*TH1: 2x+3≥ 0 <=> x ≥ -3/2 => 2x+3=x+2 <=> 2x-x=2-3 <=> x=-1(thỏa mãn)

*TH2 :2x+3 <0 <=> x< -3/2 => 2x+3 = -x-2 <=> 3x=-5 <=>x=-5/3 ( thỏa mãn )

Vậy x =(-1;-5/3).

ks cho mik nhé

\(\frac{2}{3}\)

| x - 3 | = | 2x + 1 |

\(\Rightarrow\orbr{\begin{cases}x-3=2x+1\\x-3=-\left(2x+1\right)\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x-2x=1+3\\x+2x=-1+3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}-x=4\\3x=2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-4\\x=\frac{2}{3}\end{cases}}\)

I x - 3 I = I 2x + 1 I   ₍₁₎

Xét \(x< \frac{-1}{2}\)ta co   \(\left(1\right)\Leftrightarrow3-x=-2x-1\Leftrightarrow x=-4\)(thỏa mãn)

Xét  \(\frac{-1}{2}\le x< 3\)ta có \(\left(1\right)\Leftrightarrow3-x=2x+1\Leftrightarrow3x=2\Leftrightarrow x=\frac{2}{3}\)(thỏa mãn)

Xét \(x\ge3\)ta có \(\left(1\right)\Leftrightarrow x-3=2x+1\Leftrightarrow x=-4\)(loại vì \(x\ge3\))

I2x+1/3I+3/4=0

|2x+1/3|=-3/4

TH1:

2x+1/3=-3/4

2x=-3/4-1/3

2x=-13/12

x=-13/12:2

x=-13/24

TH2:

2x+1/3=3/4

2x=3/4-2/3

2x=5/12

x=5/12:2

x=5/24

vậy x=-13/24;5/24