x = 28 / 87

Kết quả bằng 28 / 87

lời giải đàng hoàng chứ

\(\left(\frac{505}{707}+\frac{222}{333}\right)\)x=\(\frac{404}{909}\)

\(\left(\frac{5}{7}+\frac{2}{3}\right)\)x=\(\frac{4}{9}\)

\(\left(\frac{15}{21}+\frac{14}{21}\right)\)x=\(\frac{4}{9}\)

\(\frac{29}{21}\)x=\(\frac{4}{9}\)

x=\(\frac{4}{9}:\frac{29}{21}\)

x=\(\frac{4}{9}.\frac{21}{29}\)

x=\(\frac{28}{87}\)

Vậy x=\(\frac{28}{87}\)

k mình nha bạn

\(M=\frac{7}{4}\times\left(\frac{3333}{1212}+\frac{3333}{2020}+\frac{3333}{3030}+\frac{3333}{4242}+\frac{3333}{5656}\right)\)

\(M=\frac{7}{4}\times\left(\frac{11}{4}+\frac{33}{20}+\frac{11}{10}+\frac{11}{14}+\frac{33}{56}\right)\)

\(M=\frac{7}{4}\times\left(\frac{33}{12}+\frac{33}{20}+\frac{33}{30}+\frac{33}{42}+\frac{33}{56}\right)\)

\(M=\frac{7}{4}\times\left(\frac{33}{3.4}+\frac{33}{4.5}+\frac{33}{5.6}+\frac{33}{6.7}+\frac{33}{7.8}\right)\)

\(M=\frac{7}{4}\times\left[33\cdot\left(\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}\right)\right]\)

\(M=\frac{7}{4}\times\left[33\times\left(\frac{1}{3}-\frac{1}{8}\right)\right]\)

\(M=\frac{7}{4}\times\left(33\times\frac{5}{24}\right)=\frac{7}{4}\times\frac{55}{8}=\frac{385}{32}\)

Ta có : \(\frac{1717}{808}\)= \(\frac{17}{8}\)= \(\frac{119}{56}\)và \(\frac{1313}{707}\)=\(\frac{13}{7}\)=\(\frac{104}{56}\)

Vậy \(\frac{1717}{808}\)=\(\frac{1313}{707}\)

\(D=\frac{202202}{1212}+\frac{202202}{2020}+\frac{202202}{3030}+\frac{202202}{4242}+\frac{202202}{5656}\)

\(D=\frac{2002.101}{101.12}+\frac{2002.101}{20.101}+\frac{2002.101}{30.101}+\frac{2002.101}{42.101}+\frac{2002.101}{56.101}\)

\(D=\frac{2002}{12}+\frac{2002}{20}+\frac{2002}{30}+\frac{2002}{42}+\frac{2002}{56}\)

\(D=\frac{1001}{6}+\frac{1001}{10}+\frac{1001}{15}+\frac{143}{3}+\frac{143}{4}\)

\(D=\frac{5005}{12}\)

đáp án là 5005/12 nhé bạn

tích cho mik nha

\(Rút\)\(gọn:\)\(\frac{1001}{6}+\frac{1001}{10}+\frac{1001}{15}+\frac{143}{3}+\frac{143}{4}\)

\(=\frac{1001}{3}+\frac{1001}{12}=\frac{5005}{12}\)

x = 4242