So sánh: A= \(\frac{9}{a^{2009}}\)+ \(\frac{7}{a^{2008}}\)và B=\(\frac{8}{a^{2008}}\)+ \(\frac{8}{a^{2009}}\)(a thuộc N sao)
So sánh : A=9/a^2009+7/a^2008 và B=8/a^2008+8/a^2009 ( với a€N*)
A= \(\frac{9+7a}{a^{2009}}\)
B= \(\frac{8+8a}{a^{2009}}\)
So sánh tử số : A :9+7a = 8+8a-(a-1)
B :8+8a
Vậy A<B
So sánh A và B biết \(A=\frac{2006}{2007}-\frac{2007}{2008}+\frac{2008}{2009}-\frac{2009}{2010};B=\frac{1}{2006.2007}-\frac{1}{2008.2009}\)
so sánh 2 phân số : \(A=\frac{2008^{2009}+2}{2008^{2009}-1};B=\frac{2008^{2009}}{2008^{2009}-3}\)
So sánh : \(A=\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}vàB=\frac{2008+2009+2010}{2009+2010+2011}\)
So sánh : A=\(\frac{2008}{2009}\)+\(\frac{2009}{2010}\)+\(\frac{2010}{2011}\)và B=\(\frac{2008+2009+2010}{2009+2010+2011}\)
\(B=\frac{2008+2009+2010}{2009+2010+2011}\)
\(=\frac{2008}{2009+2010+2011}+\frac{2009}{2009+2010+2011}+\frac{2010}{2009+2010+2011}\)
\(< \frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}=A\)
\(B=\frac{2008+2009+2010}{2009+2010+2011}\)
\(=\frac{2008}{2009+2010+2011}=\frac{2009}{2009+2010+2011}=\frac{2010}{2009+2010+2011}\)
\(< A=\frac{2008}{2009}+\frac{2009}{2010}+\frac{2010}{2011}\)
so sánh A và B biết : A=9/a^2009+7/a^2008; B= 8/a^2008+8/a^2009
A=\(\frac{2006}{2007}-\frac{2007}{2008}+\frac{2008}{2009}-\frac{2009}{2010}\)
B=\(\frac{-1}{2006.2007}-\frac{1}{2008.2009}\)
Bài 1: Cho a;b;m \(\in\)N*
So sánh \(\frac{a+m}{b+m}\)và \(\frac{a}{b}\)
Bài 2: So sánh
a/ \(\frac{2009^{2008}+1}{2009^{2009}+1}\)và \(\frac{2009^{2007}+1}{2009^{2008}+1}\)
b/ \(\frac{7^{58}+2}{7^{57}+2}\)và \(\frac{7^{57}+2009}{7^{56}+2009}\)
Bài 2: Cho
A=\(\frac{m^{2008}+1}{m^{2009}+1}\)
B=\(\frac{m^{2009}+1}{m^{2010}+1}\)(m \(\in\)N*)
So sánh A và B
So sánh : \(A=\frac{2006}{2007}+\frac{2007}{2008}+\frac{2008}{2009}+\frac{2009}{2006}\)với 4
ta có: \(A=\frac{2006}{2007}+\frac{2007}{2008}+\frac{2008}{2009}+\frac{2009}{2006}\)
A = \(1-\frac{1}{2007}+1-\frac{1}{2008}+1-\frac{1}{2009}+1+\frac{3}{2006}\)
A= \(4\)\(+\frac{3}{2006}-\left(\frac{1}{2007}+\frac{1}{2008}+\frac{1}{2009}\right)\)
Do 1/2007 < 1/2006 ; 1/2008<1/2006 ; 1/2009<1/2006=> 1/2007 + 1/2008 + 1/2009 < 1/2006 + 1/2006 + 1/2006
Mà 1/2006 + 1/2006 + 1/2006 = 3/2006
=> 3/2006 -( 1/2007 + 1/2008 + 1/2009) > 0
=> \(4+\frac{3}{2006}-\left(\frac{1}{2007}+\frac{1}{2008}+\frac{1}{2009}\right)>4\)
=> A > 4
Ta có:\(\frac{2006}{2007}< 1\)
\(\frac{2007}{2008}< 1\)
\(\frac{2008}{2009}< 1\)
\(\frac{2009}{2006}>1\)\(\frac{2006}{2007}+\frac{2007}{2008}+\frac{2008}{2009}+\frac{2009}{2006}< 4\)
Mk chưa thấy ai làm bài sai như thế đấy lỗi đó thì hs lớp 4 cũng phát hiện ra