\(B=\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)

   \(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

   \(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)

   \(=\frac{2^{29}.3^{18}.1}{2^{28}.3^{18}.1}\)

   \(=2\)

\(\frac{5.4^{15}.9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)

= 1

đúng không ?

đề bài \(\frac{5\cdot4^{15}\cdot\left(-9\right)^9-4\cdot3^{20}\cdot8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)

Giải:

\(\frac{5\cdot4^{15}\cdot\left(-9\right)^9-4\cdot3^{20}\cdot8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)=\(\frac{5.\left(2^2\right)^{15}.\left(-3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}=\frac{-5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

=\(\frac{-5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)

=\(\frac{-2^{29}.3^{18}.\left(5.2+3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)

=\(\frac{-2^{29}.3^{18}.19}{2^{28}.3^{18}.1}\)

=\(=-2.19=-38\)

do hung sai de bai roi

Phân tích ra bình thường pạn ạ

5.4^15.9^9-4.3^20.8^9

5.2^9.6^19-7.2^29.27^6

       = 5.2^30.3^18-2^2.3^20.2^27

          5.2^9.2^19.3^19-7.2^29.3^18

       = 2^29.3^18(5.2-3^2)

          2^28.3^18(5.3-7.2)

       = 2^29.3^18

          2^28.3^18

       =2

Cái 4^15=2^30 là 4^15=(2^2)^15= 4^15

Những cái sau Tương tự pạn nhé

\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)\(=\frac{2^{29}.3^{18}\left(5.2-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}=\frac{2.1}{1}=2\)

học tốt ~~~

\(\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^9\cdot6^{19}-7\cdot2^{29}\cdot27^6}\\ =2\)

B= {[ 5 * (2^2)^15 * (3^2)^9 ] - [ (2^2) * 3^20 * (2^3)^9 ]} / {[ 5 * (2^9) * (2^19)*(3^19) ] - [ 7 * (2^29) * (3^3)^6 ]} 
B= {[ 5 * (2^30) * (3^18) ] - [ (3^20) * (2^29) ]} / {[ 5 * (2^28) * (3^19) ] - [ 7 * (2^29) * (3^18) ]} 
B= {[ (2^29) * (3^18) ] * [(5 * 2) - 3^2 ]} / {[ (2^28) * (3^18) ] - [(5 * 3) - (7 * 2)] } 
B= [ (2^29) * (3^18) ] / [ (2^28) * (3^18) ] 
B= [ (2^1) * (2^28) * (3^18) ] / [ (2^28) * (3^18) ] 
B = 2

ta có \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)=\(\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)=\(\frac{2^{29}.3^{18}\left(2.5-3^2\right)}{2^{28}.3^{18}\left(5.3-7.2\right)}\)=2