\(4\frac{25}{16}\)+25 *(\(\frac{9}{10}\): \(\frac{125}{64}\): \(\frac{27}{8}\))
\(4\frac{25}{16}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
KQ là \(-\frac{61}{16}\)
mk ko bít bạn có cần lời giải ko mk chỉ vít kq hoi
có j nếu cần lời giải ns mk ha
\(4\frac{25}{16_{ }}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
=\(\frac{25}{4}+25.\left(\frac{36}{64}-\frac{117}{64}\right):\frac{27}{8}\)
=\(\frac{25}{4}+25.\left(\frac{-81}{64}\right):\frac{28}{7}\)
=\(\frac{25}{4}+\left(\frac{-2025}{64}\right).\frac{7}{28}\)
=\(\frac{25}{4}+\left(\frac{-2025}{256}\right)\)
=\(\frac{1600}{256}-\frac{2025}{256}\)
=\(\frac{-425}{256}\)
bn xem có đúng k nhé!
\(4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{164}\right):\left(\frac{_{-27}}{8}\right)\)
\(=\frac{89}{16}+25.\frac{369}{500}:\left(\frac{-27}{8}\right)\)
\(=\frac{89}{16}+\frac{369}{20}:\left(\frac{-27}{8}\right)\)
\(=\frac{89}{16}+\frac{-82}{15}\)
\(=\frac{23}{240}\)
Thực hiện các phép tính:
a) \(A=4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{64}\right):\frac{-27}{8}\)
b) \(C=\frac{2^3}{3.5}+\frac{2^3}{5.7}+\frac{2^3}{7.9}+...+\frac{2^3}{101.103}\)
a)Ta có:
\(A=4\frac{25}{16}+25\left(\frac{9}{16}:\frac{125}{64}\right):\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+25.\frac{36}{125}:\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+\frac{36}{5}:\frac{-27}{8}\)
\(\Rightarrow A=\frac{89}{16}+\frac{-32}{15}\)
\(\Rightarrow A=\frac{823}{240}\)
Vậy A=.....
b)Ta có:
\(C=\frac{2^3}{3.5}+\frac{2^3}{5.7}+\frac{2^3}{7.9}+...+\frac{2^3}{101.103}\)
\(\Rightarrow C=\frac{2^2.2}{3.5}+\frac{2^2.2}{5.7}+\frac{2^2.2}{7.9}+...+\frac{2^2.2}{101.103}\)
\(\Rightarrow C=2^2\left(\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{101.103}\right)\)
\(\Rightarrow C=4\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{101}-\frac{1}{103}\right)\)
\(\Rightarrow C=4\left(\frac{1}{3}-\frac{1}{103}\right)\)
\(\Rightarrow C=4.\frac{100}{309}\)
\(\Rightarrow C=\frac{400}{309}\)
Vậy C=.....
B, C=2^3/3.5 + 2^3/5.7+......+2^3/101.103
C= 2^3(1/3-1/5+1/5-1/7+....+1/101-1/103)
C=8(1/3-1/103)
C=8.100/309
C=800/309
VẬY C= 800/309
\(4\frac{25}{16}\).25.\(\left(\frac{9}{16}-\frac{117}{64}\right)\): \(\frac{27}{8}\)
\(\frac{5}{16}\): 0.125+1.456: \(\frac{7}{25}\)+\(4\frac{1}{2}\)+0.8
mik làm được mỗi ý b thui :
b ) \(\frac{169}{10}=16,9\)
mik nha
phần đầu bằng -6675/128
phần sau bằng 13
bạn dùng máy tính là được mà
\(4\frac{25}{16}X25\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}=-\frac{6675}{128}=-52,1484375\)
\(\frac{5}{16}:0,125+1,456:\frac{7}{25}+4\frac{1}{2}+0,8=13\)
tÍNH:
a, \(4\frac{25}{16}+25.\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
b, -15,5x20,8+3,5x9,2-15,5x9,2+3,5x20,8
c, \(\frac{5}{16}:0,125+1,456:\frac{7}{25}+4\frac{1}{2}.0,8\)
\(\frac{89}{15}+25\left(\frac{9}{16}-\frac{117}{64}\right):\frac{27}{8}\)
=\(\frac{89}{15}+25(-\frac{81}{64}):\frac{27}{8}\)
=\(\frac{89}{15}+(-\frac{2025}{64}):\frac{27}{8} \)
=\(\frac{89}{15}+(-\frac{75}{8})\)
=\(-\frac{89}{24}\)
\(\frac{89}{15}\)+ 25 \((\) \(\frac{36}{64}\)\(-\)\(\frac{117}{64}\)\()\). \(\frac{8}{27}\)
= \(\frac{89}{15}\)+ 25 \((\)\(\frac{-81}{64}\)\()\)\(\frac{8}{27}\)
= \(\frac{89}{15}\)+ 25 . \((\)\(\frac{-3}{8}\)\()\)
= \(\frac{89}{15}\)+ \(\frac{-75}{8}\)
= \(\frac{-413}{120}\)
Nếu đúng cho mình xin 1 k nhé
Tính \(4\frac{25}{16}\)+25x\(\left(\frac{9}{16}-1\frac{17}{64}\right)\div\frac{27}{8}\)
Đáp án là :\(\frac{17}{48}\)bạn nhé.
LŨY THỪA
Bài 1: Tính
\(1.\frac{16^2}{4^5}\) \(17.\frac{9^3}{81^4}\)
\(2.\frac{4^5}{8^3}\) \(18.\frac{8^4}{4^3}\)
\(3.\frac{16^6}{8^3}\) \(19.\frac{8^4}{2^3}\)
\(4.\frac{32^3}{16^5}\)
\(5.\frac{32^5}{64^6}\)
\(6.\frac{27^5}{9^4}\)
\(7.\frac{9^6}{27^5}\)
\(8.\frac{81^5}{9^6}\)
\(9.\frac{27^4}{81^5}\)
\(10.\frac{81^5}{27^6}\)
\(11.\frac{25^6}{125^3}\)
\(12.\frac{4^7}{8^3}\)
\(13.\frac{8^4}{16^3}\)
\(14.\frac{8^5}{64^3}\)
\(15.\frac{16^6}{8^4}\)
\(16.\frac{8^8}{4^6}\)
\(\frac{1}{5}+\frac{4}{10}+\frac{9}{15}+\frac{16}{20}+\frac{25}{25}+\frac{36}{30}+\frac{49}{35}+\frac{64}{40}+\frac{81}{45}\)=?
\(\frac{1}{5}+\frac{4}{10}+...+\frac{81}{45}=\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+...+\frac{9}{5}=\frac{1+2+3+...+9}{5}=\frac{45}{5}=9\)
1/5 + 4/10 + 9/15 + 16/20 + 25/25 + 36/30 + 49/35 + 64/40 + 81/45
=1/5 + 2/5 + 3/5 + 4/5 + 5/5 + 6/5 + 7/5 + 8/5 + 9/5
=45/5 = 9