theo đề bài, ta có:

-x/2=3y/4 = -5z/6

mà -x/2= -5x/10

=> -5x/10 = 3y/4 = -5z/6

=> -5x/10 . 1/3= 3y/4 . 1/3 = -5z/6 . 1/3

=> -5x/30 = 3y/12 = -5z/18

=> -5x/30 = y/ 4= -5z/ 18

mà y/4 = 4y/ 16

=> -5x/30 = 4y/16 = -5z/18

theo t/c của dãy tỉ số bàng nhau, ta có

- 5z-(-5x) +4y/ 18- 30 +16 = -(5z - 5x -4y)/ 4 = - 50/4 = -25/2

=> -x2 : 2= ... ( tương tự với y, z)

vậy x= ... y=... z=...

p/s bạn viết lại ra giấy cho dễ hiểu

hơi rối, mình ko viết đc ps
 

A ) x = 5/24

B ) x = 7/15

\(\frac{4}{\frac{2}{5}}:\left(-\frac{33}{10}\right)+x=-\frac{1}{\frac{5}{6}}\)

\(10:\left(-\frac{33}{10}\right)+x=-\frac{6}{5}\)

\(-\frac{100}{33}+x=-\frac{6}{5}\)

\(x=\frac{302}{165}\)

\(\frac{1}{6}=\frac{x}{18}\Rightarrow x=3\)

\(\frac{x}{8}=-\frac{1}{4}\Rightarrow x=-2\)

\(\frac{4}{-5}=\frac{x}{10}\Rightarrow x=-8\)

\(\frac{11}{5}=-\frac{22}{x}\Rightarrow x=-10\)

\(\frac{x}{8}=\frac{8}{x}\Rightarrow x^2=64\Rightarrow x=8\)

\(\frac{x}{-11}=-\frac{11}{x}\Rightarrow x^2=121\Rightarrow x=11\)

#H

\(\frac{4}{7}x\frac{5}{6}+\frac{5}{7}x\frac{5}{6}\)

\(=\frac{5}{6}x\left(\frac{4}{7}+\frac{5}{7}\right)=\frac{5}{6}x\frac{9}{7}=\frac{45}{42}=\frac{15}{14}\)

\(\frac{1}{2}:3x\frac{1}{2}=\frac{1}{6}x\frac{1}{2}=\frac{1}{12}\)

ai minh cho va minh can gap vao thu 4 tuan nay

2 - 5/6= 7/6

7/8+3/4=`13/8

2/5+3/4=23/20

7/12 - 2/7 + 1/12=8/21

12/17 - 5/17 - 4/17=3/17

a)=7/6

b)=13/8

c)=8/21

d)=3/17

                  HẾT

\(2-\frac{5}{6}=1\frac{1}{6}\)

\(\frac{7}{8}+\frac{3}{4}=1\frac{5}{8}\)

\(\frac{2}{5}+\frac{3}{4}=\frac{23}{20}\)

\(\frac{7}{12}-\frac{2}{7}+\frac{1}{12}=\frac{8}{7}\)

\(\frac{12}{17}-\frac{5}{17}-\frac{4}{17}=\frac{3}{17}\)