\(10:\frac{5}{3}\) \(\frac{5}{3}:10\)
\(\frac{9}{22}x\frac{33}{18}=\)\(\frac{12}{35}:\frac{36}{25}=\)\(\frac{19}{17}:\frac{76}{51}=\)
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Bài 1 : Tính a)5+frac{3}{5}b)10-frac{9}{16}c)frac{2}{3}-left(frac{1}{6}+frac{1}{8}right)d)frac{15}{16}:frac{25}{24}e)14xfrac{5}{21}g)frac{5}{3}:10h)10:frac{5}{3}Bài 2 :a)frac{9}{22}xfrac{33}{18}b)frac{12}{35}:frac{36}{25}c)frac{19}{17}:frac{76}{51}
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Bài 1 : Tính
a)\(5+\frac{3}{5}\)
b)\(10-\frac{9}{16}\)
c)\(\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)\)
d)\(\frac{15}{16}:\frac{25}{24}\)
e)\(14x\frac{5}{21}\)
g)\(\frac{5}{3}:10\)
h)\(10:\frac{5}{3}\)
Bài 2 :
a)\(\frac{9}{22}x\frac{33}{18}\)
b)\(\frac{12}{35}:\frac{36}{25}\)
c)\(\frac{19}{17}:\frac{76}{51}\)
bn ra từng câu 1 thui đừng ra nhìu làm chán lém
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10-9/16=91/10
5+3/5=28/5
3/8
9/10
10/3
1/6
50/3
B2
3/4
5/21
51/28
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Bài 2
a)\(\frac{9}{22}x\frac{33}{18}\)
=\(\frac{9}{22}x\frac{11}{6}\)
=\(\frac{3}{4}\)
b)\(\frac{12}{35}:\frac{36}{25}\)
=\(\frac{12}{35}x\frac{25}{36}\)
=\(\frac{5}{21}\)
c)\(\frac{19}{17}:\frac{76}{51}\)
=\(\frac{19}{17}x\frac{51}{76}\)
=\(\frac{3}{4}\)
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Xem thêm câu trả lời
Tính :
a)\(\frac{9}{22}x\frac{33}{18}\)
b)\(\frac{12}{35}:\frac{36}{25}\)
c)\(\frac{19}{17}:\frac{76}{51}\)
Giúp mình với !
Trả lời được tích !
a) \(\frac{9}{22}.\frac{33}{18}=\frac{9.33}{22.18}=\frac{297}{396}=\frac{3}{4}\)
b) \(\frac{12}{35}:\frac{36}{25}=\frac{12}{35}.\frac{25}{36}=\frac{12.25}{35.36}=\frac{300}{1260}=\frac{5}{21}\)
c) \(\frac{19}{17}:\frac{76}{51}=\frac{19}{17}.\frac{51}{76}=\frac{19.51}{17.76}=\frac{969}{1292}=\frac{3}{4}\)
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Xem thêm câu trả lời
mẫu 9/22 x 5/6 = \(\frac{9x5}{10x6}\)= \(\frac{3x3x5}{5x2x3x2}\)= 3/4 ý là trên tử gạch số 3 ở giữa và số 5 giưới mẫu gạch số 5 và 3
a) 9/22 x 33/18 =?
b) 12/35 : 36/25 =?
c) 19/17 : 76/51 = ?
làm như mẫu nha
\(10:\frac{5}{3}\) \(\frac{5}{3}:10\)
\(\frac{12}{35}:\frac{36}{25}=\) \(\frac{19}{17}:\frac{76}{51}=\)
\(6\frac{1}{7}x1\frac{6}{43}=\) \(9\frac{1}{5}:4\frac{3}{5}=\)
10:5/3= 10x3/5=6
5/3:10=5/3x1/10=1/6
12/35:35/25=12/35x25/35=300/1225=12/49
19/17:76/51=19/17x 51/76= 3/4
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\(10:\frac{5}{3}=10x\frac{3}{5}=\frac{30}{5}=6\)
\(\frac{5}{3}:10=\frac{5}{3}x\frac{1}{10}=\frac{5}{30}=\frac{1}{6}\)
\(\frac{12}{35}:\frac{35}{25}=\frac{12}{35}x\frac{25}{35}=\frac{12}{35}x\frac{5}{7}=\frac{12}{7}x\frac{1}{7}=\frac{12}{49}\)
\(\frac{19}{17}:\frac{76}{51}=\frac{19}{17}x\frac{51}{76}=\frac{1}{1}x\frac{3}{4}=\frac{3}{4}\)
Thank you! Chúc bạn học tốt!
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Tính (Theo mẫu):
MẪU\(\frac{9}{10}\times\frac{5}{6}=\frac{9\times5}{10\times6}=\frac{3\times3\times5}{5\times2\times3\times2}=\frac{3}{4}\)\(\frac{3}{4}\)
\(\frac{12}{35}\div\frac{35}{25}\)
\(\frac{9}{22}\times\frac{33}{18}\)
\(\frac{12}{35}:\frac{35}{25}=\frac{12}{35}.\frac{25}{35}=\frac{12.25}{35.35}=\frac{12.5.5}{7.5.7.5}=\frac{12}{49}\)
\(\frac{9}{22}.\frac{33}{18}=\frac{9.33}{22.18}=\frac{9.3.11}{11.2.9.2}=\frac{3}{4}\)
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Tính giá trị biểu thức1.Afrac{1}{5}+frac{3}{17}-frac{4}{3}+left(frac{4}{5}-frac{3}{17}+frac{1}{3}right)-frac{1}{7}+left[frac{-14}{30}right]2.Bleft(frac{5}{8}-frac{4}{12}+frac{3}{2}right)-left(frac{5}{8}+frac{9}{13}right)-left[frac{-3}{2}right]+frac{7}{-15}3.Cfrac{5}{18}+frac{8}{19}-frac{7}{21}+left(frac{-10}{36}+frac{11}{19}+frac{1}{3}right)-frac{5}{8}4.Dfrac{1}{9}-left[frac{-5}{23}right]-left(frac{-5}{23}+frac{1}{9}+frac{25}{7}right)+frac{50}{14}-frac{7}{30}5.Efrac{1}{13}+left(frac{-5}{18}-frac...
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Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
yutyugubhujyikiu
Kiểm tra bài : Nhân, chia số hữu tỉThực hiện phép tính :(1) -frac{3}{2}.frac{7}{10}frac{-3.7}{2.10}frac{-21}{20}(2) frac{-5}{3}.frac{6}{11}frac{-5.6}{3.11}frac{-30}{33}(3) 2frac{1}{3}.left(-1frac{2}{3}right)frac{7}{3}.left(-frac{5}{3}right)frac{7.left(-5right)}{3.3}-frac{35}{9}(4) frac{9}{10}:left(-frac{15}{11}right)frac{9}{10}.left(frac{-11}{15}right)frac{9.left(-11right)}{10.15}-frac{99}{150}-frac{33}{50}(5) left(-1right):frac{3}{8}frac{left(-1right).8}{3}-frac{8}{3}(6) frac{1}{2}.left(-frac{5...
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Kiểm tra bài : Nhân, chia số hữu tỉ
Thực hiện phép tính :
(1) \(-\frac{3}{2}.\frac{7}{10}=\frac{-3.7}{2.10}=\frac{-21}{20}\)
(2) \(\frac{-5}{3}.\frac{6}{11}=\frac{-5.6}{3.11}=\frac{-30}{33}\)
(3) \(2\frac{1}{3}.\left(-1\frac{2}{3}\right)=\frac{7}{3}.\left(-\frac{5}{3}\right)=\frac{7.\left(-5\right)}{3.3}=-\frac{35}{9}\)
(4) \(\frac{9}{10}:\left(-\frac{15}{11}\right)=\frac{9}{10}.\left(\frac{-11}{15}\right)=\frac{9.\left(-11\right)}{10.15}=-\frac{99}{150}=-\frac{33}{50}\)
(5) \(\left(-1\right):\frac{3}{8}=\frac{\left(-1\right).8}{3}=-\frac{8}{3}\)
(6) \(\frac{1}{2}.\left(-\frac{5}{4}\right).\frac{8}{7}=\frac{1.\left(-5\right)}{2.4}.\frac{8}{7}=-\frac{5}{8}.\frac{8}{7}=-\frac{5.8}{8.7}=-\frac{5}{7}\)
(7) \(\frac{-9}{2}.\frac{2}{18}.\frac{1}{7}=\left(-\frac{9}{2}.\frac{2}{18}\right).\frac{1}{7}=\left(-\frac{9.2}{2.18}\right).\frac{1}{7}=-\frac{18}{36}.\frac{1}{7}=-\frac{18.1}{36.7}=-\frac{1}{14}\)
(8) \(\left(\frac{9}{2}-\frac{1}{3}\right).\frac{6}{17}=\left(\frac{27}{6}-\frac{2}{6}\right).\frac{6}{17}=\frac{27-2}{6}.\frac{6}{17}=\frac{25}{6}.\frac{6}{17}=\frac{25.6}{6.17}=\frac{25}{17}\)
(9) \(\left(-\frac{12}{13}:\frac{36}{39}\right).\frac{3}{5}=\left(-\frac{12}{13}.\frac{39}{36}\right).\frac{3}{5}=\left(\frac{-12.39}{13.36}\right).\frac{3}{5}=-\frac{1.3}{5}=-\frac{3}{5}\)
(10) \(\left(-\frac{3}{7}+\frac{7}{9}\right):\frac{4}{7}+\left(-\frac{4}{7}+\frac{2}{9}\right):\frac{4}{7}=\left(\left(-\frac{3}{7}+\frac{7}{9}\right)+\left(-\frac{4}{7}+\frac{2}{9}\right)\right):\frac{4}{7}\)
\(=\left(\left(-\frac{27}{63}+\frac{49}{63}\right)+\left(-\frac{36}{63}+\frac{14}{63}\right)\right):\frac{4}{7}=\left(\left(-\frac{27+49}{63}\right)+\left(\frac{-36+14}{63}\right)\right):\frac{4}{7}\)
\(=\left(\left(\frac{22}{63}\right)+\left(-\frac{22}{63}\right)\right):\frac{4}{7}\)
\(=\frac{22+\left(-22\right)}{63}:\frac{4}{7}=\frac{0}{63}:\frac{4}{7}=0\)
Mình đăng các bài toán này lên thứ nhất là để kiểm tra năng lực thứ hai các bạn có thể xem đây và rút ra lời giải cho các bài khác và nếu mình sai chỗ nào các bạn chỉ mình sẽ chỉnh
Tìm x, biết:
\(x=\left(2-\frac{5}{3}+\frac{7}{6}-\frac{9}{10}+\frac{11}{15}-\frac{13}{21}+\frac{15}{28}-\frac{17}{36}+\frac{19}{45}\right)\times\frac{5}{3}\)
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Tính giá trị biểu thức:
3) C= \(\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)\(\frac{5}{8}\)
4) D= \(\frac{1}{9}-\left|\frac{-5}{23}\right|-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{4}-\frac{7}{30}\)
3) C thiếu đề
4) \(D=\frac{1}{9}-\left|\frac{-5}{23}\right|-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{4}-\frac{7}{30}\)
\(D=\frac{1}{9}-\frac{5}{23}+\frac{5}{23}-\frac{1}{9}-\frac{25}{7}+\frac{50}{4}-\frac{7}{30}\)
\(D=\frac{1}{9}-\frac{1}{9}-\frac{5}{23}+\frac{5}{23}+\frac{-25}{7}+\frac{50}{4}-\frac{7}{30}\)
\(D=0+0+\frac{125}{14}-\frac{7}{30}\)
\(D=\frac{913}{105}\)
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\(C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(C=\frac{5}{18}+\frac{8}{19}-\frac{1}{3}+\frac{-5}{18}+\frac{11}{19}+\frac{1}{3}-\frac{5}{8}\)
\(C=\left(\frac{5}{18}+\frac{-5}{18}\right)+\left(\frac{8}{19}+\frac{11}{19}\right)+\left(\frac{-1}{3}+\frac{1}{3}\right)-\frac{5}{8}\)
\(C=0+1+0-\frac{5}{8}\)
\(C=\frac{3}{8}\)
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