x=176

X x 2 x 3 = 1056

X x 2       = 1056 : 3

X x 2       = 352

X             = 352 : 2

X             = 176

Ta có :

X x 2 x 3 = 1056

X x 6 = 1056

X = 1056 : 6 

X = 176

Hok tốt !

x*2*3 = 1056

x*(2*3) = 1056

x*6 = 1056

x = 1056 : 6

x = 176

X x 2 x 3 = 1056

             x = 1056 : 3 : 2 

             x = 176

X x 2 x 3 = 1056

X x 6      = 1056

X           = 1056 : 6

X           = 176

Vậy X x 2 x 3 = 1056 thì khi đó X = 176

:D

x*2*3=1056

x*(2*3) = 1056

x*6 = 1056

x = 1056 : 6

x = 176

vậy x = 176

x*2*3=1056

x*6=1056

x=1056/6

x=176

x*2*3=1056

x*6=1056

x=1056:6

x=176

vậy x=176

x là 176

nha bn

\(x.2.3=1056\)

\(x.2=1056:3\)

\(x.2=352\)

\(x=352:2\)

\(x=176\)

X x 2 x 3 = 1056

X x 6      = 1056

x            = 176

\(X\times2\times3=1056\)

          \(X\times6=1056\)

                    \(X=1056\div6\)

                    \(X=176\)

x x2 =1056:3

x x2 = 352

x =352:2

x=176

\(X\times2\times3=1056\)

\(X\times6=1056\)

\(X=1056\div6\)

\(X=176\)

Xx2 x3 = 1056 

Xx2 = 1056 : 3 

Xx2 = 352

X= 352 : 2

X=176

2^x+5+2^x=1056

=>2^x.2⁵+2^x=1056

=>2^x.32+2^x=1056

=>2^x.(32+1)=1056

=>2^x.33=1056

=>2^x=1056:33

=>2^x=32

=>2^x=2⁵

=>x=5

cho a/2 = 1/1 x2x3 + 2/3x4x5+3/5x6x7 + ...+100/199x200x201 tính 201 x a

mình lộn bài

a, x= -9/2

b, x= 2

kb nha

a) \(\left|x+5\right|-x+23=27\)

\(\Leftrightarrow\left|x+5\right|-x+23-27=0\)

\(\Leftrightarrow\left|x+5\right|-x+\left(23-27\right)=0\)

\(\Leftrightarrow\left|x+5\right|-x+\left(-4\right)=0\)

\(\Leftrightarrow\left|x+5\right|-x-4=0\)

\(\Leftrightarrow\left|x+5\right|-\left(x+4\right)=0\)

\(\Leftrightarrow\left|x+5\right|=x+4\)

Xét trường hợp 1:

\(x+5=x+4\)

\(\Leftrightarrow x+5-\left(x+4\right)=0\)

\(\Leftrightarrow x+5-x-4=0\)

\(\Leftrightarrow1=0\left(loai\right)\)

Xét trường hợp 2:

\(x+5=-\left(x+4\right)\)

\(\Leftrightarrow x+5-\left[-\left(x+4\right)\right]=0\)

\(\Leftrightarrow x+5+x+4=0\)

\(\Leftrightarrow2x+9=0\)

\(\Leftrightarrow2x=-9\)

\(\Leftrightarrow x=\dfrac{-9}{2}\left(thoa\right)\)

Vậy \(x=\dfrac{-9}{2}\)