96 - 3 ( x + 1 ) = 42

3 ( x + 1 ) = 54

x + 1 = 18

x = 18 - 1

x = 17

\(96-3\left(x+1\right)=42\)

\(\Leftrightarrow3\left(x+1\right)=96-42\)

\(\Leftrightarrow3\left(x+1\right)=54\)

\(\Leftrightarrow x+1=54\div3\)

\(\Leftrightarrow x+1=18\)

\(\Leftrightarrow x=18-1\)

\(\Leftrightarrow x=17\)

Vậy x=17.

96 - 3 (x + 1) = 42

3 (x+1)=96-42

3 (x+1)=54

x+1=54:3

x+1=18

x=18-1

x=17

c)96 - 3.(x + 1) = 42

3.(x + 1)= 96 - 42

3.(x + 1) = 54

x + 1= 54:3

x + 1= 18

x = 18 - 1

x = 17

Hzh

96 – 3(x + 1) = 42

    3(x + 1) = 96 - 42

    3(x + 1) = 54

    x + 1 = 54:3

    x + 1 = 18

    x = 18 - 1

    x = 17

Vậy x = 17

 96-3.[x+1]=42

=>3.(x+1)=96-42

=> 3.(x+1)=54

=>    x+1=54:3

=>    x+1=18

=>    x    =18-1

=>    x    =17

96 - 3 ( x + 1 ) =42
3 ( x+1) = 42 - 96

3 ( x + 1 ) = 54

x + 1 = 54 : 3

x+1= 18

x = 18 - 1

x = 17

96-3(x+1)=42

3.(x+1)==96-42

x+1=54:3

x=17-1

x=16

96 - 3 ( x + 1 ) =42
3 ( x+1) = 42 - 96

3 ( x + 1 ) = 54

x + 1 = 54 : 3

x + 1 = 18

x = 18 - 1

x = 17

a) nếu tích = 0 => một trong hai số hạng = 0 

nếu x-5=0 => x=5 

nếu x-7=0 => x= 7 

=> x thuộc {5;7}

b)96-3(x+1)=42

3.(x+1)=96-42=54 

x+1=54:3=18 

x=18-1=17 

các bạn cho mk vài li-ke cho tròn 950 với 

(x-5).(x-7)=0

=>x-5=0 =>x=5

hoac   x-7=0=>x=7

96-3.(x+1)=42

3.(x+1)     =96-42=54

  (x+1)      =54/3=18

x              =18-1

x=7

(x-5).(x-7)=0

->x-5=0(hay)(1)

  x-7=0(2)

giải1

x-5=0

->x=0-5=-5

giải2

x-7=0

->x=0-7=-7

->x thuộc{-5,-7}

Vậy x thuoc {-5.-7}

96 - 3 ( x + 1 ) = 42 

3 ( x + 1 ) = 96 - 42 

3 ( x + 1 ) = 54 

x + 1 = 54 : 3

x + 1 = 18

x = 18 - 1

x = 17  

\(96-3\left(x+1\right)=42\)

\(\Rightarrow3\left(x+1\right)=96-42=54\)

\(\Rightarrow x+1=54:3=18\)

\(\Rightarrow x=17\)

96 - 3(x - 1) = 42   

        3(x -1) = 96 - 42

        3(x - 1) = 54

        x - 1      = 54 :3

           x - 1   = 18

         x = 18 + 1

x = 19

\(96-3.\left(x+1\right)=42\)

\(3.\left(x+1\right)=96-42\)

\(3.\left(x+1\right)=54\)

\(x+1=54\div3\)

\(x+1=18\)

\(x=18-1\)

\(x=17\)