\(C=\frac{3}{1\times4}+\frac{3}{4\times7}+\frac{3}{7\times10}+...+\frac{3}{31\times34}\)

\(=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{31}-\frac{1}{34}\)

\(=1-\frac{1}{34}=\frac{33}{34}\)

99/34

\(C=3-\frac{3}{4}+\frac{3}{4}-\frac{3}{7}+\frac{3}{7}-\frac{3}{10}+...+\frac{3}{31}-\frac{3}{34}\)

\(C=3+\frac{3}{34}=\frac{99}{34}\)

Ta có: \(A=\frac{1}{5}\left(\frac{5}{4.9}+\frac{5}{9.14}+......+\frac{5}{64.69}\right)\)

\(\Rightarrow A=\frac{1}{5}\left(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+......+\frac{1}{64}-\frac{1}{69}\right)\)

\(\Rightarrow A=\frac{1}{5}\left(\frac{1}{4}-\frac{1}{69}\right)=\frac{1}{5}\times\frac{65}{276}\)

\(\Rightarrow A=\frac{13}{276}\)

Vậy \(A=\frac{13}{276}\)

\(A=\frac{1}{4.9}+\frac{1}{9.14}+...+\frac{1}{64.69}\)

\(5A=\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+...+\frac{1}{64}-\frac{1}{69}\)

\(5A=\frac{1}{4}-\frac{1}{69}\)

\(A=\frac{65}{276}:5\)

\(A=\frac{13}{276}\)

\(A=\frac{1}{4.9}+\frac{1}{9.14}+....+\frac{1}{64.69}\)

\(A=\frac{9-4}{1}+\frac{14-9}{9.14}+....+\frac{69-64}{64.69}\)

\(5A=\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+....+\frac{1}{64}-\frac{1}{64}-\frac{1}{69}\)

\(5A=\frac{1}{4}-\frac{1}{69}\)

\(5A=\frac{65}{276}\)

\(A=\frac{65}{276}\div5=\frac{13}{276}\)

8/9 - 6/12 = 8x12/9x12 - 6x9/12x9 = 96/108 - 54/108 = 42/108 = 7/18

Nếu ai bt cách viết PS to thì chỉ mình nhé !!

Thank you , ai đi qua thì k mình nha @@ !!

Cầu xin các bạn , ai k mình mình k lại và kb với mình nhé !! $_$

\(\frac{7}{18}\)

k cho mik đi mik bị âm điểm

8/9 - 6/12 

mẫu chung là 36

= 7/18

nhớ trình bày rõ ràng và giải đúng tớ mới k nha!

\(\frac{100-X+0,5x2}{2}-0,5=0\)

\(\frac{100-X+1}{2}=0,5\)

\(100-X+1=1\)

\(100-X=0\)

\(X=100-0=100\)

\(=\frac{108}{63}+\frac{105}{63}=\frac{108+105}{63}=\frac{213}{63}\)

\(\frac{12}{7}\)-\(\frac{-15}{9}\) = \(\frac{12}{7}\)+ \(\frac{15}{9}\) = \(\frac{108}{63}\)+ \(\frac{105}{63}\)= \(\frac{108+109}{63}\)= \(\frac{217}{63}\)= \(\frac{31}{9}\)

nguyễn thị thu huyền nhầm rồi 217/63 chứ

=\(\frac{217}{63}\)=\(\frac{31}{9}\)

ai k mk

mk k lai cho

a)1.2.3.4...9-1.2.3.4...8-1.2.3.4...8.8

=1.2.3.4...8(9-1-8)

=1.2.3.4...8.0

=0

b)(3.4.2¹⁶)²/11.12³.4¹¹-16⁹=(3.2².2¹⁶)²/11.2¹³.2²²-2³⁶=3².2⁴.2³²/11.2³⁵-2³⁶=3².2²⁶/2³⁵.(11-2)

=3².2³⁶/2³⁵.9=3².2³⁶/2³⁵.3²=2

c)70.(131313/565656+131313/727272+131313/909090

=70.(13/56+13/72+13/90)

=70.39/70=39

d)1/4.9+1/9.14+1/14.19+...+1/64.69

=4/4.9.4+4/9.4.14+4/14.19.4+...+4/64.69.4.

=1/4.(4/4.9+4/9.14+4/14.19+...+4/64.69)

=1/4.(1/4-1/9+1/9-1/14+1/14-1/19+...+1/64-1/69)

=1/4.(1/4-1/69)

=1/4.65/276=65/1104

~~~~~~~~Chúc bạn học giỏi nhé !~~~~~~~~

nhìu thế này sao mà làm nổi

d)\(\frac{1}{3}\times\left(\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{14}+...+\frac{1}{64}-\frac{1}{69}\right)\)

\(\frac{1}{3}\times\left(\frac{1}{4}-\frac{1}{69}\right)\)

\(\frac{1}{3}\times\frac{65}{276}\)

1.\(\frac{456}{461}va\frac{123}{128}\)

Ta có: \(\frac{456}{461}+\frac{5}{461}=1\)

             \(\frac{123}{128}+\frac{5}{128}=1\)

vì \(\frac{5}{461}< \frac{5}{128}\)nên \(\frac{456}{461}>\frac{123}{128}\)

2.\(\frac{53}{57}va\frac{531}{571}\)

Vì \(\frac{53}{57}< 1\)

\(\Rightarrow\frac{53}{57}=\frac{530}{570}< \frac{530+1}{570+1}=\frac{531}{571}\)

\(\Rightarrow\frac{53}{57}< \frac{531}{571}\)

\(y=\frac{1}{x^2+\sqrt{x}}\)

Ta có: x - y = 4 => x = 4 + y 

Thay x = 4 + y vào \(\frac{x-3}{y-2}=\frac{3}{2}\) , ta đc:

\(\frac{4+y-3}{y-2}=\frac{3}{2}\Rightarrow\frac{y+1}{y-2}=\frac{3}{2}\Rightarrow2\left(y+1\right)=3\left(y-2\right)\Rightarrow2y+2=3y-6\Rightarrow y=8\)

=> x = 4 + y = 4 + 8 = 12

Vậy x = 12 , y = 8

còn cách khác ko