\(\left(\frac{1111111111}{2222222222}+\frac{9999999999}{2222222222}+\frac{5555555555}{2222222222}+\frac{5555555555}{2222222222}\right)\) \(+\) \(90\)

\(=\) \(10+90\)

\(=\) \(100\)

1111111111111111111/22222222222222222222222222222+ggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggggg

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ta co:A=9+9+999+..........+9999999999

A=10-1+100-1+1000-1+...........+10000000000-1(10 so 0)

A=(10+100+1000+...+10000000000)-(1+...+1)

A=(1+10+100+1000+........+10000000000)-(1+1+........+1)

A=11111111111-11

A=11111111100

= 5555555555

5555555555

5555555555

\(A=\frac{\text{9999999999}}{2}-\frac{\text{9999999999}}{3}-\frac{\text{9999999999}}{6}\)

\(A=\text{9999999999}\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(A=\text{9999999999}.0\)

\(A=0\)

Vậy A = B 

A = 0 nhé bạn tôi thề là đúng luôn

bạn ko cần cảm ơn đâu cho 1 k là ok

\(\frac{9999999999}{2}+\frac{9999999999}{3}+\frac{9999999999}{6}\)

\(=9999999999\cdot\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{6}\right)\)

\(=9999999999\cdot1\)

\(=9999999999\)

1111111111+1111111111=2222222222

=2222222222

= 2222222222

nha bạn

1111111111+1111111111=2222222222

=2222222222

2222222222

1111111111 + 1111111111 = 2222222222

bang 22222222

2222222222

Nhân xét biểu thức A, ta thấy:

   \(\frac{9999999999}{2}>\frac{9999999999}{3}>\frac{9999999999}{6}>0\)

=> \(A>0\left(đpcm\right)\)

ta có 9999999999/2=9999999999*3/2*3

9999999999/3=9999999999*2/3*2

suy ra 9999999999*3/2*3 - 9999999999*2/3*2=9999999999*3-9999999999*2/6=9999999999/6

suy ra A=9999999999/6-9999999999/6=0

vậy A=0

\(A=9999999999.\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)

\(A=9999999999.0=0\)

Vậy A=0