\(\text{Đ}\text{ặt}\text{ }A=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)

\(\Rightarrow3A=3+1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}\)

\(\Rightarrow3A-A=3-\frac{1}{81}\)

\(\Rightarrow2A=\frac{242}{81}\)

\(\Rightarrow A=\frac{242}{81}:2=\frac{121}{81}\)

4/9 > 3/10

k cho mk nha

4/9=0,4444444444444444444444.

3/10=0,3

4/9>3/10.   

4/9  >  3/10

Chúc bạn học tốt !

Ta có :

\(\frac{12}{13}=1-\frac{1}{13}\)

\(\frac{13}{14}=1-\frac{1}{14}\)

Vì \(\frac{1}{13}>\frac{1}{14}\)nên \(1-\frac{1}{13}< 1-\frac{1}{14}\)

Vậy \(\frac{12}{13}< \frac{13}{14}\)

Ta thấy:

\(\frac{12}{13}=1-\frac{1}{13}\)

\(\frac{13}{14}=1-\frac{1}{14}\)

Vì 13<14.

=>\(\frac{1}{13}>\frac{1}{14}\)

=>\(1-\frac{1}{13}< 1-\frac{1}{14}\)

=>\(\frac{12}{13}< \frac{13}{14}\)

Vậy......

\(\frac{12}{13}\)và \(\frac{13}{14}\)

Ta có : \(\frac{12}{13}=\frac{12}{13}+\frac{1}{13}\)  ;   \(\frac{13}{14}=\frac{13}{14}+\frac{1}{14}\)

Ta thấy \(\frac{1}{13}>\frac{1}{14}\)=> \(\frac{12}{13}< \frac{13}{14}\)

1-8/9=1/9   1-9/10=1/10   1/9 >1/10 nen 8/9<9/10   

Vì    \(\frac{12}{49}< \frac{13}{49}\)

        \(\frac{13}{49}< \frac{13}{47}\)

Nên \(\frac{12}{49}< \frac{13}{47}\)

Ta có 13/47>13/49

Mà 13/49>12/49

=> 12/49<13/47

\(\frac{12}{49}\)và \(\frac{13}{47}\Rightarrow12.47\)và \(49.13\)\(\Rightarrow564\)và \(637\)

vì 564<637

nên \(\frac{12}{49}< \frac{13}{47}\)

a)MSC nhỏ nhất:18 

b)24

mẫu số nhỏ nhất là 18

24

a) MSC: 18

b)MSC: 24

75/77< 457/459< 2003/2005

A=\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}\)

A=\(\left(1-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{8}\right)+...+\left(\frac{1}{128}-\frac{1}{256}\right)\)

A=\(1-\frac{1}{256}\)

A=\(\frac{255}{256}\)

A = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256

2A = 1/2 x 2 + 1/4 x 2 + 1/8 x 2 + 1/16 x 2 +1/32 x 2 + 1/64 x 1/128 + 1/256 x 2

2A = 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128

2A - A = ( 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 ) - ( 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 )

A = 1 - 1/256

A = 255/256

A=$\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}$

A=$\left(1-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{4}\right)+\left(\frac{1}{4}-\frac{1}{8}\right)+...+\left(\frac{1}{128}-\frac{1}{256}\right)$

A=$1-\frac{1}{256}$

A=$\frac{255}{256}$