Tính:
\(\frac{790^{^4}}{79^{^4}}\)
\(\frac{8^{^{14}}}{4^{^{12}}}\)
\(\frac{2^{^{15}}\cdot9^{^4}}{6^{^6}\cdot8^{^3}}\)
\(\frac{45^{^{10}}\cdot5^{^{10}}}{75^{^{10}}}\)
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Bài 2 : a) frac{15^{30}}{45^{15}}?b) frac{45^{10}cdot5^{10}}{75^{10}} ?c) frac{left(0,8^5right)}{left(0,4^6right)}?d)frac{2^{15}cdot9^4}{6^6cdot8^3}?e) frac{8^{10}+4^{10}}{8^4+4^{11}}?g)frac{1^7}{7}. 77?h) frac{90^3}{153}?i) 26 . 56 ?
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Bài 2 :
a) \(\frac{15^{30}}{45^{15}}\)=?
b) \(\frac{45^{10}\cdot5^{10}}{75^{10}}\)= ?
c) \(\frac{\left(0,8^5\right)}{\left(0,4^6\right)}\)=?
d)\(\frac{2^{15}\cdot9^4}{6^6\cdot8^3}\)=?
e) \(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)=?
g)\(\frac{1^7}{7}\). 77=?
h) \(\frac{90^3}{153}\)=?
i) 26 . 56 =?
Tính \(A=\left(\frac{1}{4\cdot9}+\frac{1}{9\cdot14}+\frac{1}{14\cdot19}+...+\frac{1}{44\cdot49}\right)\cdot\frac{1-3-5-7-...-49}{89}\)
\(B=\frac{5\cdot4^{15}\cdot9^9-4\cdot3^{20}\cdot8^9}{5\cdot2^{10}\cdot6^{19}-7\cdot2^{29}\cdot27^6}-\frac{2^{19}\cdot27^3+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\)
bài này không khó. Nhưng đánh máy để giải cho bạn thì thực sự khó
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\(\frac{1}{10\cdot9}-\frac{1}{9\cdot8}-\frac{1}{8\cdot7}-\frac{1}{7\cdot6}-\frac{1}{6\cdot5}-\frac{1}{5\cdot4}-\frac{1}{4\cdot3}-\frac{1}{3\cdot2}-\frac{1}{2\cdot1}\)
Ta có : \(\frac{1}{10.9}-\frac{1}{9.8}-.....-\frac{1}{2.1}\)
\(=\frac{1}{90}-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+.....+\frac{1}{9.8}\right)\)
\(=\frac{1}{90}-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+.....+\frac{1}{8}-\frac{1}{9}\right)\)
\(=\frac{1}{90}-\left(1-\frac{1}{9}\right)\)
\(=\frac{1}{90}-\frac{8}{9}=\frac{-79}{90}\)
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a) \(\frac{0,8^5}{0,4^6}\) b)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\) c)\(\frac{2^{15}\cdot9^4}{6^3\cdot8^3}\)
a, Ta có: \(\frac{0,8^5}{0,4^6}=\frac{\left(0,4.2\right)^5}{0,4^6}=\frac{0,4^5.2^5}{0,4^6}\) \(=\frac{2^5}{0,4}=80\)
b, Ta có: \(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\) \(=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{12}\left(2^{18}+2^8\right)}{2^{12}\left(1+2^{10}\right)}\)
\(=\frac{2^{18}+2^8}{1+2^{10}}=\frac{2^8\left(2^{10}+1\right)}{2^{10}+1}=2^8\)
c, Ta có: \(\frac{2^{15}.9^4}{6^3.8^3}=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^3.\left(2^3\right)^3}=\frac{2^{15}.3^8}{2^3.3^3.2^9}\) \(=\frac{2^{15}.3^8}{2^{12}.3^3}=2^3.3^5=1944\)
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b)\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)=\(\frac{\left(2.4\right)^{10}+4^{10}}{\left(2.4\right)^{10}+4^{11}}\)=\(\frac{2^{10}.4^{10}+4^{10}.1}{2^{10}.4^{10}+4^{10}.4}\)=\(\frac{4^{10}\left(2^{10}+1\right)}{4^{10}\left(2^{10}+4\right)}\)=\(\frac{4^{10}.1025}{4^{10}.1028}\)=\(\frac{1025}{1028}\)
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\(\frac{7}{3\cdot4}-\frac{9}{4\cdot5}+\frac{11}{5\cdot6}-\frac{13}{6\cdot7}+\frac{15}{7\cdot8}-\frac{17}{8\cdot9}+\frac{19}{9\cdot10}\)
ta có:(3+4)/4=3/(3*4)+4/(3*4) =1/4+1/3 chứng minh tương tự,cộng vế với vế, ta được kết quả là 13/30
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Xem thêm câu trả lời
Rút gọn:
a) \(\frac{2^{19}\cdot27+15\cdot4^9\cdot9^4}{6^9\cdot2^{10}+12^{10}}\) c)\(\frac{4^6\cdot9^5+6^9\cdot120}{8^4\cdot3^{12}-6^{11}}\)
b)\(\frac{\left(\frac{2}{5}\right)^7\cdot5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(\sqrt[2]{4\cdot9\frac{8}{8}+\frac{48\cdot11+5}{1\cdot\frac{814}{5+\frac{6145}{1\cdot\frac{821}{614}}}}}2548-\frac{8452}{14\cdot\frac{58}{96\cdot\frac{41}{\frac{24}{1\cdot\frac{975545}{1421+\frac{84874}{\frac{1+2+3+4+5+6+7+8+9\cdot2\cdot3\cdot4\cdot5\cdot6\cdot7\cdot8\cdot9}{2\cdot\frac{2}{1}}}}}}}}\)
Help me:Tính:( 2-1 + 3-1 ) : ( 2-1 - 3-1 ) + ( 2-1 : 20 ) :23frac{left(frac{2}{5}right)^7cdot5^7+left(frac{9}{4}right)^3:left(frac{3}{16}right)^3}{2^7cdot5^2+512}frac{4^6cdot9^5+6^9cdot120}{^{8^4cdot3^{12}-6^{11}}}frac{4^5cdot9^4-2cdot6^9}{2^{10}cdot3^8+6^8cdot20}
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Help me:
Tính:
( 2-1 + 3-1 ) : ( 2-1 - 3-1 ) + ( 2-1 : 20 ) :23
\(\frac{\left(\frac{2}{5}\right)^7\cdot5^7+\left(\frac{9}{4}\right)^3:\left(\frac{3}{16}\right)^3}{2^7\cdot5^2+512}\)
\(\frac{4^6\cdot9^5+6^9\cdot120}{^{8^4\cdot3^{12}-6^{11}}}\)
\(\frac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^8\cdot20}\)
\(41\sqrt[9^1]{8\sqrt[2]{\frac{12}{2.85\frac{1\cdot2+3\cdot4+5\cdot6+7\cdot8+9\sqrt[4]{16}}{2\cdot\frac{12}{2}\sqrt{4^2}-7^2}}}4\cdot5\cdot6\cdot7\cdot8\cdot9}\)
Ô phép tính khủng. Cái này do bạn chế ra à !
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