Tính :3\(\frac{1}{2}\)+ 4\(\frac{5}{7}-5\frac{5}{14}\)=
Mấy anh chị giúp em với
Những câu hỏi liên quan
Tính : \(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}\)=
\(4\frac{1}{2}+\frac{1}{2}\div5\frac{1}{2}\)=
Mấy bác giúp cho cháu với
câu b trần nhật quỳnh tính sai rồi. Nhân chia trước cộng trừ sau mà
4\(\frac{1}{2}\)+\(\frac{1}{2}\): 5\(\frac{1}{2}\)
=\(\frac{9}{2}\)\(+\)\(\frac{1}{2}\)\(\div\)\(\frac{11}{2}\)
=\(\frac{9}{2}\)\(+\)\(\frac{1}{2}\)\(\times\)\(\frac{2}{11}\)
=\(\frac{9}{2}\)\(+\)\(\frac{1}{11}\)
=\(\frac{101}{22}\)
Đúng 0
Bình luận (0)
\(3\frac{1}{2}=\frac{7}{2};4\frac{5}{7}=\frac{33}{7};5\frac{5}{14}=\frac{75}{14}\)
\(3\frac{1}{2}+4\frac{5}{7}-5\frac{5}{14}\)
\(=\frac{7}{2}+\frac{33}{7}-\frac{75}{14}\)
\(=\frac{49}{14}+\frac{66}{14}-\frac{75}{14}\)
\(=\frac{115}{14}-\frac{75}{14}\)
\(=\frac{40}{14}=\frac{20}{7}\)
Đúng 0
Bình luận (0)
\(4\frac{1}{2}+\frac{1}{2}\div5\frac{1}{2}\)
\(4\frac{1}{2}=\frac{9}{2};5\frac{1}{2}=\frac{11}{2}\)
\(4\frac{1}{2}+\frac{1}{2}\div5\frac{1}{2}\)
\(=\frac{9}{2}+\frac{1}{2}\times\frac{2}{11}\)
\(=5\times\frac{2}{11}\)
\(=\frac{10}{11}\)
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
Tìm x :
\(\left(7\frac{1}{2}\cdot8\frac{3}{70}+8\frac{3}{70}\cdot\frac{9}{4}+\frac{19}{4}\cdot8\frac{3}{70}+5\frac{1}{2}\cdot8\frac{3}{70}\right):x=1126\)
Giúp em với các anh chị , thầy cô ơi em gấp lắm
ta có:
\(\left(7\frac{1}{2}.8\frac{3}{70}+8\frac{3}{70}.\frac{9}{4}+\frac{19}{4}.8\frac{3}{70}+5\frac{1}{2}.8\frac{3}{70}\right):x=1126\)
\(8\frac{3}{70}\left(7\frac{1}{2}+\frac{9}{4}+\frac{19}{4}+5\frac{1}{2}\right):x=1126\)
\(\frac{563}{70}.\left(\frac{15}{2}+7+\frac{11}{2}\right):x=1126\)
\(\frac{563}{70}.20:x=1126\)
\(\frac{1126}{70}:x=1126\)
\(=>x=\frac{1126}{7}:1126\)
\(=>x=\frac{1}{7}\)
cho mình nha các bạn.
Đúng 0
Bình luận (0)
Giúp em bài toán này với các anh chị ơi:
Bài 1: Tính a) \(\frac{1212}{1515}x\frac{2525}{2727}=...........\)
b) \(\frac{14}{27}:\frac{7}{8}x\frac{6}{5}+\frac{3}{10}=.............\)
TÍNH NHANH:
a, \(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)\)
b, \(\left(\frac{-4}{5}+\frac{4}{3}\right)+\left(\frac{-5}{4}+\frac{14}{5}\right)-\frac{7}{3}\)
a, \(6\frac{5}{7}-\left(1\frac{3}{4}+2\frac{5}{7}\right)=6\frac{5}{7}-1\frac{3}{4}-2\frac{5}{7}=6\frac{5}{7}-2\frac{5}{7}-\frac{7}{4}=4-\frac{7}{4}=\frac{16}{4}-\frac{7}{4}=\frac{9}{4}\)
b, (-4/5+4//3)+(-5/4+14/5)-7/3 = -4/5+4/3+-5/4+14/5-7/3=(-4/5+14/5)+(4/3-7/3)+-5/4=2+(-1)+-5/4=1+-5/4=-1/4
Phần b dấu ''/'' là dấu phần nha , mk viết ra phân số thì nó dài quá nên mk viết vậy , t.i.c.k mk hennnn ^^ thanks @@
Nếu thích kb qua face vs mk nick : Akiko Ayano nhé . Kb và ib nch vs nhau nè
Đúng 0
Bình luận (0)
15 tháng 1 2020 lúc 23:18
tính :
\(Q=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).203\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
"ai giúp mình bài tính tổng này với .Trả lời rõ ra nhé : \(1\frac{2}{3}+4\frac{3}{5};\)
\(2\frac{5}{12}+3\frac{4}{9};\frac{7}{31}+\frac{14}{29}+\frac{27}{31};8\frac{3}{19}+7\frac{12}{19}+1\frac{4}{19};12\frac{3}{5}+\frac{17}{24}+\frac{7}{5};4\frac{2}{3}+2\frac{1}{5}+2\frac{2}{3}+3\frac{3}{5}\)
Tính (Tính nhanh nếu có thể)a,7frac{3}{4}:5-15.0,025+frac{3}{14}.left(-0,7right)b,frac{-11}{5}+frac{5}{17}.left(6frac{1}{3}-5frac{1}{5}right)-1frac{11}{15}c,frac{-3}{7}.frac{5}{9}+frac{4}{9}.frac{-3}{7}2frac{3}{7} là +d,0,5.1frac{1}{3}.75%:frac{2}{5}+frac{3}{5}e,left(frac{2}{3}+frac{2}{7}-frac{1}{14}right):left(-1-frac{3}{7}+frac{3}{28}right)
Đọc tiếp
Tính (Tính nhanh nếu có thể)
\(a,7\frac{3}{4}:5-15.0,025+\frac{3}{14}.\left(-0,7\right)\)
\(b,\frac{-11}{5}+\frac{5}{17}.\left(6\frac{1}{3}-5\frac{1}{5}\right)-1\frac{11}{15}\)
\(c,\frac{-3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}=2\frac{3}{7}\) = là +
\(d,0,5.1\frac{1}{3}.75\%:\frac{2}{5}+\frac{3}{5}\)
\(e,\left(\frac{2}{3}+\frac{2}{7}-\frac{1}{14}\right):\left(-1-\frac{3}{7}+\frac{3}{28}\right)\)
1. Tính hợp lý:
\(A=\left(\frac{-4}{5}+\frac{4}{3}\right)+\left(\frac{-5}{4}+\frac{14}{5}\right)-\frac{7}{3}\)
\(C=\frac{-5}{7}.\frac{2}{11}+\frac{-5}{7}.\frac{9}{14}+1\frac{5}{7}\)
\(A=\left(\frac{-4}{5}+\frac{4}{3}\right)+\left(\frac{-5}{4}+\frac{14}{5}\right)-\frac{7}{3}\)
\(A=\frac{-4}{5}+\frac{4}{3}+\frac{-5}{4}+\frac{14}{5}-\frac{7}{3}\)
\(A=\left(\frac{-4}{5}+\frac{14}{5}\right)+\left(\frac{4}{3}-\frac{7}{3}\right)+\frac{-5}{4}\)
\(A=2+\left(-1\right)+\frac{-5}{4}\)
\(A=\frac{-1}{4}\)
Đúng 0
Bình luận (0)
A=\(\left(\frac{-4}{5}+\frac{4}{3}\right)+\left(\frac{-5}{4}+\frac{14}{5}\right)-\frac{7}{3}\)\(\frac{7}{3}\)
=\(\frac{-4}{5}+\frac{4}{3}+\frac{-5}{4}+\frac{14}{5}+\frac{-7}{3}\)=\(\left(\frac{-4}{5}+\frac{14}{5}\right)+\left(\frac{4}{3}+\frac{-7}{3}\right)+\frac{-5}{4}\)
=\(\frac{10}{5}+\frac{-3}{3}+\frac{-5}{4}\)=\(2-1+\frac{-5}{4}\)=\(1+\frac{-5}{4}\)=\(\frac{4}{4}+\frac{-5}{4}\)=\(\frac{4-5}{4}\)=\(\frac{-1}{4}\)
Đúng 0
Bình luận (0)
\(A=\left(\frac{-4}{5}+\frac{4}{3}\right)+\left(\frac{-5}{4}+\frac{14}{5}\right)-\frac{7}{3}\)
\(=\frac{-4}{5}+\frac{4}{3}+\frac{-5}{4}+\frac{14}{5}-\frac{7}{3}\)
\(=\frac{-4}{5}+\frac{14}{5}+\frac{4}{3}-\frac{7}{3}+\frac{14}{5}\)
\(=-2-1+\frac{14}{5}\)
\(=\frac{14}{5}-\frac{15}{5}\)
\(=\frac{-1}{5}\)
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
1. Tính nhanh:
a) 7/12 . 6/11 + 7/12 . 5/11 - \(2\frac{7}{12}\)
b) -5/9 . -6/13 + 5/-9 . -5/13 - 5/9
c) 0,8 . -15/14 - 4/5 . 13/14 - \(1\frac{2}{5}\)
d) -75% . 6/7 + 5% . 6/7 + 7/10 . \(1\frac{1}{7}\)
Mọi người giúp em với ạ🥺 Em cảm ơn nhoéee:3
a)\(\frac{7}{12}.\frac{6}{11}+\frac{7}{12}.\frac{5}{11}-2\frac{7}{12}\)
\(=\frac{7}{12}.\left(\frac{6}{11}+\frac{5}{11}\right)-\frac{31}{12}\)
\(=\frac{7}{12}-\frac{31}{12}\)
\(=-2\)
b)\(\frac{-5}{9}.\frac{-6}{13}+\frac{5}{-9}.\frac{-5}{13}-\frac{5}{9}\)
\(=\frac{5}{9}.\left(\frac{6}{13}+\frac{5}{13}-1\right)\)
\(=\frac{5}{9}.\left(\frac{11}{13}-\frac{13}{13}\right)\)
\(=\frac{5}{9}.\frac{-2}{13}\)
\(=-\frac{10}{117}\)
c)\(0,8.\frac{-15}{14}-\frac{4}{5}.\frac{13}{14}-1\frac{2}{5}\)
\(=\frac{4}{5}.\frac{-15}{14}-\frac{4}{5}.\frac{13}{14}-\frac{7}{5}\)
\(=\frac{4}{5}.\left(-\frac{15}{14}-\frac{13}{14}\right)-\frac{7}{5}\)
\(=\frac{4}{5}.\left(-2\right)-\frac{7}{5}\)
\(=\frac{-8}{5}-\frac{7}{5}\)
\(=-3\)
d)\(-75\%.\frac{6}{7}+5\%.\frac{6}{7}+\frac{7}{10}.1\frac{1}{7}\)
\(=\frac{-15}{20}.\frac{6}{7}+\frac{1}{20}.\frac{6}{7}+\frac{7}{10}.\frac{8}{7}\)
\(=\frac{6}{7}.\left(\frac{-15}{20}+\frac{1}{20}\right)+\frac{4}{5}\)
\(=\frac{6}{7}.\frac{-7}{10}+\frac{4}{5}\)
\(=-\frac{3}{5}+\frac{4}{5}\)
\(=\frac{1}{5}\)
Linz