x^2-9xy+20y^2
4x^2(x-y)-x-y
16+ty^2+6xt-9t+x^2
nhom hang tu nhe,giai that chi tiet
1)2x^2-4xy+2y^2-32
2)5x^2-5y^2-x+y
3)x^2-9xy+20y^2
4)4x^2(x+y)-x-y
5)16+ty^2+6xt-9t+x^2
Giai bang phuong phap phan tich thanh nhan tu chung bang cach nhom hang tu.
Mai mình nộp bài,mong giaup đó
1. =2(x2-2xy+y2-16)
=2((x-y)2-42)
=2(x-y-4)(x-y+4)
2. =5(x2-2.1/10.x+1/100-y2+2.1/10y-1/100)
=5.((X-1/10)2-(Y-1/10)2)
=5(X-1/10-Y+1/10)(X-1/10+Y-1/10)
=5(X-Y)(X+Y-2/10)
3. =(X2-9XY+81/4Y2)-1/4Y2
=(X-9/2Y)^2-1/4Y^2
=(X-9/2Y-1/2Y)(X-9/2Y+1/2Y)
(X-5Y)(X-4Y)
5x^2-5y^2-x+y
nhom hang tu nhe,giai that chi tiet
Phân tích đt thành nhân tử
\(x^2-9xy+20y^2\)
\(4x^2\left(x+y\right)-x-y\)
\(16ty^2+6xt-9t-tx^2\)
\(4x^2\left(x+y\right)-x-y\)
\(=4x^2\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(4x^2-1\right)\)
\(=\left(x+y\right)\left(2x-1\right)\left(2x+1\right)\)
\(16ty^2+6xt-9t-tx^2\)
\(=t.\left(16y^2+6x-9-x^2\right)\)
\(=t.\left[\left(4y\right)^2-\left(x^2-2.x.3+3^2\right)\right]\)
\(=t.\left[\left(4y\right)^2-\left(x-3\right)^2\right]\)
\(=t.\left(4y-x+3\right)\left(4y+x-3\right)\)
\(x^2-9xy+20y^2\)
\(=\left(x^2-4xy\right)-\left(5xy-20y^2\right)\)
\(=x.\left(x-4y\right)-5y\left(x-4y\right)\)
\(=\left(x-4y\right)\left(x-5y\right)\)
(x+y).(x-y)=5
giai chi tiet ra nhe!
x × 2 + x × 3 = 4
Giai chi tiet ho minh nhe
chung minh dt
a)(x+y)2-y2=x.(x+2y)
b)(a+b)-(a-b).3=2y.(a2+3b2)
GIAI CHI TIET GIUP MINH NHE !
tìm x
|x|=5
|x-3|=2
x+|x|=2
20-7.|x-1|=6
[GIAI CHI TIET GIUP TO NHE]
a)|x|=5
=>x=5 hoặc x=-5
b)|x-3|=2
=>x-3=2 hoặc x-3=-2
x=2+3 x=-2+3
x=5 x=1
c)x+|x|=2
|x|=2-x
=>x=2-x hoặc x=-(2-x)=-2+x
x+x=2 x-x=-2
2x=2 0=(-2)(loại)
x=2/2
x=1
d)20-7|x-1|=6
7|x-1|=20-6
|x-1|=14/7
|x-1|=2
=>x-1=2 hoặc x-1=-2
x=2+1 x=-2+1
x=3 x=-1
Nêu tác dụng của miêu tả. M.n giúp mình nha. Mình vầng bây giờ
a)3/4 + 1/4.x + x - 7/6. x = 5/12
b)0,25.x - 2/3.x = -1 1/6
giai chi tiet nhe
\(\frac{3}{4}+\frac{1}{4}\cdot x+x-\frac{7}{6}\cdot x=\frac{5}{12}\)
\(\frac{3}{4}+\frac{1}{4}\cdot x-\frac{7}{6}\cdot x+x\cdot1=\frac{5}{12}\)
\(\frac{3}{4}+x\left(\frac{1}{4}-\frac{7}{6}+1\right)=\frac{5}{12}\)
\(\frac{3}{4}+x\cdot\frac{1}{12}=\frac{5}{12}\)
\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{3}{4}\)
\(x\cdot\frac{1}{12}=\frac{5}{12}-\frac{9}{12}\)
\(x\cdot\frac{1}{12}=\frac{-1}{3}\)
\(x=\frac{-1}{3}\text{ : }\frac{1}{12}\)
\(x=\frac{-1}{3}\cdot12\)
\(x=\frac{-12}{3}\)
\(x=-4\)
\(\text{b, }0,25\cdot x-\frac{2}{3}\cdot x=-1\frac{1}{6}\)
\(\frac{1}{4}\cdot x-\frac{2}{3}\cdot x=\frac{-7}{6}\)
\(x\cdot\left(\frac{1}{4}-\frac{2}{3}\right)=\frac{-7}{6}\)
\(x\cdot\frac{-5}{12}=\frac{-7}{6}\)
\(x=\frac{-7}{6}\text{ : }\frac{-5}{12}\)
\(x=\frac{-7}{6}\cdot\frac{12}{-5}\)
\(x=\frac{-14}{-5}\)
giup mk gap 5 tick nha giai chi tiet nhe tinh gia tri cua da thuc P(x)= x^2018 + x^2017 + x^2016 + .... + x^2 + x + 1 tai x=1