398 : a dư 38 =>398-38=360 chia hết cho a

450 : a dư 18 =>450-18=432 chia hết cho a

Điều kiện a thuộc N^*

Ta tìm ƯCLN của 360 và 432:

360=2³.3².5

432=2⁴.3³

Suy ra ƯCLN của 360 và 432 = 2³.3²=8.9=72

Vậy a=72

Zu la la

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Ta c : 

398 : a du 38 

=> 398 - 38 =360 chia het cho a

450 a du 18 

=> 450 - 18 = 432 chia het cho a

Dieu kien a thuoc N*

Ta co UCLN(360;432)

360=2³.3².5

432=2⁴.3³

Suy ra : UCLN(360;432)=2³.3²=71

Vay a=71

**** nhe

72 mà

398 chia a dư 38 => 398-38 = 360 chia hết cho a

450 chia a dư 18 => 450-18 = 432 chia hết cho a 

Với a thuộc N*

Ta có: ƯCLN(360,432) = 72

Vậy a = 72

398 chia cho a dư 38 nên 398 - 38 = 360 chia hết cho a.

450 chia cho a dư 18 nên 450 - 18 = 432 chia hết cho a.

Ta có: 360 = 2³ x 3² x 5

          432 = 2⁴ x 3³

Suy ra: ƯCLN(360,432) = 2³ x 3² = 72 

Vậy a = 72

398 : a dư 38 => 398 - 38 = 360 : a 

450 : a dư 18 => 450 - 18 = 432 chia hết cho a

Điều kiện a thuộc N* 

ta tìm ƯCLN của 360 và 432

360 = 2³ . 3² . 5

432 = 2⁴. 3³

=> ƯCLN của 360 và 432 là: 2³ . 3² = 72

Vậy a = 72 

k mik nha 

72 dung 100%

72 lÀ kq d

Ta có :

+, \(398:a\)( dư 38 )

=> \(398-38⋮a\)

hay \(360⋮a\)

+, \(450:a\)( dư 18 )

=> \(450-18⋮a\)

hay \(432⋮a\)( a \(\in\)N* )

Vậy 360 và 432 chia hết cho a

Ta có

\(360=2^3.3^2.5\)

\(432=2^4.3^3\)

=> ƯCLN ( 360;432 ) là : \(2^3.3^2=72\)

Vậy a = 72