\(ab+ac=a\left(b+c\right)\)

\(ab-ac+a=a\left(b-c+1\right)\)

\(ax-bx-cx+dx=x\left(a-b-c-d\right)\)

\(a\left(b+c\right)-d\left(b+c\right)=0\Leftrightarrow\left(b+c\right)\left(a-d\right)\)

\(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+b\right)\left(c-d\right)\)

\(ax+by+bx+ay=\left(ax+ay\right)+\left(bx+by\right)=a\left(x+y\right)+b\left(x+y\right)=\left(a+b\right)\left(x+y\right)\)

ab + ac = a( b + c )

ab - ac + a = a( b - c +1 )

ax - bx - cx + dx = x( a - b - c - d )

a( b + c ) - d( b + c ) = 0 <=> ( b + c ) ( a - d )

ac - ad + bc - bd = a( c - d ) + b( c - d ) = ( a + b ) ( c - d )

ax + by + bx + ay = ( ax + ay ) + ( bx + by ) = a( x + y ) + b( x + y ) = ( a + b ) ( x + y )

1, ab + ac = a . ( b + c )

2, ab - ac + a = a . ( b - c + 1)

3, ax - bx - cx + dx = x . ( a - b - c + d )

4, a . ( b + c ) - d . ( b + c) = ( a - d ) . ( b + c )

5, ac - ad + bc - bd = a . ( c - d ) + b . ( c - d ) = ( a + b ) . ( c - d )

6, C1: ax + by + bx + ay = ( ax + ay ) + ( bx + by ) = a . ( x + y ) + b . ( x + y ) = ( a + b ) . ( x + y)

    C2: ax + by + bx + ay = ( ax + bx ) + ( ay + by ) = x . ( a + b ) + y . ( a + b ) = ( x + y ) . (a + b )

a) ax(b+c)

b) ax(b-c+d)

c) X x(a-b-c+d)

e, f tương tự

k mình nha bạn

a) ab+ac=a(b+c)

b) ab-ac+ad=a(b-c+d)

c) ax-bx-cx+dx = x(a-b-c+d)

d) a(b+c)-d(b+c)= (b+c)(a-d)

e) ac-ad+bc-bd = a(c-d)+b(c-d)= (c-d)(a+b)

g) ax+by+bx+ay= x(a+b)+y(a+b)=(x+y)(a+b)

a,a.(b+c)

b,a.(b-c+d)

c,x.(a-b-c+d)

d,(a-d).(b+c)

...............

nhớ cho mk nha, mk làm đây, đừng cho ai khác nha, mk sẽ làm ngay bây giờ nhưng khi mk làm xong thì cho mk là đc

a, \(ab+ac\)

\(=a\left(b+c\right)\)

b, \(ab-ac+ad\)

\(=a\left(b-c+d\right)\)

c, \(ax-bx-cx+dx\)

\(=x\left(a-b-c+d\right)\)

d, \(a\left(b+c\right)-d\left(b+c\right)\)

\(=\left(b+c\right)\left(a-d\right)\)

\(a)ab+ac=a\left(b+c\right)\)

\(b)ab-ac+ad=a\left(b-c+d\right)\)

\(c)ax-bx-cx+dx=x\left(a-b-c+d\right)\)

\(d)a\left(b+c\right)-d\left(b+c\right)=\left(b+c\right)\left(a-d\right)\)

\(e)ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+b\right)\left(c-d\right)\)

\(g)ax+by+bx+ay=\left(ax+bx\right)+\left(ay+by\right)=x\left(a+b\right)+y\left(a+b\right)=\left(x+y\right)\left(a+b\right)\)

ab + ac = a(b + c)

ab - ac + ad = a(b - c + d)

ax - bx - cx + dx

=x(a - b - c + d)

chuẩn men

ab+ac=a(b+c)

ab-ac+ad=a(b-c+d)

ax-bx-cx+dx=x(a-b-c+d)

a,ab+ac=a(b+c)

b,ab-ac+ad=a(b-c+d)

c,ax-bx-cx+dx=(a-b-c+d)x

d,a(b+c)-d(b+c)

=ab+ac-bd+cd

=b(a-d)+(a+d)c

e,ac-ad+bc-bd

=c(a+b)-(a-b)d

f,ax+by+bx+ay

=a(x+y)+b(y+x)

a) \(ab+ac=a\left(b+c\right)\)

b) \(ab-ac+ad=a\left(b-c+d\right)\)

c) \(ax-bx-cx+dx=x\left(a-b-c+d\right)\)

d) \(a\left(b+c\right)-d\left(b+c\right)=\left(b+c\right)\left(a-d\right)\)

e) \(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(c-d\right)\left(a+b\right)\)

f) \(ax+by+bx+ay=ax+bx+by+ay=x\left(a+b\right)+y\left(a+b\right)=\left(a+b\right)\left(x+y\right)\)

a) \(ab+ac=a.\left(b+c\right)\)

b) \(ab-ac+ad=a.\left(b-c+d\right)\)

c) \(ax-bx-cx-dx=x.\left(a-b-c-d\right)\)

d) \(a.\left(b+c\right)-d.\left(b+c\right)=ab+ac-db-dc=b.\left(a-d\right)+c.\left(a-d\right)=\left(a-d\right).\left(b+c\right)\)

e) \(ac-ad+bc-bd=a.\left(c-d\right)+b.\left(c-d\right)=\left(c-d\right).\left(a+b\right)\)

f) \(ax+by+bx+ay=a.\left(x+y\right)+b.\left(y+x\right)=\left(x+y\right).\left(a+b\right)\)

CHÚC BN HỌC TỐT!!!!!

a) \(ab+acbx=ab\left(1+cx\right)\)

b) \(ab-ac+ad=a\left(b-c+d\right)\)

c) \(ax-bx-cx+dx=x\left(a-b-x+d\right)\)

d) \(a\left(b+c\right)-d\left(b+c\right)=\left(b+c\right)\left(a-d\right)\)

e) \(ac-ad+bc-bd=a\left(c-d\right)+b\left(c-d\right)=\left(a+b\right)\left(c-d\right)\)

f) \(ax+by+bx+ay=\left(ax+bx\right)+\left(by+ay\right)\)

\(=x\left(a+b\right)+y\left(a+b\right)=\left(a+b\right)\left(x+y\right)\)

,bố thằng nào làm đc

 bạn đừng vào bình luận linh tinh

kh trả lời thì thôi