\(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right).462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{13}+...+\frac{1}{19}-\frac{1}{21}\right)\cdot462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\cdot462-x=19\)

\(\frac{10}{231}.462-x=19\)

\(20-x=19\)

\(x=20-19\)

\(x=1\)

Đề abfi sai. Chỗ đó là 19, k phải 29

Bạn biết tính chất này không?

\(\frac{a}{n\left(n+a\right)}=\frac{1}{n}-\frac{1}{n+a}\)

Sử dụng tính chất đó thì được:

\(\left(\frac{2}{11}-\frac{2}{13}+\frac{2}{13}-\frac{2}{15}+...+\frac{2}{19}-\frac{2}{21}\right)\)x 462 - x =19

\(\left(\frac{2}{11}-\frac{2}{21}\right)\cdot462-x=19\)

\(\frac{924}{11}-\frac{924}{21}-x=19\)

84 - 44 - x =19

40 - x = 19

x = 40 - 19

x = 21

Nhớ tk cho mình nếu đúng nhé

\(\left(\frac{2}{11.13}+\frac{2}{13.15}+.....+\frac{2}{19.21}\right).462-x=19\)

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+......+\frac{1}{19}-\frac{1}{21}\right).462-x=19\)

\(\Leftrightarrow\left(\frac{1}{11}-\frac{1}{21}\right).462-x=19\)

\(\Leftrightarrow\frac{10}{231}.462-x=19\)

\(\Leftrightarrow20-x=19\)

\(\Leftrightarrow x=20-19\)

\(\Leftrightarrow x=1\)

ta lấy : (1/11-1/13+1/13-1/15+...+1/19)x462-y=19

                (1/11-1/19)x462-y=19

                  32/209x462-y=19

                      70,73-y=19

                         y=70,73-19=51,73

đúng thì k cho mình nhé , ko đúng cũng ko sao ^^

\(\left(\frac{2}{11x13}+\frac{2}{13x15}+\frac{2}{15x17}+\frac{2}{17x19}+\frac{2}{19x21}\right)\)) x 462 - y = 19

\(=\left(\frac{13-11}{11x13}+\frac{15-13}{13x15}+\frac{17-15}{15x17}+\frac{19-17}{17x19}+\frac{21-19}{19x21}\right)\)x 462 - y = 19

\(=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\)) x 462 - y = 19

\(=\left(\frac{1}{11}-\frac{1}{21}\right)\)x 462 - y = 19

\(=\left(\frac{21}{231}-\frac{11}{231}\right)\)x 462 - y = 19

\(=\frac{10}{231}\)x 462 - y = 19

\(=20\)- y = 19

                y = 20 - 19

                y = 1

Mình làm bài này rồi

Đúng đó

Bài này có trong violympic

thanks pro

bạn @nguyentrinhnganthanh cố giúp mik nha

1. \(\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+\frac{2}{17.19}+\frac{2}{19.21}\right)\times462-x=19\)

\(\left(\frac{13-11}{11.13}+\frac{15-13}{13.15}+\frac{17-15}{15.17}+\frac{19-17}{17.19}+\frac{21-19}{19.21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+\frac{1}{17}-\frac{1}{19}+\frac{1}{19}-\frac{1}{21}\right)\times462-x=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right)\times462-x=19\)

\(\frac{10}{231}\times462-x=19\)

\(20-x=19\)

\(x=20-19\)

\(x=1\)

2.b \(187-[[497-(8\times x+11)\div x]\div3-78]=150\)

​​\(187-[[497-(\frac{8\times x}{x}+\frac{11}{x})]:3-78]=150\)

\(187-[(497-8-\frac{11}{x}):3-78]=150\)

\(187-[(489-\frac{11}{x}):3-78]=150\)

\(187-[\frac{489}{3}-\frac{33}{x}-78]=150\)

\(187-[163-\frac{33}{x}-78]=150\)

\(187-85+\frac{33}{x}=150\)

\(102+\frac{33}{x}=150\)

\(\frac{33}{x}=150-102\)

\(\frac{33}{x}=48\)

\(x=\frac{48}{33}=\frac{16}{11}\)

(1/11-1/13+1/13-1/15+.....+1/19-1/21)*462-y=19

(1/11-1/21)*462-y=19

10/231*462-y=19

20-y=19

y=1

đáp án là 1

k cho mk nha

là 1

khỏi cần ai giúp nữa nhưng k cho mình nhé

k cho mình