A=1.3/2.2x2.4/3.3x3.5/4.4x...29.31/30.30

A=(1.2.3....29)x(2.3.4.....31)/(2.3.4....30)x(2.3.4....30)

A=31/30

A=31/30

\(A=\frac{3}{4}.\frac{8}{9}.\frac{15}{16}....\frac{899}{900}\)

\(=\frac{1.3}{2.2}.\frac{2.4}{3.3}.\frac{3.5}{4.4}....\frac{29.31}{30.30}\)

\(=\frac{1.2.3....29}{2.3.4....30}.\frac{3.4.5....31}{2.3.4....30}\)

\(=\frac{1}{100}.\frac{31}{2}=\frac{31}{200}\)

31/60

31/60

31/60 đó bạn.

Ta có:

A = 3/4 . 8/9 . 15/16 . 24/25 . .... 899/900

   = (1.3)/(2.2) . (2.4)/(3.3) . (3.5)/(4.4).....(29.31)/(30.30) 
   = [(1.2.3...29).(3.4.5...31)]/[(2.3.4...30).(2.3.4...30)] 
   = [(1.2.3...29)/(2.3.4...30)] . [(3.4.5...31)/(2.3.4...30)]
   = (1/30) . (31/2)

   = 31/60

Bài này lp 6 mk thi huyện r

36/60

31/60

\(\frac{3}{4}.\frac{8}{9}.\frac{15}{16}...\frac{99}{100}\)

\(=\frac{1.3}{2^2}.\frac{2.4}{3^2}.\frac{3.5}{4^2}....\frac{9.11}{10^2}\)

( đoạn này bạn rút )

\(=\frac{1}{2}.\frac{11}{10}=\frac{22}{20}\)

(mik cx ko chắc, có j sai ib mik sẽ sửa ạ)

ok thx bạn

\(\frac{3}{4}\cdot\frac{8}{9}\cdot\frac{15}{16}\cdot...\cdot\frac{99}{100}\)

\(=\frac{1\cdot3}{2\cdot2}\cdot\frac{2\cdot4}{3\cdot2}+\frac{3\cdot5}{4\cdot2}+...+\frac{9\cdot11}{10\cdot10}\)

\(=\frac{1}{2}\cdot\frac{11}{10}=\frac{11}{20}\)

F=1-2+3-4+5-6+...+99-100+101

F=(1-2)+(3-4)+...+(99-100)+101

F=-1+(-1)+..+(-1)+101

F=-50+101  ( Vì từ 1 -> 100 có 100 số và chia thành 50 cặp )

F=51

101 -1 =100

1-2+3-4+5-6+...+99-100+101(có 101 số hạng)

=(1-2)+(3-4)+(5-6)+...+(99-100)+101

= -1 + (-1) + (-1) + ... + (-1) + 101 (có 100 : 2 = 50 số -1 và số 101)

= -50 + 101

=101-50

=51

kb nha!

P=3/4.8/9.15/16...99/100

P = 3.8.15...99 / 4.9.16...100

P = 1.3.2.4.3.5...9.11 / 2.2.3.3.4.4...10.10

P = (1.2.3.4...9) . (1.2.3.4...9) / (2.3.4...10) . (2.3.4...10)

P = 1.11 / 10.2

P = 11 / 20

max easy

\(\frac{3}{4}\cdot\frac{8}{9}\cdot\frac{15}{16}\cdot...\cdot\frac{99}{100}=\frac{1\cdot3}{2\cdot2}=\frac{2\cdot4}{3\cdot3}=\frac{3\cdot5}{4\cdot4}\cdot...\cdot\frac{9\cdot11}{10\cdot10}=\frac{1}{2}\cdot\frac{11}{10}=\frac{11}{20}\)