tim x biet (x-2)^3 -(x-3)(x^2+3x+9)+6(x+1)^2
Những câu hỏi liên quan
Tim so nguyen x biet:
a,x-(-24)=3
b,(x+5)-(x-9)=x+3
c,c(x+2)=0
d,(x-1)^2=0
e,x^2-3x=0
f,-13-(6-|x+1|)=24
g,26-|x+9|=-13
i,(3x-6).3=3^4
tim x biet (x^2+2x+1)(x+2)-x^2(x-3)-7x(x-1)=3x-9
Tim x, biet:
a)(x-3)^3-(x-3)(x^2+3x+9)+9(x-1)^2=15
b)(x^2-2)^2+4(x-1)^2-4(x^2-2)(x-1)=0
Giup minh voi!
tim x biet
(2x=1)^2 - 4(x=2)^2=9
3(x-1)^2 -3x(x-5)=1
3(x+2)^2+ (2x-1)^2 =7
7(x+3)(x-3)=36
giup mik voi tim x biet
1, 5-(3x+6)>-2x+1
2, -7.(x+2)-3x<6-11x
3, (x+1).(x+2)-x.(x+3)<4-x
4, 6-2x>17+(4-x)
P = \(\frac{3x-9}{x^2-5x+6}-\frac{x+3}{x-2}-\frac{2x+1}{3-x}.\)
a, Ruts gon
b , Tinh P biet x=-1/2
c, tim x de P < 0
d Tim x e Z de P e Z
a) \(P=\frac{3x-9}{x^2-5x+6}-\frac{x+3}{x-2}-\frac{2x+1}{3-x}\)
\(P=\frac{3\left(x-9\right)}{\left(x-3\right)\left(x-2\right)}-\frac{x+3}{x-2}-\frac{2x+1}{3-x}\)
\(P=\frac{3}{x-2}-\frac{x+3}{x-2}-\frac{2x+1}{3-x}\)
\(P=\frac{3\left(3-x\right)-\left(x+3\right)\left(3-x\right)-\left(2x+1\right)\left(x-2\right)}{\left(x-2\right)\left(3-x\right)}\)
\(P=\frac{9-3x-9+x^2-2x^2+4x-x+2}{\left(x-2\right)\left(3-x\right)}\)
\(P=\frac{2-x^2}{\left(x-2\right)\left(3-x\right)}\) (*)
b) Thay \(x=-\frac{1}{2}\) vào (*) ta có:
\(P=\frac{2-\left(-\frac{1}{2}\right)^2}{\left[\left(-\frac{1}{2}\right)-2\right]\left[3-\left(-\frac{1}{2}\right)\right]}=\frac{2-\frac{1}{4}}{-\frac{5}{2}.\frac{7}{2}}=-\frac{\frac{7}{4}}{\frac{5}{2}.\frac{7}{2}}=-\frac{7}{35}=-\frac{1}{5}\)
c) \(\frac{2-x^2}{\left(x-2\right)\left(3-x\right)}< 0\)
\(\Leftrightarrow2-x^2< 0\)
\(\Leftrightarrow-x^2< -2\)
\(\Leftrightarrow x^2>2\)
\(\Leftrightarrow\hept{\begin{cases}x< -\sqrt{2}\\-\sqrt{2}< x< \sqrt{2}\\x>2\end{cases}}\)
Vậy: ...
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Tim xthuoc Z biet:
1,|2x-5|-|2x+9|=0
2,|x+1|-|x+2|-|3-x|=7
3,|2x+3|+|3x+2|-|4-x|=10
Tim x biet
a) \(60\%x+\frac{2}{3}x=\frac{1}{3}.6\frac{1}{3}\)
b) \(3\left(3x-\frac{1}{2}\right)^3+\frac{1}{9}=0\)
a, 60%x + 2/3x =1/3.6 1/3
3/5x +2/3x =1/3.19/3
x.(3/5+2/3)=19/9
x.(9/15+10/15)=19/9
x.19/15=19/9
x=19/9:19/15
x=15/9
Vậy x=15/9
b,3.(3x-1/2)^3 +1/9=0
3.(3x-1/2)^3= -1/9
(3x-1/2)^3= -1/9:3
(3x-1/2)^3= -1/27
(3x-1/2)^3=(-1/3)^3
3x-1/2= -1/3
3x= -1/3-1/2
3x= -2/6+(-3/6)
3x= -5/6
x= -5/6 :3
x=-5/18
Vậy x=-5/18
tim x thuoc Z biet
a,x^2+3x-13 chia het x+3
b,x^2 +3 chia het x-1
c,x-6 chia het x^2-1
a, Ta có:x^2+3x-13=(x^2+3x)-13
=x(x+3)-13
Vì (x+3) chia hết cho (x+3)=>x(x+3) chia hết cho x+3
Để: (x^2+3x-13) chia hết cho x+3 thì 13 phải chia hết cho x+3
=>(x+3) thuộc Ư(13)
Mà Ư(13)={0;13}
=>(x+3) thuộc {0;13}
=> x thuộc {-3;10}
b,c, giống câu a
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