phan tich thanh nhan tu
(x+y)5-x5-y5
Phan tich da thuc thanh nhan tu: (x+y+z)^5 - x^5 - y^5 - z^5
phan tich da thuc thanh nhan tu
x^2-x-y^2-y
x^2-2xy+y^2-z^2
bai 32 va 33 sbt
lop 8 bai phan tich da thuc thanh nhan tu bang cach nhom hang tu
Ta có
a, x2-x-y2-y
=x2-y2-(x+y)
=(x-y)(x+y) - (x+y)
=(x+y)(x-y-1)
b, x2-2xy+y2-z2
=(x-y)2-z2
=(x-y-z)(x-y+z)
con bai 32, 33 neu ban tra loi duoc minh h them
x^4 -y^6: phan tich thanh nhan tu
\(=\left(x^2\right)^2-\left(y^3\right)^2=\left(x^2-y^3\right)\left(x^2+y^3\right)\)
phan tich thanh nhan tu D=(x-y)^3+(y-z)^3+(z-x)^3
http://olm.vn/hoi-dap/question/102127.html
bạn tham khảo tại đây
phan tich da thuc thanh nhan tu
x^5+x+1
x^5+x+1
=x(x^4+1)+1
=(x^2+x+1)(x^3-x^2+1)
Ta có : x5 + x + 1
= x5 + x4 - x4 - x3 + x3 + x2 - x2 - x + x + 1
= (x5 + x4) - (x4 + x3) + (x3 + x2) - (x2 + x) + (x + 1)
= x5(x + 1) - x4.(x + 1) + x3(x + 1) - x2(x + 1) + (x + 1)
= (x + 1)(x5 - x4 + x3 - x2 + 1)
5x^2+3(x+y)^2-5y^2 phan tich thanh nhan tu
Ta có:
\(5x^2+3\left(x+y\right)^2-5y^2\)
\(\Rightarrow5x^2+3.\left(x^2+2xy+y^2\right)-5y^2\)
\(\Rightarrow5x^2+3x^2+6xy+3y^2-5y^2\)
\(\Rightarrow8x^2+6xy-2y^2\)
Ta có :\(5x^2+3\left(x+y\right)^2-5y^2\)
\(\Rightarrow5x^2+3.\left(x^2-2xy-y^2\right)-5y^2\)
\(\Rightarrow5x^2+3x^2+6xy+3y^2-5y^2\)
\(\Rightarrow8x^2+6xy-2y^2\)
TK CHO MK NHA
Chúc Bạn Học Tốt :):):):)
phan tich da thuc thanh nhan tu :xy(x-y)-xz(x+z)+yz(2x+z-y)
phan tich thanh nhan tu: x3+y3+6xy+x+y-10
phan tich da thuc thanh nhan tu (x-y).z^3 +(y-z).x^3 +(z-y).y^3