a) 
1990.1990 -1992.1998 = (1995-5)^2 -(1995+3)(1995-3) = -10.1995 +25 +9 = -(19950-34) = -19916 
b) 
ta có
tu = 124 .237 +152 = 122.137 + 474 +152= 122. 137 + 626 
mau = ( 870 + (237-2).122= 870 +122.237 - 244 =122.237 + 626 
=> phân thức đã cho = tử/mẫu = 1

a/ \(=1990.1990-\left(1990+2\right).\left(1990-2\right)=1990.1990-\left(1990.1990-4\right)=4\)

b/ \(=\frac{2.687.57+687.86}{26.13+74.\left(13+1\right)}=\frac{687\left(2.57+86\right)}{26.13+74.13+74}=\frac{687.\left(114+86\right)}{13\left(26+74\right)+74}=\)

\(=\frac{687.200}{13.100+74}=\frac{687.200}{1374}=\frac{687.200}{687.2}=\frac{200}{2}=100\)

c/ \(=\frac{214.237+152}{870+\left(237-2\right).\left(124-2\right)}=\frac{124.237+152}{870+124.237-2.237-2.124+4}=\)

\(=\frac{124.237+152}{124.237+870+4-2.237-2.124}=\frac{124.237+152}{124.237+152}=1\)

cảm ơn nha Nguyễn Ngọc Anh Minh!

bài này dễ mà 

mik đăng cho vui thôi

a)1990*1990-1992*1988=1990*(1988+2)-(1990+2)*1988=1990*1988+2*1990-1990*1988-2*1988=(1990*1988-1990*1988)+(2*1990-2*1988)=0+2*(1990-1988)=2*2=4

b)(1374*57+687*86)/(26*13+74*14)=(687*2*57+687*86)/(26*13+74+74*13)=(687*114+687*86)/(100*13+74)

=(687*200)/1374=137400/1374=100

c)(124*237+152)/(870+235*122)=\(\frac{\left(122+2\right)\cdot237+152}{870+\left(237-2\right)\cdot122}=\frac{122\cdot237+2\cdot237+152}{870-2\cdot122+237\cdot122}=\frac{122\cdot237+626}{626+237\cdot122}=1\)

d)\(\frac{423134\cdot846267-423133}{846267\cdot423133+423134}=\frac{\left(423133+1\right)\cdot846267-423133}{846267\cdot423133+423134}\)

\(=\frac{423133\cdot846267+846267-423133}{846267\cdot423133+423134}=\frac{423133\cdot846267+423134}{846267\cdot423133+423134}=1\)

(mỏi hết cả mắt)

mình lam một phần thôi

\(\frac{42134\times846267-423133}{846267\times423133+423134}=\frac{\left(42133+1\right)\times846267-42133}{846267\times423133+423134}\)

\(=\frac{42133\times846267+846267-42133}{846267\times42133+42134}=\frac{846267\times42133+42134}{846267\times42133+42134}=1\)

423134×846267−423133846267×423133+423134 

1990×1990−1992×1998

(1374.57+687.86):(26.13+74.14)

(124.237+152):(870+235.122)

Vận dụng tính chất để tìm kết quả nhanh chóng 

Giúp mình nha , mk tích cho , mk đang cần gấp

124.237+152 = (122+2)(235+2) + 152 = 122.235 + 2*(122+235) + 4 + 152 = 122.235 + 870

Vậy (124.237+152) : (870 + 235.122) = 1

1990.1990-1992.1998

=1990.1990-(1990+2).1998

=1990.1990-1990.1998+2.1998

=1990.(1990-1998)+2.1998

=1990.(-8)+2.1998

=1990.(-8)+2.(1990+8)

=1990.(-8)+2.1990+16

=1990.{(-8)+2}+16

=1990.(-6)+2.8

=(-1990).3.2+2.8

=-5970.2+2.8

=2.{(-5970)+8}

=2.-5962

=−11924

Bài 1:

a.1990.1990-1992.1988 

Gọi 1990 là a ta có:

1992=a+2

1988=a-2

\(\Rightarrow A=a^2-\left(a+2\right)\left(a-2\right)\)

\(\Rightarrow A=a^2-a^2-2a+2a-4\)

\(\Rightarrow A=-4\)