\(0,5\sqrt{100}-\sqrt[]{\frac{4}{25}}va\left(\sqrt{\frac{10}{9}}-\sqrt{\frac{9}{16}}\right):5\)
so sanh
so sánh các số sau: a,\(0,5\sqrt{100}-\sqrt{\frac{4}{25}}và\left(\sqrt{1\frac{1}{9}-\sqrt{\frac{9}{16}}}\right):5\)
\(0,5\sqrt{100}-\sqrt{\frac{4}{25}}=0,5.10-\frac{\sqrt{4}}{\sqrt{25}}=5-\frac{2}{5}=\frac{23}{5}=\frac{138}{30}\)
\(\left(\sqrt{1\frac{1}{9}-\sqrt{\frac{9}{16}}}\right):5=\left(\sqrt{\frac{10}{9}-\frac{3}{4}}\right):5=\sqrt{\frac{13}{36}}:5=\frac{\sqrt{13}}{6}:5=\frac{\sqrt{13}}{30}\)
Vì 13 < 138 nên \(\sqrt{13}< 138\Rightarrow\frac{\sqrt{13}}{30}< \frac{138}{30}\)
Vậy \(0,5\sqrt{100}-\sqrt{\frac{4}{25}}>\left(\sqrt{1\frac{1}{9}-\sqrt{\frac{9}{16}}}\right):5\).
So sánh các số sau:
a) \(0,5\sqrt{100}-\sqrt{\frac{4}{25}}v\text{à}\left(\sqrt{1\frac{1}{9}}-\sqrt{\frac{9}{16}}\right):5\)
b) \(\sqrt{25+9}v\text{à}\sqrt{25}+\sqrt{9}\)
Giúp mik với
Tính
a)\(\frac{2}{3}\sqrt{81}-\left(\frac{-3}{4}\right).\sqrt{\frac{9}{64}}+\left(\frac{\sqrt{2}}{3}\right)^2\)
b)\(\left(-\sqrt{\frac{5}{4}}\right)^2-\sqrt{\frac{9}{4}}:\left(-4,5\right)-\sqrt{\frac{25}{16}}.\sqrt{\frac{64}{9}}\)
c)\(-2^4-\left(-2\right)^2:\left(-\sqrt{\frac{16}{121}}\right)-\left(-\sqrt{\frac{2}{3}}\right)^2:\left(-2\frac{2}{3}\right)\)
a)
\(\frac{3}{7}+\left(-\frac{5}{2}\right)+\left(-\frac{3}{5}\right)\)
b)
\(\frac{4}{5}-\left(-\frac{2}{7}\right)-\frac{7}{10}\)
c)
\(3,5-\left(-\frac{2}{7}\right)\)
d)
\(\sqrt{\left(-7\right)^2}+\sqrt{\frac{25}{16}}-\frac{3}{2}\)
e)
\(\sqrt{0,36}.\sqrt{\frac{25}{16}}+\frac{1}{4}\)
f)
\(\frac{1}{2}.\sqrt{100}-\sqrt{\frac{1}{16}}+\left(\frac{1}{3}\right)^0\)
g)
\(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}}-1\frac{2}{5}\)
i)
\(\frac{21^9.2^{10}}{14^9.3^8}\)
k)
\(\frac{10^{11}.21^{12}}{15^{10}.14^{11}}\)
l)
\(0,5.\sqrt{100}-\sqrt{\frac{1}{4}}\)
a, \(-\frac{187}{70}\)
b,\(\frac{27}{70}\)
c,\(\frac{53}{14}\)
d,\(\frac{27}{4}\)
e,1
f,\(\frac{23}{4}\)
g,-1
i,6
k,315
l,\(\frac{9}{2}\)
Rút Gọn
a,\(\sqrt{75}-\sqrt{5\frac{1}{3}}+\frac{9}{2}\sqrt{2\frac{2}{3}}+2\sqrt{27}\)
b,\(\sqrt{48}+\sqrt{5\frac{1}{3}}+2\sqrt{75}-5\sqrt{1\frac{1}{3}}\)
c,\(\left(\sqrt{12}+2\sqrt{27}\right)\frac{\sqrt{3}}{2}-\sqrt{150}\)
d,\(\left(\sqrt{18}+\sqrt{0,5}-3\sqrt{\frac{1}{3}}\right)-\left(\sqrt{\frac{1}{8}-\sqrt{75}}\right)\)
e,\(6\sqrt{\frac{8}{9}}-5\sqrt{\frac{32}{25}}+14\sqrt{\frac{18}{49}}\)
f,\(2\sqrt{\frac{16}{3}}-3\sqrt{\frac{1}{27}}-6\sqrt{\frac{4}{75}}\)
g,\(\left(2\sqrt{\frac{16}{3}}-3\sqrt{\frac{1}{27}}-6\sqrt{\frac{4}{75}}\right)\sqrt{3}\)
h,\(\left(6\sqrt{\frac{8}{9}}-5\sqrt{\frac{32}{25}}+14\sqrt{\frac{18}{49}}\right)\sqrt{\frac{1}{2}}\)
i,\(\frac{1}{2}\sqrt{48}-2\sqrt{75}-\frac{\sqrt{33}}{\sqrt{11}}+5\sqrt{1\frac{1}{3}}\)
j,\(\left(\sqrt{\frac{1}{7}}-\sqrt{\frac{16}{7}}+7\right):\sqrt{7}\)
Tính giá trị của biểu thức sau:
a, \(\sqrt{0,09}+2.\sqrt{0,25}\)
b, \(0,5.\sqrt{100}-\sqrt{\frac{4}{25}}\)
c, \(\left(\sqrt{1\frac{9}{16}}-\sqrt{\frac{9}{16}}\right):5\)
d, 3. \(\sqrt{1\frac{17}{64}}-2.\sqrt{0,0625}\)
a)\(\sqrt{0,09}\)+2.\(\sqrt{0,25}\)=0,3+2.0,5
=0,3+1
=1,3
b)0,5.\(\sqrt{100}\)-\(\sqrt{\frac{4}{25}}\)=0,5.10-0,4
=5-0,4
=4,6
c)(\(\sqrt{1\frac{9}{16}}\) -\(\sqrt{\frac{9}{16}}\)):5=(1,25-0,75):5
=0,5:5
=0,1
d)3.\(\sqrt{1\frac{17}{64}}\) -2.\(\sqrt{0,0625}\)=1,125-2.0,25
=1,125-0,5
=0,625
So sánh \(0,5\sqrt{100}-\sqrt{\frac{4}{25}}\) và \((\sqrt{\frac{11}{9}-\sqrt{\frac{9}{16}}})\div5\)
Tính
a) \(2\sqrt{\frac{25}{16}}-3\sqrt{\frac{49}{36}}+4\sqrt{\frac{81}{64}}\)
b) \(\left(3\sqrt{2}\right)^2-\left(4\sqrt{\frac{1}{2}}\right)^2+\frac{1}{16}.\left(\sqrt{\frac{3}{4}}\right)^2\)
c) \(\frac{2}{3}\sqrt{\frac{81}{16}}-\frac{3}{4}\sqrt{\frac{64}{9}}+\frac{7}{5}.\sqrt{\frac{25}{196}}\)
a) = \(\frac{7}{2}\)
b) = \(\frac{643}{64}\)
c) = 0
Tính:
a.\(\left(\frac{2}{25}-1,008\right)\):\(\sqrt{\frac{16}{7}}\):\(\left[\left(3\frac{1}{4}-6\frac{5}{9}\right).2\frac{2}{17}\right]\)
b.\(\left(\sqrt{1\frac{9}{16}-\sqrt{\frac{9}{16}}}\right):5\)
\(b,\left(\sqrt{1\frac{9}{16}-\sqrt{\frac{9}{16}}}\right):5\)
\(=\left(\sqrt{\frac{25}{16}-\frac{3}{4}}\right):5\)
\(=\sqrt{\frac{13}{16}}:5\)
\(=\frac{\sqrt{13}}{4}:5\)
\(=\frac{\sqrt{13}}{20}\)