=2/11+2/13-2/13+2/15-2/15+...-2/97+2/98

=2/11+(2/13-2/13+2/15-2/15+...-2/97+2/99)

=2/11+2/99

=20/99

\(\frac{2}{11}\times13+\frac{2}{13}\times15+\frac{2}{15}\times17+........+\frac{2}{97}\times99\)

\(A\times2=\frac{2}{11\times13}+\frac{2}{13\times15}+\frac{2}{15\times17}+........+\frac{2}{97\times99}\)

\(A\times2=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+........+\frac{1}{97}-\frac{1}{99}\)

\(A=\frac{1}{11}-\frac{1}{99}\)

\(A=\frac{8}{99}\)

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\(\frac{4}{9\times11}+\frac{4}{11\times13}+\frac{4}{13\times15}+...+\frac{4}{95\times97}+\frac{4}{97\times99}\)

\(=2\times\left(\frac{2}{9\times11}+\frac{2}{11\times13}+\frac{2}{13\times15}+...+\frac{2}{95\times97}+\frac{2}{97\times99}\right)\)

\(=2\times\left(\frac{11-9}{9\times11}+\frac{13-11}{11\times13}+\frac{15-13}{13\times15}+...+\frac{97-95}{95\times97}+\frac{99-97}{97\times99}\right)\)

\(=2\times\left(\frac{1}{9}-\frac{1}{11}+\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{95}-\frac{1}{97}+\frac{1}{97}-\frac{1}{99}\right)\)

\(=2\times\left(\frac{1}{9}-\frac{1}{99}\right)=\frac{20}{99}\)

4/9x11 + 4/11x13 + 4/13X15 + .............+ 4/95X97 + 4/97X99

=2 x (2/9x11 + 2/11x 13 + .........+2/95x97 + 2/97x99)

=2 x ( 1/9 - 1/11 + 1/11- 1/13 +...... + 1/97 - 1/99)

=2 x (1/9 - 1/99)

=2 x10/99

=20/99

Học tốt!

A=\(\frac{4}{11}-\frac{4}{13}+\frac{4}{13}-\frac{4}{15}+...+\frac{4}{99}-\frac{4}{101}\)

\(A=4\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{99}-\frac{1}{101}\right)\)

\(A=4.\left(\frac{1}{11}-\frac{1}{101}\right)\)

A=4. 90/1111=360/1111

Co dung khong vay Cuong Lucha DT

\(\frac{2}{11x13}+\frac{2}{13x15}+\frac{2}{15x17}+...+\frac{2}{97x99}\)

\(=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{97}-\frac{1}{99}\)

\(=\frac{1}{11}-\frac{1}{99}\)

\(=\frac{8}{99}\)

Ta có:

\(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+...+\frac{2}{97.99}\)

\(=\frac{2}{11}-\frac{2}{13}+\frac{2}{13}-\frac{2}{15}+\frac{2}{15}-\frac{2}{17}+...+\frac{2}{97}-\frac{2}{99}\)

\(=\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{97}-\frac{1}{99}\)

\(=\frac{1}{11}-\frac{1}{99}=\frac{8}{99}\)

Sửa lại đề bài nhé:

\(\frac{2}{11x13}+\frac{2}{13x15}+\frac{2}{15x17}+.........+\frac{2}{97x99}\)

= \(\frac{2}{11}-\frac{2}{13}+\frac{2}{13}-\frac{2}{15}+\frac{2}{15}-\frac{2}{17}+..........+\frac{2}{97}-\frac{2}{99}\)

Sau khi trực tiêu hết ta có:

= \(\frac{2}{11}-\frac{2}{99}\)

= \(\frac{16}{19}\)

8/99 nha bạn

(1/11-1/13+1/13-1/15+.....+1/19-1/21)*462-y=19

(1/11-1/21)*462-y=19

10/231*462-y=19

20-y=19

y=1