tap hop cac so nguyen x thoa man |x-22| -33=-20
tap hop cac so nguyen x thoa man |x+2| = 10
tap hop cac so nguyen x thoa man |x+2|=10
Nếu x + 2 = 10
=> x = 10 - 2 = 8
Nếu x + 2 = -10
=>x = -10 - 2 = -12
Vậy x = 8 ; -12
Nếu x + 2 = 10
=> x = 10 - 2 = 8
Nếu x + 2 = -10
=>x = -10 - 2 = -12
Vậy x thuộc {8; -12}
x=-12 hoặc 8
đúng không ? k cho mình nhé.
tap hop cac so nguyen x thoa man 15-|x-2|=12
Tap hop cac so nguyen x thoa man : |7-x|=|x+3| la
TH1:|7-x|=|x+3|
=>7-x=x+3
-x-x=3-7
-2x =-4
x = \(\frac{-4}{-2}\)
x = 2
TH2:|7-x|=|3+x|
=> 7-x =-(x+3)
7-x =-x-3
-x+x =-3-7
0 =-10 (sai)
=>x =2
tap hop cac so nguyen x thoa man -3 x |2x - 3 |= -12
tap hop cac so nguyen x thoa man 15-/x-2\=12 la
15- |x - 2| = 12
|x - 2| = 3
x - 2 = 3 => x= 5
x - 2= -3 => x = -1
{-1 ; 5}
Tap hop cac so nguyen x thoa man /+2/ = 10 la
tap hop cac so nguyen x thoa man 45-|-27- ( -25) -x | = -7 +27
45 - |-27 - (-25) - x| = -7 + 27
=> |-27 + 25 - x| = 45 - (-7 + 27)
=> |-2 - x| = 25
+) -2 - x = 25 => x = -2 - 25 = -27
+) -2 - x = -25 => x = -2 - (-25) = 23
Vậy x thuộc {-27; 23}.
tap hop tat ca cac so nguyen x thoa man ( 2- x ).(x+7) = 0
\(\orbr{\begin{cases}2-x=0\\x+7=0\end{cases}}\)
\(\orbr{\begin{cases}x=0+2\\x=0-7\end{cases}}\)
\(\orbr{\begin{cases}x=2\\x=-7\end{cases}}\)
rồi kết luận nhé bạn
\(\Leftrightarrow\orbr{\begin{cases}2-x=0\\x+7=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-7\end{cases}}\)
Vay.........
\(\left(2-x\right)\left(x+7\right)=0\)
\(\Rightarrow\orbr{\begin{cases}2-x=0\\x+7=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2\\x=-7\end{cases}}\)
Vậy\(x\in\left\{-7;2\right\}\)