,y,z biet x/y=9/7; y/2=7/3 va x-y+z=-15
TIm y 99 - 7 x y : 6 = 15
Tim x,y biết y.x=-15
Vì \(y.x=-15\)
\(\Rightarrow y;x\inƯ\left(-15\right)\)
Mà \(Ư\left(-15\right)=\left\{1;3;5;15;-1;-3;-5;-15\right\}\)
Ta có bảng :
x | 1 | 3 | 5 | 15 | -1 | -3 | -5 | -15 |
y | 15 | 5 | 3 | 1 | -15 | -5 | -3 | -1 |
Vậy \(\left(x,y\right)\in\left\{\left(1;15\right),\left(3;5\right),\left(5;3\right),\left(15;1\right),\left(-1;-15\right),\left(-3;-5\right),\left(-5;-3\right),\left(-15;-1\right)\right\}\)
tim x,y,z
3/x=21/35y=y/25=-18/z=1/15
Bài làm
Ta có: 3/x = 21/35y = y/25 = -18/z = 1/15
=> z = -18 . 15 : 1 = -270
=> y = 25 . ( -18 ) : z = 25 . ( -18 ) : ( -270 ) = 5/3
=> x = 3 . 35y : 21 = 3 . 35 . 5/3 : 21 = 25/3
Vậy x = 25/3, y = 5/3, z = -270
\(\frac{3}{x}=\frac{21}{35y}=\frac{y}{25}=-\frac{18}{z}=\frac{1}{15}\)
Xét : \(\frac{3}{x}=\frac{1}{15}\Leftrightarrow45=x\Leftrightarrow x=45\)
Xét : \(\frac{y}{25}=\frac{1}{15}\Leftrightarrow15y=25\Leftrightarrow y=\frac{5}{3}\)
Xét : \(-\frac{18}{z}=\frac{1}{15}\Leftrightarrow-270=x\Leftrightarrow x=-270\)
tim x , y tu nhien biet (x^2+1)(2^x+2)(2^x+3)(2^x+4) +15^y=1679