\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+....+\frac{1}{2048}\)
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{2048}\)
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{2048}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-...-\frac{1}{2048}+\frac{1}{2048}\)
\(=1-\frac{1}{2048}\)
\(=\frac{2047}{2048}\)
k mk nha
Đặt A = 1/21 + 1/22 + 1/23 + 1/24 +... +1/211
2A = (1/21 + 1/22 + 1/23 + 1/24 +... +1/211).2
2A = 1 + 1/2 +1/22 + ...+ 1/210
2A - A = ( 1 + 1/2 +1/22 + ...+ 1/210 ) - (1/21 + 1/22 + 1/23 + 1/24 +... +1/211)
A = 1 - 1/211
A = 1 - 1/2048
A = 2047/2048
NHA CÁC BẠN ^_^
Đặt S = 1/2 + 1/4 + 1/8 + 1/16 + ... + 1/2048
2.S = 1 + 1/2 + 1/4 + 1/8 + ... + 1/2048
2.S - S = ( 1 + 1/2 + 1/4 + 1/8 + ... + 1/2048 ) - ( 1/2 + 1/4 + 1/8 + 1/16 + ... + 1/2048 )
S = 1 - 1/2048
S = 2047/2048
Tính giá trị biểu thức : \(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+..............+\frac{1}{1024}+\frac{1}{2048}=\)
Giúp mình với !!!!!!!!!!!!!!!!
A=1/2+1/4+1/8+1/16+...+1/2048
2A=1+1/2+1/4+1/1/8+...+1/1024
2A-A=(1+1/2+...+1/1024)-(1/2+1/4+...+1/2048)
A=1-1/2048
A=2047/2048
Tinhs tổng sau:
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{2048}\)
(Nhập kết quả là phân số tói giản)
Đặt: \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{2048}\)
\(\Rightarrow A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+....+\frac{1}{2^{11}}\)
\(\Rightarrow2A=2\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+....+\frac{1}{2^{11}}\right)\)
\(=1+\frac{1}{2}+\frac{1}{2^2}+.....+\frac{1}{2^{10}}\)
\(\Rightarrow2A-A=\left(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{10}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{11}}\right)\)
\(\Rightarrow A=1-\frac{1}{2^{11}}=\frac{2^{11}-1}{2^{11}}=\frac{2047}{2048}\)
\(2A=1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}\)
\(2A-A=\left(1+...+\frac{1}{1024}\right)-\left(\frac{1}{2}+...+\frac{1}{2048}\right)\)
\(A=1-\frac{1}{2048}=\frac{2047}{2048}\)
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+....+\frac{1}{2048}\)
\(=\left(1+\frac{1}{2}+\frac{1}{4}+....+\frac{1}{2048}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{2048}\right)\)
\(=1-\frac{1}{2048}\)
\(=\frac{2047}{2048}\)
Tính nhanh:
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+...+\frac{1}{1024}+\frac{1}{2048}\)
Nhớ trình bày cách làm đầy đủ nhé!
Ai đunhs và nhanh nhất mình cho 1 tick.
gọi biểu thức là A
A=1/2+1/4+1/8+...+1/2048=1/2+1/2^2+1/2^3+...+1/2^10
=>2A=1+1/2+1/2^2+...+1/2^9
=>A=2A-A(bạn đặt cột dọc ra rồi sẽ thấy:1/2-1/2=0;1/2^2-1/2^2=0;...)Ta được kết quả bằng 1+1/2^10
Đặt A =1/2 + 1/4 + 1/8 + ...+ 1/1024 + 1/2048
A= 1/2 + 1/2^2 + 1/2^3+...+ 1/2^10 + 1/2^11
2A= 1 +1/2 + 1/2^2 +...+ 1/2^9 + 1/2^10
2A-A= (1 +1/2 + 1/2^2 +...+ 1/2^9 + 1/2^10) - (1/2 + 1/2^2 + 1/2^3+...+ 1/2^10 + 1/2^11)
A= 1+1/2 + 1/2^2 +...+ 1/2^9 + 1/2^10 - 1/2 - 1/2^2 - 1/2^3 - ...- 1/2^10 - 1/2^11
A= 1- 1/2^11
A= 2047/ 2048
Đặt \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+...+\frac{1}{1024}+\frac{1}{2048}\)
\(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+...+\frac{1}{512}+\frac{1}{1024}\)
\(2A-A=1-\frac{1}{2048}\)
\(A=\frac{2047}{2048}\)
Tính :\(\frac{1}{2}\)+ \(\frac{1}{4}\)+ \(\frac{1}{8}\)+ \(\frac{1}{16}\)+ ... + \(\frac{1}{2048}\)
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{2048}\)
\(=1-\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{2048}\)
\(=1-\frac{1}{2048}\)
\(=\frac{2047}{2048}\)
NHận xét :
1/2 = 1 - 1/2
1/4 = 1/2 - 1/4
1/8 = 1/4 - 1/8
...................
1/2048 = 1/1024 - 1/2048
Vậy 1/2 + 1/4 + 1/8 + ... + 1/2048
= 1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + ... - ... + 1/1024 - 1/2048
= 1 - 1/2048 = 2047/2048
\(\frac{1}{2}\)\(+\)\(\frac{1}{4}\)\(+\)\(\frac{1}{8}\)\(+\)\(\frac{1}{16}\)...\(+\)\(\frac{1}{2048}\)
\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+..+\frac{1}{2048}\)
\(=1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+..+\frac{1}{2048}\)
\(=1-\frac{1}{2048}\)
\(=\frac{2047}{2048}\)
Ta có:
1/2 = 1 - 1/2
1/4 = 1/2 - 1/4
1/8 = 1/4 - 1/8
…
1/2048 = 1/1024 - 1/2048
Suy ra:
1/2 + 1/4 + 1/8 + ... + 1/2048
= 1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + ... - 1/1024 + 1/1024 - 1/2048
= 1 - 1/2048
= 2047/2048
k mình nha
\(\frac{1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}}{1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\frac{1}{16}}\)
31/11 nhen bạn bấm may tính ra liền
A= -1 - \(\frac{1}{2}\) - \(\frac{1}{4}\) - \(\frac{1}{8}\) - ... - \(\frac{1}{2048}\)
Ta có:
1/2=1—1/2
1/4=1/2—1/4
…………
1/1024—1/2048=1/2048
»» ......bạn tự làm nốt nhé
\(\frac{1}{1-x}+\frac{1}{1+x}+\frac{2}{1+x^2}+\frac{4}{1+x^4}+\frac{8}{1+x^8}+\frac{16}{1+x^{16}}\)