chịu

+ \(3x=y\Rightarrow6x=2y\)

+ \(4z=5y\Rightarrow8z=10y\)

Thay vào biểu thức

\(6x+7y+8z=2y+7y+10y=456\)

\(\Rightarrow19y=456\Rightarrow y=24\)

Từ đó suy ra x và z

=(3x-5)(y+2)=20=1.20=4.5=2.10 Va nguoc lai

hoi nhieu nghiem

3x-5=1=>x=2

y+2=20=> 18

....

tu lam lay cho vui

\(a.2x^3+6x=2x\left(x^2+3\right)\)

\(=2x\left(x^2+3\right)-2x\left(x^2+3\right)\)

\(=\left(x^2+3\right)\left(2x-2x\right)\)

\(b.5x\left(x-2\right)-3x^2\left(x-2\right)\)

\(=\left(x-2\right)\left(5x-3x^2\right)\)

\(c.3x\left(x-5y\right)-2y\left(5y-x\right)\)

\(=3x\left(x-5y\right)+2\left(x-5y\right)\)

\(=\left(x-5y\right)\left(3x+2\right)\)

\(d.y^2\left(x^2+y\right)-x^3-xy\)

\(=y^2\left(x^2+y\right)-x\left(x^2+y\right)\)

\(=\left(x^2+y\right)\left(y^2-x\right)\)

e. Cái bài này ghi lại đàng hoàng xíu nha t k hỉu

\(f.3x^2\left(y^2-2x\right)-15x\left(2x-y^2\right)\)

\(=3x^2\left(y^2-2x\right)+15x\left(y^2-2x\right)\)

\(=\left(y^2-2x\right)\left(3x^2+15x\right)\)

Ta có : 3x=5y=6x \(\Rightarrow\)\(\frac{x}{\frac{1}{3}}\)=\(\frac{y}{\frac{1}{5}}\)=\(\frac{z}{\frac{1}{6}}\)= K

x.y=\(\frac{1}{3}k\) .\(\frac{1}{5}k\)=(\(\frac{1}{3}.\frac{1}{5}\) ). \(k^2\)= \(\frac{1}{15}k^2\)=4860

K²  =4860 : \(\frac{1}{15}\)=72900

K =\(\sqrt{72900}\)=270

X=270.\(\frac{1}{3}\)= 90 

Tương tự y;z bạn tự làm nhé!

\(\hept{\begin{cases}3x=y\\5y=4z\end{cases}\Rightarrow\hept{\begin{cases}\frac{3x}{12}=\frac{y}{12}\\\frac{5y}{60}=\frac{4z}{60}\end{cases}\Rightarrow}\hept{\begin{cases}\frac{x}{4}=\frac{y}{12}\\\frac{y}{12}=\frac{z}{15}\end{cases}\Rightarrow}\frac{x}{4}=\frac{y}{12}=\frac{z}{15}=\frac{6x}{24}=\frac{7y}{84}=\frac{8z}{120}=\frac{6x+7y+8z}{24+84+120}=\frac{456}{228}=2\Rightarrow x=2.4=8}\)