A triangle ABC has the height AH = 8 cm corresponding the base BC = 10 cm. What is the length of the base AB of the triangle ABC if the height of CK = 5 cm ()?
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Given a square with the length of one side is 8 cm and a isosceles triangle with the length of its base is 12 cm. If the area of the square is equal to the area of the isosceles triangle then what is the length of the height of the isosceles triangle, in cm?
Given a square with the length of one side is 8cm and an isosceles triangle with the length of its base is 12 cm . If the area of the square equal of the area of the isosceles triangle then is the length of height of the isosceles triangle ?
M.n ơi kb vs mk nha ! Mk là thành viên ms nên chưa có bn !
Girl 2k5 -FA
Give the triangle ABC and the bisector BD, AB = 5cm, CB = 7cm. If the length of AD is 1cm less than the length of CD then the length of AC is ....... cm.
Because BD is bisector, we have: \(\frac{DC}{AD}=\frac{BC}{AB}=\frac{7}{5}\)
On the other hand, CD - AD = 1.
Hence we have \(\hept{\begin{cases}CD=3,5\\AD=2,5\end{cases}}\)
Thus the length of AC equal : 3,5 + 2,5 = 6 (cm).
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The right triangle FGH has mid-segments of length 10 cm, 24cm and 26cm. What is the area of triangle FGH
What is the area of a parallelogram, if the base is 156 cm and the height is 210 cm.
What is the area of a parallelogram, if the base is 19 m and the height is 17 m.
The area of a parallelogram is: 156 x 210= 32760 m2
The area of a parallelogram is: 19 x 17= 323 m2
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In a triangle of area 100cm2 , the ratio between the length of one side and the corresponding height is 1:2.
What is the length of the height, in m?
Answer: The height is...m.
(write your answer by decimal in simplest form)
Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
I don't know English very much so i can't answere your question. Sory about that :(
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Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Mới học lớp 7 thôi, ko làm được bài nhưng để mk dịch đề thử nhá:
Cho tam giác ABC (A^= 90o), BD là tia phân giác của góc B (D thuộc AC). Nếu AD= 6cm, AB= 12cm thì diện tích của tam giác ABC là .....cm2.
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Dựng DE vuông góc với BC (E thuộc BC).2 tam giác vuông ABD và EBD bằng nhau (gcg) nên \(S_{ABD}=S_{EBD}=\frac{1}{2}\cdot12\cdot6=36\)(cm2)Và cạnh DE=AD=6(cm)2 tam giác vuông CED và CAB có chung góc C thì đồng dạng với nhau với tỷ lệ cạnh là: \(\frac{DE}{AB}=\frac{6}{12}=\frac{1}{2}\)nên tỷ lệ diện tích bằng bình phương tỷ lệ cạnh, ta có:\(\frac{S_{CED}}{S_{CAB}}=\frac{1}{2^2}=\frac{1}{4}\)Vậy \(S_{ABC}=S_{ABD}+S_{BDE}+S_{CED}=\left(2+\frac{1}{4}\right)S_{ABD}=\frac{9}{4}S_{ABD}=\frac{9}{4}\cdot36=81\)(cm2).
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Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.